Free until 14 Nov · 80% off for the first 100 · Pricing

Biology 0610/52 May/June 2025: question paper and mark scheme

Cambridge IGCSE Biology (0610), Paper 5 Practical Test, May/June 2025. Read both free below, or download them. Done the paper? Get it marked by AI against this mark scheme.

0610_s25_qp_520610_s25_ms_520610/52/M/J/25

Paper
Paper 5 Practical Test
Total marks
40
Time
1 hour 15 minutes
Code on the paper
0610/52/M/J/25
0610_s25_ms_52.pdf

0610/52 mark scheme, question by question

Each question as it's printed, and the mark scheme's points for it, as text. Diagrams, tables and graphs are in the PDFs above.

Question 120 marks

Question

You are going to investigate the effect of the concentration of salt solutions on osmosis in potato tissue. Read all the instructions but DO NOT DO THEM until you have drawn a table for your results in the space provided in 1(a)(ii). You should use the safety equipment provided while you are doing the practical work. You are going to use three different concentrations of salt solution. Step 1 Label three beakers S1, S2 and S3. (a) (i) Decide the volumes of salt solution S and distilled water W you need to make 50 cm3 of a 0.5 mol per dm3 salt solution. Complete Table 1.1 by writing in the volumes of S and W you will use to make the 0.5 mol per dm3 salt solution. Table 1.1 volume of volume of final concentration of 1.0 mol per dm3 beaker distilled water W salt solution salt solution S / cm3 / mol per dm3 / cm3 S1 50 0 1.0 S2 0.5 S3 0 50 0.0 [1] Step 2 Use the volumes of 1.0 mol per dm3 salt solution S and distilled water W shown in Table 1.1 to make the salt solutions in beakers S1, S2 and S3. Step 3 Put the potato cylinders onto a white tile and cut each potato cylinder into 3 mm discs, as shown in Fig. 1.1. You will need 30 discs of potato for this investigation and one extra potato disc for Question 1(b). Leave the extra potato disc on the white tile. 3 mm Fig. 1.1 * 0000800000004 * DFD 4 Step 4 Place 10 potato discs in a line on the white tile. Place the ruler at the start of the line so you can measure the total length of the line of potato discs, as shown in Fig. 1.2. 1 2 3 4 5 6 7 8 9 potato discs not to scale Fig. 1.2 Step 5 Measure the total length of the 10 potato discs and record this value in your table in 1(a)(ii). Step 6 Put the 10 potato discs from step 5 into beaker S1. Step 7 Repeat step 4 to step 6 with the other potato discs and the salt solutions in beakers S2 and S3. Step 8 Start the stop-clock and leave the potato discs in the beakers of salt solution for 20 minutes. Continue with the rest of the questions while you are waiting. Step 9 After 20 minutes, pour the salt solution from beaker S1 into the beaker labelled waste. Step 10 Put the 10 potato discs from beaker S1 onto the white tile and line them up as shown in Fig. 1.2. Step 11 Measure the final total length of the 10 potato discs and record this value in your table in 1(a)(ii). Step 12 Pour the salt solution from beaker S2 into the waste beaker and repeat step 10 and step 11. Step 13 Pour the salt solution from beaker S3 into the waste beaker and repeat step 10 and step 11. (ii) Prepare a table and record your results. Include the final concentrations of the salt solutions in your table. [4] * 0000800000005 * DFD 5 (iii) Calculate the change in total length of the 10 discs in each beaker. beaker S1 …… beaker S2 …… beaker S3 …… [1] (iv) State a conclusion for your results. …… [1] (v) State the dependent variable in this investigation. …… [1] (vi) Identify one source of error in this investigation. …… [1] (vii) Describe one safety precaution you took when preparing the potato discs. …… [1] (b) Put a few drops of iodine solution onto the potato disc that you kept from step 3. Record the final colour of the iodine solution on the potato disc and state a conclusion for this test. final colour …… conclusion …… [1] * 0000800000006 * DFD 6 (c) Fig. 1.3 shows a leaf from a potato plant. P Q Fig. 1.3 (i) Draw a large diagram of the leaf shown in Fig. 1.3. [4] * 0000800000007 * DFD 7 (ii) Line PQ represents the length of the leaf in Fig. 1.3. Measure the length of line PQ in Fig. 1.3. length of line PQ …… mm The actual length of the leaf is 39 mm. Using your measurement and the formula, calculate the magnification of the leaf in Fig. 1.3. length of line PQ in Fig. 1.3 magnification = actual length of the leaf Give your answer to two significant figures. Space for working. [3] (iii) Fig. 1.4 shows a leaf from a tomato plant. The tomato leaf is narrower than the potato leaf shown in Fig. 1.3. Fig. 1.4 Compare the leaves shown in Fig. 1.3 and in Fig. 1.4. Describe one visible difference, other than size, and one visible similarity. difference …… similarity …… [2] [Total: 20] * 0000800000008 * DFD 8

Mark scheme

1(a)(i) 25 and 25 (cm3) ; 1 1(a)(ii) table drawn with a minimum of three columns and a header line ; 4 suitable headings with correct units for concentration and length ; six lengths recorded ; correct trend - change in S1 is greater than change in S3 ; 1(a)(iii) correct values calculated ; 1 1(a)(iv) any one from: 1 the higher the concentration (of salt), the, more / faster, osmosis occurs ; A potatoes have a higher water potential than the higher the concentration (of salt) the more water, is lost / moves out ; the salt solution but a lower water potential water move out of the, potato / disc(s), in salt solution(s) ; than (pure/distilled) water water moves into the, potato / disc(s), when there is no salt / in pure water / in 0 mol dm3 ; the solute concentration of the potato (cell(s)) is between 0.5 mol dm3 and 0 mol dm3 ; 1(a)(v) length (of discs) ; 1 1(a)(vi) any one from: 1 difficult to line up discs along ruler ; difficult to mark / measure length due to curve on potato discs ; idea of contamination of the measuring cylinder ; AVP ; 1(a)(viii) cut, on a tile / on a flat surface / away from hand or body / AW ; 1 1(b) final colour: blue-black 1 and conclusion: starch present ; 1(c)(i) Outline is a single clear line with no shading ; 4 Size –at least half the available space used ; Detail 1: midrib as a double line for at least half its length ; Detail 2: four bumps across the base of the leaf (two on either side of the petiole and two bulges at the edges) ; 1(c)(ii) PQ = 63 ± 1 (mm) ; 3 MP1 correct measurement of line PQ (×) 1.6 ;; MP2 correct calculation of the actual size to any number of significant figures MP3 correct rounding to three significant figures ecf from previous step 1(c)(iii) one difference from: ; 2 (potato / Fig. 1.3) (tomato / Fig. 1.4) more veins OR fewer veins veins more OR veins less branched branched (outline / side / edge AND (outline / side / edge is) is) smooth / even / not uneven / lobed / wav lobed y / jagged / bumpy single / undivided / n AND divided ot lobed , leaf leaf / leaflet / lobed (at bottom) Symmetrical AND not symmetrical / irregul ar shape one similarity from: ; • (both have) veins / midrib • (both have) a (leaf) stalk / stem / petiole (both have) a pointed tip

Question 214 marks

Question

(a) The enzyme pectinase is used in the production of apple juice. In an experiment, a student investigated the production of apple juice using five different concentrations of pectinase solution. For each concentration, the student: • put 100 g of crushed apple into a beaker • added 10 cm3 of the pectinase solution to the crushed apple • left the crushed apple and enzyme mixture for 30 minutes at 40 °C • filtered the apple juice from the mixture • measured the volume of apple juice produced. (i) The temperature was maintained at 40 °C. Describe how the student could maintain the crushed apple and enzyme mixture at a constant temperature. …… [1] (ii) State two other variables that were kept constant in this investigation. 1 …… 2 …… [2] (b) The results of this investigation are shown in Table 2.1. Table 2.1 percentage concentration volume of apple juice of the pectinase solution produced / cm3 0.1 4 0.2 6 0.4 12 0.8 22 1.6 22 * 0000800000009 * DFD 9 (i) Plot a line graph on the grid of the data in Table 2.1. [4] (ii) Use your graph to estimate the volume of apple juice produced with a 0.5% pectinase solution. Show on your graph how you obtained your answer. …… cm3 [2] (iii) Describe the effect of pectinase solution concentration on apple juice production. …… [1] * 0000800000010 * DFD 10 (iv) Pectinase is used to produce apple juice commercially. Suggest what extra data would be required to determine if a 0.8% pectinase solution is the optimum concentration for the production of apple juice. …… [1] (v) Draw and label the apparatus the student could use to filter and measure the volume of apple juice produced. [3] [Total: 14] * 0000800000011 * DFD 11

Mark scheme

2(a)(i) thermostatic(ally controlled) water-bath / AVP ; 1 2(a)(ii) any two from: 2 mass of apple ; volume of, pectinase / enzyme (solution) ; time / left for 30 minutes ; 2(b)(i) axes labelled with units ; 4 suitable linear scale and data occupies at least half the grid in both directions ; all points plotted accurately ± half a small square ; suitable line drawn ; 2(b)(ii) any indication on graph at 0.5% pectinase concentration / indication of 2 correct value on the volume axis ; correct value recorded from candidates graph ; 2(b)(iii) increasing, concentration / pectinase , increases juice production 1 and then stops increasing / AW ; 2(b)(iv) more concentrations measured between 0.4% and 1.6% ; 1 A smaller intervals above and below, 0.8% e.g. 0.7% and 0.9% A smaller intervals around 0.8% 2(b)(v) drawings of: 3 funnel with filter paper ; measuring cylinder ; labelling: at least one item correctly labelled ;

Question 36 marks

Question

Hydrogencarbonate indicator can be used to determine the concentration of carbon dioxide in a solution. The table shows the colour of the indicator at different concentrations of carbon dioxide. carbon dioxide hydrogencarbonate concentration indicator colour high yellow medium red low purple Aquatic plants photosynthesise and use up carbon dioxide when in the light. Aquatic plants respire and produce carbon dioxide in the light and in the dark. When the carbon dioxide produced is equal to carbon dioxide used, hydrogencarbonate indicator is red. Using an aquatic plant, plan an investigation to determine the light intensity at which the rate of photosynthesis is equal to the rate of respiration. …… [6] * 0000800000012 * DFD 12

Mark scheme

3 independent variable 6 1 at least three different light intensities ; dependent variable 2 the colour of the indicator ; 3 and 4 details of the method ;; • method of changing light intensity e.g. different lamp distances / dimmer switch altered / different bulbs / different lamps / different power lamps / detail of how to make one in the dark and one in the light • method to avoid heating effect of light e.g. heat shield / beaker of water between lamp and plant / use LED bulbs to prevent heating • keeping the plant under the water / weighting the plant down • sample the water around the plant and test with indicator 5 and 6 and 7 variables kept constant ;;; • colour / wavelength, of light • temperature • type / species / age, of plant • size / mass / length / height / surface area / number of leaves, of plant • volume of water (covering plant) • volume / number of drops, of (hydrogencarbonate) indicator • concentration of (hydrogencarbonate) indicator • set (stated) time for equilibration (to the new light intensity) • set (stated) time before noting colour 8 two or more repeats ; 9 relevant safety ;

Checked your answers against these? Let AI mark the whole paper, on your own working.

Mark my 0610/52

How this paper is marked

Examiners follow the generic marking principles at the front of the scheme, then each question's points: method (M), accuracy (A) and independent (B) marks, error carried forward where the scheme allows it, and positive marking, so you're credited for what you got right.

Check your answers against it

Done this paper? Upload your script and CIE Buddy's AI marker marks it question by question against this exact scheme, puts the ticks on your own working and says what each lost mark needed.

0610/52 in other series

Find another Biology paper

Every IGCSE Biology mark scheme

Question papers and mark schemes © Cambridge University Press & Assessment. CIE Buddy is independent and not connected to Cambridge.

0610/52 questions

Where can I find the 0610/52 May/June 2025 mark scheme?

On this page, free: the mark scheme for IGCSE Biology 0610/52, May/June 2025 (0610_s25_ms_52), and the question paper (0610_s25_qp_52), to read or download, with each question's marking points written out underneath.

How many marks is 0610/52 out of?

Biology 0610/52 for May/June 2025 is out of 40 marks, with 1 hour 15 minutes to answer it.

Can I get my 0610/52 answers marked?

Yes. Upload your answers to 0610/52/M/J/25 as a PDF or photos, and CIE Buddy marks every question against this paper's official mark scheme, using Cambridge's marking rules. You get your score, each lost mark explained on your own script, and the topics to revise. It's a guide, not an official Cambridge grade.