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Mathematics 0580/22 February/March 2022: question paper and mark scheme

Cambridge IGCSE Mathematics (0580), Paper 2 (Extended), February/March 2022. Read both free below, or download them. Done the paper? Get it marked by AI against this mark scheme.

0580_m22_qp_220580_m22_ms_220580/22/F/M/22

Paper
Paper 2 (Extended)
Total marks
70
Time
1 hour 30 minutes
Code on the paper
0580/22/F/M/22
0580_m22_ms_22.pdf

0580/22 mark scheme, question by question

Each question as it's printed, and the mark scheme's points for it, as text. Diagrams, tables and graphs are in the PDFs above.

Question 11 mark

Question

Measure the marked angle. …… [1]

Mark scheme

1 40° 1

Question 22 marks

Question

Work out 5 # 6 2 . Give your answer correct to 2 decimal places. …… [2]

Mark scheme

2 80.50 cao 2 B1 for 80.498… or 80.5 or correctly rounding their more accurate decimal to 2 dp

Question 31 mark

Question

A journey starts at 21 15 one day and ends at 04 33 the next day. Calculate the time taken, in hours and minutes. …… h …… min [1]

Mark scheme

3 7 [h] 18 [min] 1

Question 43 marks

Question

NOT TO SCALE 5 cm 4 cm 7 cm Calculate the total surface area of this cuboid. …… cm 2 [3]

Mark scheme

4 166 3 M2 for [2 ×] (7×4 + 4×5 + 5×7) or M1 for 7×4 or 4×5 or 5×7

Question 52 marks

Question

(a) Write down the gradient of the line y = 5x + 7 . …… [1] (b) Find the coordinates of the point where the line y = 5x + 7 crosses the y-axis. ( …… , …… ) [1]

Mark scheme

5(a) 5 1 5(b) (0, 7) 1

Question 62 marks

Question

9.5 cm 8 cm NOT TO SCALE 12 cm Using a ruler and compasses only, construct this triangle. Leave in your construction arcs. The side of length 12 cm has been drawn for you. [2]

Mark scheme

6 correct triangle with arcs 2 B1 for correct triangle with incorrect or no arcs or for two correct arcs. or a triangle with arcs but one side not in range

Question 71 mark

Question

n –2 –1 0 1 Write down the inequality, in terms of n, shown by the number line. …… [1]

Mark scheme

7 n > − 1 oe 1

Question 86 marks

Question

y 6 5 4 3 A 2 1 B –5 –4 –3 –2 –1 0 1 2 3 4 5 6 7 8 9 10 x –1 –2 –3 –4 –5 (a) On the grid, draw the image of (i) triangle A after a reflection in the y-axis, [1] -3 (ii) triangle A after a translation by the vector e o. [2] -4 (b) Describe fully the single transformation that maps triangle A onto triangle B. …… [3]

Mark scheme

8(a)(i) triangle at (− 1, 1) (− 4, 2) (− 3, 5) 1 8(a)(ii) triangle at (− 2, −3) (1, − 2) (0, 1) 2 −3 k B1 for translation by or by k −4 8(b) enlargement 3 B1 for each 1 [sf] 2 [centre] (9, − 1)

Question 92 marks

Question

Factorise completely. 12a 3 - 21a …… [2]

Mark scheme

9 ( ) 3a 4a 2 − 7 final answer ( ) ( 2 B1 for 3 4a 3 − 7 a or a 12a 2 − 21 ) or for 3a ( 4a − 7 ) seen then spoilt 2

Question 104 marks

Question

(a) The nth term of a sequence is n 2 + 7 . Find the first three terms of this sequence. …… , …… , …… [2] (b) These are the first four terms of a different sequence. 15 7 −1 -9 Find the nth term of this sequence. …… [2]

Mark scheme

10(a) 8 11 16 2 B1 for two correct 10(b) 23 – 8n oe final answer 2 B1 for j – 8n or 23 – kn k ≠ 0 or 23 – 8n seen then spoilt

Question 111 mark

Question

As the temperature increases, people eat more ice cream. What type of correlation does this statement describe? …… [1]

Mark scheme

11 Positive 1

Question 126 marks

Question

(a) Sanjay invests $700 in an account paying simple interest at a rate of 2.5% per year. Calculate the value of his investment at the end of 6 years. $ …… [3] (b) Meera invests $700 in an account paying compound interest at a rate of r % per year. At the end of 17 years the value of her investment is $1030.35 . Find the value of r. r = …… [3]

Mark scheme

12(a) 805 3 B2 for 105 700 × 2.5 × 6 or M2 for + 700 oe 100 700 × 2.5 [×6] or M1 for oe 100 12(b) 2.3[0…] 3 1030.35 M2 for 17 oe 700 or M1 for 1030.35 = 700 ( k ) 17 oe for any k

Question 133 marks

Question

(a) Simplify h 2 # h 5 . …… [1] (b) Simplify b l . -3 7 x …… [1] (c) a8 ' a p = a2 Find the value of p. p = …… [1]

Mark scheme

13(a) h 7 final answer 1 13(b) x3 1 final answer 343 13(c) 6 1

Question 142 marks

Question

Calculate the circumference of a circle with radius 4.7 cm. …… cm [2] 1 11

Mark scheme

14 29.5 or 29.53… 2 M1 for 2 × π × 4.7 oe

Question 153 marks

Question

Without using a calculator, work out 2 # . 3 14 You must show all your working and give your answer as a mixed number in its simplest form. …… [3]

Mark scheme

15 7 M1 k 11 oe improper fraction or × where k > 3 3 3 14 5 A2 77 11 35 1 cao A1 for or or 1 6 42 6 42

Question 164 marks

Question

y 6 A 5 4 3 2 1 –8 –7 –6 –5 –4 –3 –2 –1 0 1 2 x –1 –2 –3 B –4 –5 –6 –7 –8 A is the point (- 6, 5) and B is the point (- 2, - 3). (a) Find the equation of the straight line, l, that passes through point A and point B. Give your answer in the form y = mx + c . y = …… [2] (b) Find the equation of the line that is perpendicular to l and passes through the origin. …… [2]

Mark scheme

16(a) [ y =] − 2 x − 7 final answer 2 B1 for − 2x + c or kx – 7, k ≠ 0 final answer 16(b) 1 2 1 y= x [ ±0] final answer FT − 2 their gradient in(a) B1 for y = kx [ ±0] oe, k ≠ 0 1 or y = their x + c oe for any c 2 1 or their x [ ±0] oe 2

Question 175 marks

Question

O R X NOT TO 4 cm SCALE P 11 cm Q The diagram shows a rectangle OPQR with length 11 cm and width 4 cm. OQ is a diagonal and OPX is a sector of a circle, centre O. Calculate the percentage of the rectangle that is shaded. …… % [5]

Mark scheme

17 77.8 or 77.77 to 77.80 5 B4 for answer 22.2[%] or 22.20[%] to 22.23[%] OR 11 4 M1 for tan −1 oe or tan −1 oe 4 11 their acute angle M2 for 4 × 11 − × π × 42 oe 360 their acute angle or M1 for π × 42 oe 360 their shaded area M1 for [×100] oe 4 ×11 their sector area or ×100 oe 4 ×11

Question 186 marks

Question

Mrs Kohli buys a jacket, 2 shirts and a hat. The jacket costs $x. The shirts each cost $24 less than the jacket and the hat costs $16 less than the jacket. Mrs Kohli spends exactly $100. Write down an equation in terms of x. Solve this equation to find the cost of the jacket. $ …… [3] 19 y is inversely proportional to the square root of (x +4). When x = 5, y = 2. Find y when x = 77. y = …… [3]

Mark scheme

18 A correct equation leading to 3 M2 for 4 x = 164 41 or M1 for x + 2 ( x − 24 ) + x − 16 = 100 oe or M1 for correctly simplifying their equation to the form kx = c provided at least one part correct from [ 2] ( x − 24 ) oe or x − 16 or B1 for answer 41 without an equation in x shown

Question 19

Question

In the question paper above.

Mark scheme

19 2 3 k oe M1 for y = 3 x+4 theirk M1 for y = 77 + 4

Question 205 marks

Question

Solve the simultaneous equations. You must show all your working. 3x + y = 11 x 2 - 2y = 18 x = …… y = …… x = …… y = …… [5]

Mark scheme

20 x 2 + 6 x − 40 [=0] M2 M1 for correct method to eliminate one variable e.g. or y 2 − 40 y − 41 [=0] x 2 − 2 (11 − 3 x ) = 18 (11 − y )2 or − 2 y = 18 32 ( x − 4 )( x + 10 ) [=0] M1 or for correct factors for their quadratic equation or ( y − 41)( y + 1) [=0] or for correct use of quadratic formula for their quadratic equation or for correctly completing the square for their quadratic equation x = 4, y = − 1 B2 B1 for x = 4, x = − 10 x = −10, y = 41 or for y = − 1, y = 41 or for a correct pair of x and y values If B0 scored and at least 1 method mark scored SC1 for correct substitution shown of both of their x values or their y values into 3x + y = 11 or x2 – 2y = 18

Question 217 marks

Question

M H G E F NOT TO 14.5 cm SCALE D C 9 cm A 18.6 cm B The diagram shows an open rectangular box ABCDEFGH. AB = 18.6 cm, BC = 9 cm and CG = 14.5 cm. A straight stick AGM rests against A and G and extends outside the box to M. (a) Calculate the angle between the stick and the base of the box. …… [4] (b) AM = 30 cm. Show that GM = 4.8 cm, correct to 1 decimal place. [3]

Mark scheme

21(a) 35.1 or 35.05 to 35.06 4 14.5 M3 for tan = oe 18.62 + 92 or M2 for AC 2 = 18.62 + 92 oe or better or AG 2 = 18.62 + 92 + 14.52 or M1 for recognising the angle GAC 21(b) 30 − 18.62 + 92 + 14.52 M2 M1 for AG 2 = 18.62 + 92 + 14.52 oe or better 14.5 14.5 30 – or sin ( their (a) ) = sin ( their(a) ) AG or 18.62 + 92 or cos ( their (a) ) = 18.62 + 92 AG 30 – cos ( their (a) ) 4.75 to 4.78… A1

Question 224 marks

Question

R Q NOT TO a SCALE O b P The diagram shows a trapezium OPQR. O is the origin, OR = a and OP = b . 3 RQ = OP 5 (a) Find PQ in terms of a and b in its simplest form. PQ = …… [2] (b) When PQ and OR are extended, they intersect at W. Find the position vector of W. …… [2]

Mark scheme

22(a) 2 2 3 a − b oe simplified M1 for −b + a + b or a correct route 5 5 22(b) 5 2 5 ρ a oe B1 for ka where k >1 or OR 2 2

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How this paper is marked

Examiners follow the generic marking principles at the front of the scheme, then each question's points: method (M), accuracy (A) and independent (B) marks, error carried forward where the scheme allows it, and positive marking, so you're credited for what you got right.

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0580/22 questions

Where can I find the 0580/22 February/March 2022 mark scheme?

On this page, free: the mark scheme for IGCSE Mathematics 0580/22, February/March 2022 (0580_m22_ms_22), and the question paper (0580_m22_qp_22), to read or download, with each question's marking points written out underneath.

How many marks is 0580/22 out of?

Mathematics 0580/22 for February/March 2022 is out of 70 marks, with 1 hour 30 minutes to answer it.

Can I get my 0580/22 answers marked?

Yes. Upload your answers to 0580/22/F/M/22 as a PDF or photos, and CIE Buddy marks every question against this paper's official mark scheme, using Cambridge's marking rules. You get your score, each lost mark explained on your own script, and the topics to revise. It's a guide, not an official Cambridge grade.