Question 11 mark
Question
Write two hundred thousand and seventeen in figures. …… [1]
Mark scheme
1 200 017 1
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Cambridge IGCSE Mathematics (0580), Paper 2 (Extended), October/November 2020. Read both free below, or download them. Done the paper? Get it marked by AI against this mark scheme.
0580_w20_qp_220580_w20_ms_220580/22/O/N/20
Each question as it's printed, and the mark scheme's points for it, as text. Diagrams, tables and graphs are in the PDFs above.
Question
Write two hundred thousand and seventeen in figures. …… [1]
Mark scheme
1 200 017 1
Question
Insert one pair of brackets to make this calculation correct. 7 - 5 - 3 + 4 = 9 [1]
Mark scheme
2 7 – (5 – 3) + 4 1
Question
Solve the equation. 6 - 2x = 3x x = …… [2]
Mark scheme
3 1 6 2 M1 for 6 = 2x + 3x or better 1.2 or 1 or 5 5
Question
x° y° NOT TO SCALE 140° 120° The diagram shows a triangle drawn between a pair of parallel lines. Find the value of x and the value of y. x = …… y = …… [3]
Mark scheme
4 [x =] 60 3 B1 for [x =] 60 [y =] 80 B2 for [y =] 80 or B1 for 40 in a correct place on diagram If 0 scored SC1 for their x + their y = 140
Question
Increase 42 by 16%. …… [2]
Mark scheme
5 48.72 2 16 M1 for × 42 oe or better 100
Question
Factorise completely. 4 - 8x …… [1]
Mark scheme
6 4(1 – 2x) 1
Question
C NOT TO SCALE h cm A 6 cm B The area of triangle ABC is 27 cm 2 and AB = 6 cm. Calculate the value of h. h = …… [2]
Mark scheme
7 9 2 1 M1 for × 6 × h = 27 oe 2
Question
Calculate the size of one interior angle of a regular polygon with 40 sides. …… [2]
Mark scheme
8 171 2 M1 for 180 – (360 ÷ 40) oe or ( 40 − 2 ) × 180 oe 40
Question
Solve the simultaneous equations. 2x + y = 7 3x - y = 8 x = …… y = …… [2] 5 1
Mark scheme
9 [x =] 3 2 B1 for each [y =] 1
Question
Without using a calculator, work out '1 . 6 3 You must show all your working and give your answer as a fraction in its simplest form. …… [3]
Mark scheme
10 5 3 5 8 M2 4 5 3 × or ÷ oe M1 for seen or for × their 6 4 6 6 3 6 4 5 their8 or for ÷ 6 6 5 A1 dep on M2 cao 8
Question
Simplify. 2x 2 # 5x 5 …… [2]
Mark scheme
11 10x7 final answer 2 B1 for kx7 or 10xk final answer or for correct answer then spoilt
Question
Alex and Chris share sweets in the ratio Alex : Chris = 7 : 3. Alex receives 20 more sweets than Chris. Work out the number of sweets Chris receives. …… [2]
Mark scheme
12 15 2 M1 for 4 [parts] = 20 soi or x + 20 x a correct equation e.g. = oe 7 3
Question
The length of one side of a rectangle is 12 cm. The length of the diagonal of the rectangle is 13 cm. Calculate the area of the rectangle. …… cm 2 [3]
Mark scheme
13 60 3 M2 for 12 × 132 − 122 or M1 for 132 – 122 or for 12 × their 5 from Pythagoras or trig
Question
Work out (3 # 10 199) + (2 # 10 201) . Give your answer in standard form. …… [2]
Mark scheme
14 2.03 × 10201 2 B1 for figs 203 or [0].03 × 10201 or 200 × 10199
Question
NOT TO SCALE 60° 7.5 cm Calculate the area of this sector of a circle. …… cm 2 [2]
Mark scheme
15 29.5 or 29.45 to 29.46 2 60 M1 for × π × 7.52 oe 360
Question
The selling price of a shirt is $26.50 . This includes a tax of 6%. Calculate the price of the shirt before the tax was added. $ …… [2]
Mark scheme
16 25 2 6 M1 for x × 1 + = 26.50 oe or better 100
Question
4 3 Speed 2 (m/s) 1 0 0 10 20 30 40 Time (seconds) The diagram shows the speed–time graph for the first 40 seconds of a cycle ride. (a) Find the acceleration between 20 and 40 seconds. …… m/s 2 [1] (b) Find the total distance travelled. …… m [3]
Mark scheme
17(a) 1 1 0.1 or 10 17(b) 90 3 M2 for 1 1 × 10 × 2 +10 × 2 + ( 2 + 4 ) × 20 oe 2 2 or M1 for one area calculation or indicated on diagram
Question
The sides of an isosceles triangle are measured correct to the nearest millimetre. One side has a length of 8.2 cm and another has a length of 9.4 cm. Find the largest possible value of the perimeter of this triangle. …… cm [3]
Mark scheme
18 27.15 cao 3 M2 for (9.4 + 0.05) × 2 + 8.2 + 0.05 or better or M1 for 8.2 + 0.05 or 9.4 + 0.05 or better seen OR SC2 for answer 25.95 or SC1 for answer 26.85
Question
100° NOT TO 8 cm SCALE x° 9 cm (a) Calculate the value of x. x = …… [3] (b) Calculate the area of the triangle. …… cm 2 [3]
Mark scheme
19(a) 61.1 or 61.08 to 61.09... 3 8sin100 M2 for [sin x =] oe or better 9 9 8 or M1 for = oe sin100 sin x 19(b) 11.7 or 11.66 to 11.67 3 M2 for 1 × 9 × 8 × sin(180 − 100 − their (a)) oe 2 or M1 for 180 – 100 – their (a)
Question
A model of a statue has a height of 4 cm. The volume of the model is 12 cm 3 . The volume of the statue is 40 500 cm 3 . Calculate the height of the statue. …… cm [3]
Mark scheme
20 60 3 40500 M2 for 4 × 3 oe 12 3 4 12 or M1 for = oe l 40500 40500 12 or 3 oe or 3 oe 12 40500
Question
(a) Differentiate 6 + 4x - x 2 . …… [2] (b) Find the coordinates of the turning point of the graph of y = 6 + 4x - x 2 . ( …… , …… ) [2]
Mark scheme
21(a) 4 – 2x 2 B1 for 4 or – 2x 21(b) (2, 10) 2 B1 for x-coordinate of 2 or M1 for their 4 – 2x = 0
Question
C A NOT TO SCALE a M O B b The diagram shows a triangle OAB and a straight line OAC. OA : OC = 2 : 5 and M is the midpoint of AB. OA = a and OB = b . Find, in terms of a and b, in its simplest form (a) AB, AB = …… [1] (b) MC . MC = …… [3]
Mark scheme
22(a) –a + b 1 22(b) 1 3 1 1 2a – b B2 for answer 2a + pb or qa – bq≠ 2 2 2 or correct unsimplified answer in terms of a and b ρ 3 ρ 5 or M1 for AC = a or OC = a or 2 2 correct route 1 If 0 scored SC1 for answer a + b 2
Question
Write as a single fraction in its simplest form. 2x - 1 2- x+1 …… [3] 1
Mark scheme
23 3 3 B1 for 2( x + 1) − (2 x − 1) oe final answer x +1 B1 for common denominator x + 1
Question
A line from the point (2, 3) is perpendicular to the line y = x + 1. 3 The two lines meet at the point P. Find the coordinates of P. ( …… , …… ) [5] Questions 25 and 26 are printed on the next page.
Mark scheme
24 (2.4, 1.8) oe 5 1 M1 for [gradient =] –1 ÷ oe 3 M1 for substituting (2, 3) into y = (their m)x + c oe 1 M1 for x + 1 = their ( mx + c ) with 3 1 their m ≠ 3 M1 for substituting their x-coord into either equation to find y or for substituting their y-coord into either equation to find x
Question
Solve the equation tan x = 2 for 0° G x G 360° . x = …… or x = …… [2]
Mark scheme
25 63.4 or 63.43... 2 B1 for each 243.4 or 243.4... If 0 scored SC1 for two answers with a difference of 180
Question
Simplify. ux - 2u - x + 2 u2 - 1 …… [4]
Mark scheme
26 x−2 4 B2 for ( x − 2)(u − 1) oe final answer u +1 or B1 for u ( x − 2) − ( x − 2) or x(u − 1) − 2(u − 1) B1 for (u − 1)(u + 1)
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Mark my 0580/22Examiners follow the generic marking principles at the front of the scheme, then each question's points: method (M), accuracy (A) and independent (B) marks, error carried forward where the scheme allows it, and positive marking, so you're credited for what you got right.
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Mathematics 0580/22 for October/November 2020 is out of 70 marks, with 1 hour 30 minutes to answer it.
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