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Biology 0610/41 October/November 2023: question paper and mark scheme

Cambridge IGCSE Biology (0610), Paper 4 Theory (Extended), October/November 2023. Read both free below, or download them. Done the paper? Get it marked by AI against this mark scheme.

0610_w23_qp_410610_w23_ms_410610/41/O/N/23

Paper
Paper 4 Theory (Extended)
Total marks
80
Time
1 hour 15 minutes
Questions
6
Code on the paper
0610/41/O/N/23
0610_w23_ms_41.pdf

0610/41 mark scheme, question by question

Each question as it's printed, and the mark scheme's points for it, as text. Diagrams, tables and graphs are in the PDFs above.

Question 113 marks

Question

(a) Fig. 1.1 shows the changes in the concentration of two hormones involved in the menstrual cycle. Key Y Z concentration of hormone 0 7 14 21 28 day of menstrual cycle Fig. 1.1 (i) State the names of the hormones Y and Z in Fig. 1.1. Y …… Z …… [2] (ii) On Fig. 1.1, sketch a line to show the levels of progesterone through the 28-day menstrual cycle. [2] (iii) State the day in the 28-day menstrual cycle when the egg is most likely to be released from a follicle. …… [1] (iv) State the main site of progesterone production during pregnancy. …… [1] (b) Egg cells are contained in follicles in the ovary. At the start of the menstrual cycle, a follicle has an average diameter of 29 µm. Just before an egg is released from the follicle, the follicle has an average diameter of 22 mm. Calculate the percentage increase in the average diameter of the follicle from the start of the menstrual cycle, until just before an egg is released. Step 1 Convert the average starting diameter of a follicle to millimetres (mm). …… mm Step 2 Calculate the percentage increase. …… % Step 3 Give your answer to three significant figures. …… % [4] (c) Once an egg cell has been released from a follicle it can be fertilised by a sperm cell. State three adaptive features of a sperm cell. 1 …… 2 …… 3 …… [3] [Total: 13]

Mark scheme

1(a)(i) Y is FSH ; 2 Z is LH ; 1(a)(ii) line drawn: 2 low until day 14 ; increasing until day 21, then a decrease ; 1(a)(iii) 14 ; 1 1(a)(iv) placenta ; 1 1(b) Step 1: 0.029 (mm) ; 4 MP1 for correct Step 1 conversion Step 2: 75 762 ;; MP2 22 - 0.029 = 21.971mm in Step 2 Step 3: 75 800 (%) ; MP3 (21.971 ÷0.029) x 100 = 75762 in Step 2 MP4 correct rounding to three significant figures ecf from previous step 1(c) any three from: 3 flagellum ; (many) mitochondria ; acrosome (containing enzymes) ; haploid (nucleus) / AW ;

Question 215 marks

Question

(a) The small intestine is lined with many villi and is adapted to absorb glucose. Fig. 2.1 shows two villi from the lining of the small intestine. M N Fig. 2.1 (i) State the name of structure N in Fig. 2.1. …… [1] (ii) Cell M in Fig. 2.1 secretes mucus. State the name of cell M. …… [1] (iii) State one other place in the body where mucus secreting cells are found. …… [1] (iv) Describe and explain how the structure of a villus is adapted for its function. …… [4] (b) State the name of the main blood vessel that takes blood from the small intestine to the liver. …… [1] (c) All cells develop from stem cells. Describe what is meant by the term stem cell. …… [2] (d) Some cells in the small intestine have many mitochondria. Fig. 2.2 shows the variation in the average number of mitochondria found in three different types of cell. 1800 1600 1400 1200 average 1000 number of mitochondria per cell 800 600 400 200 0 heart muscle mature red blood cell epithelium in the small intestine type of cell Fig. 2.2 Explain the differences in the average number of mitochondria in each type of cell. …… [5] [Total: 15]

Mark scheme

2(a)(i) lacteal ; 1 2(a)(ii) goblet (cell) ; 1 2(a)(iii) trachea / bronchi / bronchioles / AVP ; 1 2(a)(iv) any four from: 4 microvilli ; (microvilli) provide a large surface area ; epithelium / lining, one cell thick / thin / AW ; ref. to diffusion ; ref. to enzyme production ; good blood supply ; (good blood supply) to maintain a steep concentration gradient ; ref. to lacteal / N, and fat transport ; AVP ; 2(b) hepatic portal vein ; 1 2(c) any two from: 2 unspecialised (cells) ; that divide by mitosis ; (to produce daughter cells) that become specialised (for specific functions) ; 2(d) any five from: 5 1 mitochondria are site of aerobic respiration ; 2 release energy ; 3 heart / intestine (cells), respire more ; 4 heart (cells) (continuously) contract ; 5 epithelial cells need more energy ; 6 active transport in the small intestine ; 7 red blood cells need space, for haemoglobin / oxygen ; 8 red blood cells, are moved in the blood / do not (actively) move ; 9 red blood cells, take up/ release, oxygen by diffusion ; 10 so no energy needed for active transport ; 11 idea that it is good if RBCs do not use up the oxygen they transport ; 12 AVP ;

Question 317 marks

Question

(a) (i) Frogs are classified as amphibians. State two features of amphibians that distinguish them from all other vertebrates. 1 …… 2 …… [2] (ii) Fig. 3.1 is a photograph of a cross-section of a frog’s eye. G H Fig. 3.1 Identify the structures labelled G and H in Fig. 3.1. G …… H …… [2] (b) Fig. 3.2 is a diagram of a rod cell and a cone cell from a human eye. rod cell synaptic endings M K cone cell L mitochondrion Fig. 3.2 (i) Identify cell structures K, L and M in Fig. 3.2. K …… L …… M …… [3] (ii) State the names of the two parts of the mammalian central nervous system. 1 …… 2 …… [1] (c) Fig. 3.3 is a graph showing the distribution of rod cells and cone cells across the retina in a human eye. Key cone cells rod cells number of receptors distance across the retina Fig. 3.3 (i) On Fig. 3.3 draw: • the letter P to show the location of the fovea • the letter Q to show the location of the blind spot. [2] (ii) Describe and explain the distribution of rod cells and cone cells shown in Fig. 3.3. …… [5] (iii) Some mammals are nocturnal which means they are active at night and sleep during the day. Suggest how the number and distribution of rod cells and cone cells across the retina of a nocturnal mammal would differ from a human retina. …… [2] [Total: 17]

Mark scheme

3(a)(i) any two from: 2 eggs laid in / larvae live in, water and adults live on land / AW ; two stage life cycle / AW ; gas exchange occurs through skin (and lungs) ; larva have gills and adults have lungs ; moist skin (described) ; AVP ; 3(a)(ii) G cornea ; 2 H lens ; 3(b)(i) K (cell) membrane ; 3 L cytoplasm ; M nucleus ; 3(b)(ii) brain and spinal cord ; 1 either order 3(c)(i) P draw on the graph in the fovea (area on the graph where there is the 2 highest number of cone cells and no rod cells) ; Q draw on the graph in the blind spot (area on the graph where there are no cone cells or rod cells) ; 3(c)(ii) any five from: 5 describe: 1 more rod cells than cone cells ; 2 (number of) cone cells peak, in the middle / at the fovea ; 3 there are no rod cells where the number of cone cells is highest ; 4 ref. to uneven distribution of rod cells, either side of the, middle / fovea ; 5 no rod cells and no cone cells at blind spot ; explanation: 6 light absorbed (by a pigment) ; 7 rods detect low light (intensity) ; 8 (rods) do not detect colour ; 9 (rods) provide night vision / AW ; 10 (cones) detect high light (intensity) ; 11 (cones) detect colour ; 12 any detail, e.g. three different types of cone ; 13 (no rods and cones at blind spot) because of optic nerve ; 3(c)(iii) more rods present and no / fewer cones present ; 2 A more rods than cones rods at the fovea / rods mainly at periphery ; A more rods in the middle

Question 410 marks

Question

Mitosis and meiosis are both important processes for life. (a) Complete the sentences about mitosis and meiosis. Mitosis is a type of nuclear division which produces genetically identical cells. It is important for growth, …… of tissues and …… reproduction. Just before mitosis the chromosomes are replicated and then the chromosomes …… so that the chromosome number is maintained in each daughter cell. Meiosis is another type of nuclear division that is involved in the production of gametes. The chromosome number is halved from …… to haploid resulting in genetically different cells. The fusion of the nuclei of two gametes formed by meiosis forms a …… . This process is known as …… . [6] (b) Mutations are a source of genetic variation in a population. (i) Describe what is meant by a gene mutation. …… [2] (ii) State two examples of how mutation rates can be increased. 1 …… 2 …… [2] [Total: 10]

Mark scheme

4(a) repair ; 6 asexual ; separate ; diploid ; zygote ; fertilisation ; 4(b)(i) random ; 2 change in the base sequence of DNA ; 4(b)(ii) ionising radiation ; 2 (named) chemicals ; AVP ;

Question 511 marks

Question

Fig. 5.1 shows the changes in the percentage of the total global fish stocks that are overfished and those that are sustainable. 100 90 80 70 60 Key percentage of the total sustainable global fish 50 overfished stocks 40 30 20 10 0 1975 1980 1985 1990 1995 2000 2005 2010 2015 2020 year Fig. 5.1 (a) Use the information in Fig. 5.1 to: (i) State the percentage of fish stocks that were sustainable in 2020. …… % [1] (ii) State which five-year period had the greatest increase in sustainable fish populations. …… [1] (b) Overfishing is one reason why populations of fish decline. Explain the risks to a species if its population size decreases. …… [3] (c) Describe and explain how fish stocks can be managed sustainably and how overfishing can be prevented through conservation. …… [6] [Total: 11]

Mark scheme

5(a)(i) 66 (%) ; 1 5(a)(ii) 1985 to 1990 ; 1 5(b) any three from: 3 reduction in genetic variation / reduced gene pool ; inbreeding ; idea of an increase in the frequency of recessive alleles ; (described) consequence of having too many recessive alleles ; risk of extinction ; idea of unable to find mates / AW ; AVP ; 5(c) any six from: 6 1 education / awareness ; 2 monitoring the populations ; 3 ref. to net type ; 4 ref. to mesh size ; 5 reduced demand (to eat from unsustainable fish stocks) ; 6 alternative sources of fish ; 7 treaties / licenses / fines / laws / making it illegal ; 8 (legal) quotas / restricted catch weight ; 9 no-catch zones / nursery zones / protected areas / Marine Protected Areas / AW ; 10 fish farms ; 11 closed fishing season / AW ; 12 restocking / captive breeding and release ; 13&14 AVP ;;

Question 614 marks

Question

(a) Fig. 6.1 is a diagram showing how glucose is used by different organisms. cellulose sucrose starch carbon dioxide alcohol and glucose and water 3 1 carbon dioxide 2 lactic acid Fig. 6.1 (i) State the number or numbers from Fig. 6.1 that identify the processes that: • release the most energy per glucose molecule …… • take place in yeast cells. …… [2] (ii) State the balanced chemical equation for anaerobic respiration in a yeast cell. …… [2] (iii) State the names of two enzymes that are needed to break down starch into glucose in humans. 1 …… 2 …… [2] (iv) State the main use of the molecule cellulose in a plant. …… [1] (v) Sucrose and amino acids are transported around a plant. State the name of: • the process by which sucrose is transported around a plant • the tissue that transports sucrose and amino acids around a plant • the mineral ion that is used to make amino acids. process …… tissue …… mineral ion …… [3] (b) In humans, the build-up of lactic acid creates an oxygen debt. (i) State the body tissue that produces the most lactic acid during vigorous exercise. …… [1] (ii) The oxygen debt needs to be removed after exercise. State how the breathing and circulatory systems act to remove the oxygen debt. …… [2] (iii) State the name of the organ which breaks down lactic acid. …… [1] [Total: 14]

Mark scheme

6(a)(i) 3; 2 1 and 3 ; 6(a)(ii) C6H12O6 → 2C2H5OH + 2CO2 ;; 2 MP1 correct formulae MP2 correct balancing (of correct formulae) 6(a)(iii) amylase ; 2 either order maltase ; 6(a)(iv) (to build) cell walls / provide support ; 1 6(a)(v) translocation ; 3 phloem ; nitrate(s) ; 6(b)(i) muscle ; 1 6(b)(ii) any two from: 2 continuation of deeper breathing / faster breathing / AW ; continuation of fast heart rate / AW ; idea of delivering oxygen for the breakdown of lactic acid / delivering lactic acid to the liver to be broken down ; 6(b)(iii) liver ; 1

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Where can I find the 0610/41 October/November 2023 mark scheme?

On this page, free: the mark scheme for IGCSE Biology 0610/41, October/November 2023 (0610_w23_ms_41), and the question paper (0610_w23_qp_41), to read or download, with each question's marking points written out underneath.

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Biology 0610/41 for October/November 2023 is out of 80 marks, with 1 hour 15 minutes to answer it, across 6 questions.

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Yes. Upload your answers to 0610/41/O/N/23 as a PDF or photos, and CIE Buddy marks every question against this paper's official mark scheme, using Cambridge's marking rules. You get your score, each lost mark explained on your own script, and the topics to revise. It's a guide, not an official Cambridge grade.