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Mathematics 0580/42 May/June 2025: question paper and mark scheme

Cambridge IGCSE Mathematics (0580), Paper 4 (Extended), May/June 2025. Read both free below, or download them. Done the paper? Get it marked by AI against this mark scheme.

0580_s25_qp_420580_s25_ms_420580/42/M/J/25

Paper
Paper 4 (Extended)
Total marks
100
Time
2 hours
Code on the paper
0580/42/M/J/25
0580_s25_ms_42.pdf

0580/42 mark scheme, question by question

Each question as it's printed, and the mark scheme's points for it, as text. Diagrams, tables and graphs are in the PDFs above.

Question 11 mark

Question

A quadrilateral has these properties • the diagonals are the only lines of symmetry • it has rotational symmetry of order 2. Write down the mathematical name of this quadrilateral. …… [1]

Mark scheme

1 rhombus 1

Question 21 mark

Question

The diagram shows the net of a solid. Write down the mathematical name of this solid. …… [1] * 0000800000004 * DFD 4

Mark scheme

2 triangular prism 1

Question 33 marks

Question

Mass of box A : Mass of box B = 4 : 7 The mass of box B is 2.4 kg more than the mass of box A. Calculate the mass of box A and the mass of box B. box A …… kg box B …… kg [3]

Mark scheme

3 [A =] 3.2 3 B2 for one correct or for both correct but [B =] 5.6 reversed 2.4 or M1 for × k where k = 1, 4, 7 or 11 oe 7−4 x 4 or for = oe x + 2.4 7

Question 42 marks

Question

D 10 cm C NOT TO 8 cm SCALE A 12 cm B ABCD is a trapezium. Work out the area of the trapezium. …… cm 2 [2]

Mark scheme

4 88 2 1 M1 for (10 + 12) × 8 oe 2

Question 51 mark

Question

Scott changes $300 into pounds (£). The exchange rate is £1 = $1.20 . Calculate the amount Scott receives. …… pounds [1] * 0000800000005 * DFD 5

Mark scheme

5 250 1

Question 63 marks

Question

A solid wooden cone has base radius 4 cm and height 12 cm. The density of the wood is 0.74 g/cm 3 . Calculate the mass of the cone. [Density = Mass ' Volume] …… g [3]

Mark scheme

6 149 or 148.7 to 148.8… 3 1 M1 for × π × 42 ×12 oe 3 M1 for 0.74 × their volume

Question 72 marks

Question

y = mx + c Rearrange the formula to make m the subject. m = …… [2]

Mark scheme

7 y −c y c 2 y c [ m =] or − M1 for y – c = mx or c – y= –mx or =m+ x x x x x final answer

Question 81 mark

Question

Calculate. 2.1 2 - 1.9 0.5 …… [1] * 0000800000006 * DFD 6

Mark scheme

8 5.02 cao 1

Question 93 marks

Question

Solve the simultaneous equations. You must show all your working. 2w - 3y = 11 3w + y = 11 w = …… y = …… [3]

Mark scheme

9 Correct elimination of one M1 variable [w =] 4 A2 A1 for one correct [y =] –1 If A0 scored, SC1 for answers satisfying one of the original equations

Question 103 marks

Question

A group of 12 adults and 9 children travel on a bus. The cost of an adult ticket is $n. The cost of a child ticket is $ (n - 10) . The total cost of the tickets is $277.50 . Find the cost of one adult ticket. $ …… [3] * 0000800000007 * DFD 7

Mark scheme

10 17.5[0] cao 3 M1 for 12n + 9(n – 10) = 277.50 oe M1 dep on their equation using n and n – 10 for simplifying their equation correctly to an = b

Question 112 marks

Question

In a sale, the original price of a shirt is reduced by 15%. The sale price of the shirt is $23.63 . Find the original price of the shirt. $ …… [2]

Mark scheme

11 27.8[0] 2 100 − 15 M1 for X × = 23.63 oe 100

Question 122 marks

Question

The length of a rectangle is 16 cm, correct to the nearest centimetre. The width of the rectangle is 14 cm, correct to the nearest centimetre. Calculate the lower bound of the perimeter of the rectangle. …… cm [2] * 0000800000008 * DFD 8

Mark scheme

12 58 nfww 2 M1 for 15.5 oe or 13.5 oe seen

Question 134 marks

Question

A 12 cm P NOT TO 9 cm 6 cm SCALE B 16 cm C Q R Triangle ABC and triangle PQR are mathematically similar. (a) Calculate the length of PR. PR = ……cm [2] (b) Triangle ABC and triangle PQR are the cross-sections of two prisms. These prisms are mathematically similar. The volume of the smaller prism is 1120 cm 3. Calculate the volume of the larger prism. …… cm 3 [2]

Mark scheme

13(a) 8 2 9 12 M1 for = oe 6 PR 13(b) 3780 2 63 93 9 3 M1 for = or better or 1120 × oe 1120 V 6 3 9 or for × 3 1120 6

Question 142 marks

Question

Factorise. 5x - 10 - ax + 2a …… [2] * 0000800000009 * DFD 9

Mark scheme

14 (x – 2)(5 – a) final answer 2 M1 for 5(x – 2) – a (x – 2) or for x(5 – a) – 2 (5 – a) or –5(2 – x) + a (2 – x) or 2(a – 5) – x(a – 5) or for correct answer seen then spoilt

Question 152 marks

Question

The interior angle of a regular polygon is 172°. Find the number of sides of this polygon. …… [2]

Mark scheme

15 45 2 M1 for 360 oe or ( n − 2 )180 = 172 oe 180 − 172 n

Question 164 marks

Question

On any day, the probability that the weather will be sunny is 0.7 . (a) Find the probability that on any day the weather will not be sunny. …… [1] (b) When the weather is sunny, the probability that Rohit goes for a walk is 0.9 . When the weather is not sunny, the probability that Rohit goes for a walk is 0.2 . Find the probability that on any day Rohit goes for a walk. …… [3] * 0000800000010 * DFD 10

Mark scheme

16(a) 0.3 oe 1 16(b) 0.69 oe 3 M2 for 0.7 × 0.9 + (their 0.3) × 0.2 oe or M1 for 0.7 × 0.9 oe or (their 0.3) × 0.2 oe

Question 1710 marks

Question

(a) Alex invests $400 at a rate of 2.3% per year simple interest. Find the total amount Alex has at the end of 5 years. $ …… [3] (b) Virat has $100 to spend. In February he spends $x . In March he spends 10% more than he spends in February. In April he spends 10% more than he spends in March. At the end of April, Virat has $33.80 remaining. Find the value of x. x = …… [3] * 0000800000011 * DFD 11 (c) Bobbie invests $500 in an account that pays compound interest each year. At the end of 17 years, the value of Bobbie’s investment is $700.13 . Find the value of Bobbie’s investment at the end of 20 years. $ …… [4] * 0000800000012 * DFD 12

Mark scheme

17(a) 446 3 B2 for answer 46 400 × 2.3 × 5 or M2 for 400 + oe 100 400 × 2.3[×5] or M1 for oe 100 17(b) 20 nfww 3 M2 for x + 1.1x + 1.12 x = [100 –] 33.80 oe 2 10 or M1 for 1 + [ x] oe seen 100 or for one correctly evaluated trial 17(c) 742.97 to 742.99 4 B3 for 1.02[0…] or interest rate = 2[.0…][%] OR 20 700.13 M3 for 500 × 17 oe 500 3 700.13 or for 700.13× 17 oe 500 700.13 or M2 for 17 oe 500 OR M1 for 500(…)17 = 700.13 oe M1 dep on previous M1 for 20 3 their r their r 500 × 1 + or 700.13 × 1 + 100 100

Question 184 marks

Question

D z° E C NOT TO x° 26° SCALE y° 52° 125° A B A, B, C, D and E lie on a circle. Find the values of x, y and z. x = …… y = …… z = …… [4] * 0000800000013 * DFD 13

Mark scheme

18 [x =] 29 4 B1 for 29 [y =] 52 [z =] 107 B1 for 52 B2FT for 107 or for z = their x + their y + 26 or B1 for EAC = 73 or EBC = 73 or B1FT for EAC = 180 – (their x + their y + 26)

Question 196 marks

Question

f (x) = x + 1 g (x) = 5 - 2x h (x) = 2 x (a) Find f (–3) . …… [1] (b) The domain of g (x) is {–3, 0, 2}. Find the range of g (x) . { …… } [2] 1 (c) Find x when h (x) = . 32 x = …… [1] (d) Find x when h –1 (x) = 3 . x = …… [2] * 0000800000014 * DFD 14

Mark scheme

19(a) –2 1 19(b) 11, 5, 1 2 B1 for 2 correct listed on answer line 19(c) –5 1 19(d) 8 2 M1 for [x =] h(3) or [x =] 23

Question 2013 marks

Question

C NOT TO SCALE 10 m 56° 12 m D B 34° A The diagram shows a quadrilateral ABCD. CD = 10 m and DB = 12 m. Angle DBA = 90°, angle CDB = 56° and angle ADB = 34°. (a) Calculate the length of AB. AB = …… m [2] (b) Calculate the area of the quadrilateral ABCD. …… m 2 [3] * 0000800000015 * DFD 15 (c) Calculate the perimeter of the quadrilateral ABCD. …… m [5] (d) Calculate the shortest distance from B to the line AD. …… m [3]

Mark scheme

20(a) 8.09 or 8.094… 2 AB M1 for tan 34 = oe 12 20(b) 98.3 or 98.28 to 98.31 3 1 M1 for × 10 ×12sin 56 oe 2 1 M1 for × 12 × their (a) oe 2 20(c) 43[.0] to 43.1 5 M2 for [BC =] 102 +122 − 2×10×12cos56 or M1 for [BC [2] =] 102 +122 – 2×10×12cos56 12 M2 for [AD =] oe cos34 12 or M1 for cos 34 = oe AD 20(d) 6.71 or 6.706 to 6.710… 3 dist M2 for sin 34 = oe or 12 1 1 ×12 × their (a) = × theirAD × dist oe 2 2 or M1 for recognition of perpendicular distance

Question 214 marks

Question

Simplify. (a) 3t 5 # 5t 3 …… [2] 5 (b) `64u 36j6 …… [2] * 0000800000016 * DFD 16

Mark scheme

21(a) 15t8 final answer 2 B1 for answer kt8 or 15tk (k > 0) or correct answer seen 21(b) 32u30 final answer 2 B1 for answer ku30 or 32uk (k > 0) or correct answer seen

Question 225 marks

Question

% G H 8 13 7 5 % = {number of students in a class} G = {number of students who study geography} H = {number of students who study history} The Venn diagram shows information about the 33 students in a class. (a) One of the students in the class is picked at random. Find the probability that this student (i) does not study geography and does not study history …… [1] (ii) studies geography and studies history. …… [1] (b) Two of the students who study history are picked at random. Find the probability that one student also studies geography and one student does not study geography. …… [3] * 0000800000017 * DFD 17

Mark scheme

22(a)(i) 5 1 oe 33 22(a)(ii) 13 1 oe 33 22(b) 91 3 13 7 oe M2 for [2×] × oe 190 20 19 13 12 7 6 or for 1 − × − × oe 20 19 20 19 13 13 7 7 or M1 for or or or oe seen 20 19 20 19 91 If 0 scored, SC1 for answer oe 200

Question 233 marks

Question

Simplify. h 2 + 4h h 2 - 16 …… [3]

Mark scheme

23 h 3 B1 for h(h + 4) isw final answer h−4 B1 for (h + 4)(h – 4) isw

Question 248 marks

Question

Ahmed walks 2 km at a speed of x km/h. He then walks a further 3 km at a speed of (x + 1) km/h. 1 The total time he takes to walk the 5 km is 1 hours. 4 (a) Show that 5x 2 - 15x - 8 = 0 . [5] (b) Find the value of x. Show all your working and give your answer correct to 2 decimal places. x = …… [3] * 0000800000018 * DFD 18

Mark scheme

24(a) 2 3 5 M2 2 3 + = oe M1 for seen or seen x x +1 4 x x +1 2 × 4(x + 1) + 3 × 4x = 5x(x + 1) M1 Correctly removing algebraic fractions or use of or common denominator from their three-term 2 ( x + 1) 3x 5 equation with two fractions with different + = algebraic denominators x ( x + 1) x ( x + 1) 4 8x + 8 + 12x = 5x2 + 5x oe M1 Correctly multiplying their brackets and clearing algebraic fractions from their three-term equation with two fractions with different algebraic denominators Leading to 5x2 – 15x – 8 = 0 A1 With no errors or omissions 24(b) [− −]15 + ([−]15) 2 − 4(5)(−8) B2 B1 for ([−]15)2 − 4 × 5 × −8 oe oe 2(5) 15 + p 15 − p or or for oe or oe 2(5) 2(5) 2 3 8 3 2 + + oe 3 2 5 2 or for x − oe 2 3.46 B1

Question 255 marks

Question

P is the point (8, 0) and Q is the point (20, 6). Find the equation of the perpendicular bisector of PQ. Give your answer in the form y = mx + c . y = …… [5]

Mark scheme

25 [y =] –2x + 31 5 B1 for (14, 3) AND 6−0 M1 for (m1 ) oe 20 − 8 1 M1 for m = − their m1 AND M1dep for their 3 = their m × their 14 + c oe

Question 262 marks

Question

y = ax 11 + 3x b dy = 44x 10 + 18x c dx Find the values of a, b and c. a = …… b = …… c = …… [2] * 0000800000019 * DFD 19

Mark scheme

26 [a =] 4 2 B1 for one correct [b =] 6 [c =] 5

Question 274 marks

Question

P NOT TO SCALE D C A B The diagram shows a cube. Calculate the angle between the diagonal AP and the base ABCD. …… [4] * 0000800000020 * DFD 20

Mark scheme

27 35.3 or 35.26… 4 M3 for correct numerical trig statement for angle PAC e.g. l 1 tan = or oe 2 l +l 2 2 l 1 or sin = or oe l2 + l2 + l2 3 l2 + l2 2 or cos = or oe l2 + l2 + l2 3 where l is a value or M2 for a correct Pythagoras statement soi or correct trig statement for diagonal of a face with angle 45 used soi e.g. For side length k, AC shown as k 2 or M1 for recognition of angle PAC

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Where can I find the 0580/42 May/June 2025 mark scheme?

On this page, free: the mark scheme for IGCSE Mathematics 0580/42, May/June 2025 (0580_s25_ms_42), and the question paper (0580_s25_qp_42), to read or download, with each question's marking points written out underneath.

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Mathematics 0580/42 for May/June 2025 is out of 100 marks, with 2 hours to answer it.

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