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Biology 0610/63 October/November 2019: question paper and mark scheme

Cambridge IGCSE Biology (0610), Paper 6 Alternative to Practical, October/November 2019. Read both free below, or download them. Done the paper? Get it marked by AI against this mark scheme.

0610_w19_qp_630610_w19_ms_630610/63/O/N/19

Paper
Paper 6 Alternative to Practical
Total marks
40
Time
1 hour
Questions
2
Code on the paper
0610/63/O/N/19
0610_w19_ms_63.pdf

0610/63 mark scheme, question by question

Each question as it's printed, and the mark scheme's points for it, as text. Diagrams, tables and graphs are in the PDFs above.

Question 118 marks

Question

Photosynthesis occurs in chloroplasts. A chloroplast suspension can be made by extracting the chloroplasts from green leaves. The blue dye DCPIP can be used to investigate photosynthesis. During photosynthesis the blue colour of the DCPIP changes and eventually disappears so that it becomes colourless. The remaining mixture appears green due to the chloroplast suspension. A student investigated the effect of light on photosynthesis in a chloroplast suspension. Step 1 The student crushed eight green leaves in an ice-cold buffer solution. Step 2 The mixture of crushed leaves and buffer solution was then filtered to form a chloroplast suspension. Step 3 The student was given two test-tubes. One test-tube was wrapped in aluminium foil to exclude light. The second test-tube was not covered in foil so that light could reach the contents of this test-tube. Step 4 A plastic pipette was used to add 2 cm3 of the chloroplast suspension to each of the two test-tubes. Step 5 A syringe was used to add 5 cm3 of DCPIP solution to both test-tubes. A stopper was placed in each test-tube. Step 6 Both test-tubes were placed in a water-bath containing ice-cold water. The water-bath was positioned near a bright light. Step 7 The test-tubes were left in the bright light for five minutes. Step 8 After five minutes the student observed and noted the colour of the liquid in the test-tube that was not wrapped in foil. They removed the foil from the covered test-tube and observed the colour in this test-tube. The student’s results are shown in Fig. 1.1. light – green dark – blue Fig. 1.1 (a) (i) Prepare a table and record the results from Fig. 1.1. [2] (ii) Identify the variable that was changed (independent variable) and the variable that was measured (dependent variable) in this investigation. independent variable …… dependent variable …… [2] (iii) State two variables that were kept constant in this investigation. 1 …… 2 …… [2] (iv) State a conclusion for these results. …… [1] (b) In step 6 both test-tubes were placed in a water-bath containing ice-cold water for five minutes. A thermometer was also placed in the water-bath. Fig. 1.2 shows the thermometer at the start of the investigation and after five minutes. at the start of after five the investigation minutes 30 30 20 20 10 10 0 0 Fig. 1.2 Record the temperatures shown in Fig. 1.2. Include the units. temperature at the start of the investigation …… temperature after five minutes …… [2] (c) The investigation was not repeated. (i) Suggest why it would be advisable to repeat the investigation. …… [1] (ii) Identify one other source of error in this investigation and suggest an improvement for this error. error …… improvement …… [2] (d) A student wanted to investigate the effect of temperature on the rate of photosynthesis in a chloroplast suspension. Describe how the student could carry out this investigation using DCPIP. …… [6] [Total: 18]

Mark scheme

(a)(i) table drawn with lines, minimum two columns + row headings 2 underlined + suitable headings ; colour matches condition ; 1(a)(ii) independent variable: light (and dark) / amount of light ; 2 dependent variable: colour (of the chloroplast suspension) ; 1(a)(iii) volume of chloroplast suspension ; 2 concentration of chloroplast suspension ; volume of DCPIP ; concentration of DCPIP ; time ; (same) age / type of leaf ; temperature / ice-cold ; buffer solution / pH ; 1(a)(iv) light is needed for photosynthesis / AW ; ora 1 1(b) 2 and 8 ; 2 °C ; 1(c)(i) to identify, anomalous results / outliers / AW ; 1 PUBLISHED 1(c)(ii) 2 the improvement must match the error given error ; improvement ; chloroplasts settle out stir the chloroplast suspension (plastic) pipettes are used to use a syringe / burette, to measure volume / volume of measure the chloroplasts chloroplasts was inaccurate temperature not maintained insulate beaker / use heat shield / add more ice DCPIP and chloroplast stir or shake extract not mixed subjective end-point / AW use colour chart / white surface / colorimeter mixture of leaves select leaves of same type different time for each test- stagger start / do tube sequentially test-tubes not the same leave in water-bath for some temperature as water-bath time before at the start starting / equilibrate AVP, e.g. insufficient CO2 AVP, e.g. add HCO3 PUBLISHED 1(d) given method (max 2): 6 A correct alternative methods 1 method of extracting chloroplasts ; 2 add DCPIP to chloroplasts ; 3 concentration / (stated) volume of chloroplast suspension ; 4 concentration / (stated) volume of DCPIP ; 5 buffer solution / pH ; new method: 6 two or more different temperatures ; 7 method to maintain temperature ; 8 measure time taken for DCPIP to become colourless / determine reduction in blue colour after set time / AW ; 9 equilibrate ; 10 same carbon dioxide / CO2, concentration ; 11 leaves / chloroplasts, from same plant ; 12 same light intensity / same distance from light source ; 13 AVP ; 14 set up a test-tube with no DCPIP to compare to / method of telling when it has become colourless ; 15 set up control with boiled / no chloroplasts / glass beads ; 16 two or more repeats / replicates ; 17 safety ; e.g. goggles / gloves / ref. to safe method of heating / ref. to use of tongs for hot objects PUBLISHED

Question 222 marks

Question

Fig. 2.1 is a photomicrograph of part of the lower epidermis of a leaf. M stoma guard cell epidermal cell N magnification ×400 Fig. 2.1 (a) (i) Make a large drawing of Fig. 2.1. Do not label your drawing. [4] (ii) Measure the length of the line MN on Fig. 2.1. length of line MN …… mm Calculate the actual width of the guard cells and the stoma indicated by line MN in Fig. 2.1. Use the equation and information in Fig. 2.1. length of line MN on Fig. 2.1 magnification = actual width of the guard cells and the stoma Give your answer to two decimal places. …… mm [3] (b) A student investigated the effect of sucrose concentration on stomatal opening. Strips of epidermis from leaves were placed in different concentrations of sucrose solution for one hour. The student measured the width of 10 stomatal openings from the epidermis in each sucrose solution. The results are shown in Table 2.1. Table 2.1 percentage width of stomatal opening / μm concentration of sucrose 1 2 3 4 5 6 7 8 9 10 average 0 5 6 7 5 5 6 7 5 7 6 5.9 5 3 4 3 3 4 3 2 3 3 2 20 1 2 1 2 1 1 5 1 2 1 1.7 (i) Circle one measurement in Table 2.1 that could be anomalous. [1] (ii) Calculate the average width of stomatal opening in the 5% sucrose solution. Include the unit. [2] (c) Pineapple plants are adapted to grow in hot dry conditions. Scientists investigated the number of stomata open, in pineapple plants, at different times of day. The data is shown in Table 2.2 (00:00 is midnight). Table 2.2 average number of time of day stomata open per mm2 00:00 77 04:00 61 08:00 22 12:00 4 16:00 10 20:00 51 (i) Calculate the percentage change in the average number of open stomata per mm2 between 16:00 hours and 20:00 hours. Space for working. ……% [2] (ii) Plot a bar chart on the grid to show the data in Table 2.2. [3] (iii) Describe, using your graph, how the average number of open stomata per mm2 changes throughout the day. …… [2] (d) When fruit ripens the starch contained within it is converted into reducing sugars. (i) State the name of the substance that is used to test for the presence of starch. …… [1] (ii) Describe how you could safely show a reducing sugar was present in a sample of pineapple fruit juice. procedure …… safety …… …… [4] [Total: 22]

Mark scheme

(a)(i) lines: single clear lines, no shading ; 4 size: at least half available space ; detail: bottom epidermal cell larger than top epidermal cell ; thickening of guard cell inner cell indicated ; 2 (a)(ii) 31 ±1 (mm) ; 3 0.08 (mm) ;; ecf from measurements 2 (b)(i) 5 (20% sucrose, repeat 7) circled or indicated ; 1 2 (b)(ii) 3.0 ; 2 µm ; 2(c)(i) 410 ;; 2 2(c)(ii) axes labelled with units ; 3 even scale and working area occupies at least half the grid in both directions + bars clearly identified ; all values plotted accurately ± half a small square ; 2(c)(iii) (average number of stomata open) decreases and then 2 increases ; suitable data quote ; e.g. fewest open at 12:00 / highest number open at 00:00 / (decreases) from 0:00 (hours) to 12:00 / (increases) from 12:00 PUBLISHED 2(d)(i) iodine solution ; 1 2(d)(ii) procedure: 4 add Benedict’s (solution / reagent) ; heat ; green / yellow / orange / (brick) red ; safety: goggles / gloves / appropriate precaution with hot water described ;

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Where can I find the 0610/63 October/November 2019 mark scheme?

On this page, free: the mark scheme for IGCSE Biology 0610/63, October/November 2019 (0610_w19_ms_63), and the question paper (0610_w19_qp_63), to read or download, with each question's marking points written out underneath.

How many marks is 0610/63 out of?

Biology 0610/63 for October/November 2019 is out of 40 marks, with 1 hour to answer it, across 2 questions.

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