Biology 0610/33 October/November 2025: question paper and mark scheme
Cambridge IGCSE Biology (0610), Paper 3 Theory (Core), October/November 2025. Read both free below, or download them. Done the paper? Get it marked by AI against this mark scheme.
(a) Enzymes are involved in all metabolic reactions.
The box on the left contains the word ‘Enzymes’.
The boxes on the right contain some sentence endings.
Draw lines to make three correct sentences about enzymes.
all have an optimum temperature of 20 °C.
are biological catalysts.
are carbohydrates.
Enzymes are changed by reactions.
are found in plant cells.
increase the rate of reactions.
[3]
(b) State the name of the substrate that protease enzymes act on and the name of the products formed.
substrate ……
products ……
[2]
* 0000800000003 * DFD
3
(c) Fig. 1.1 shows the activity of a protease enzyme at different pH values.
9
8
7
6 enzyme
5 activity
/ arbitrary units 4
3
2
1
0
7 8 9 10 11 12
pH
Fig. 1.1
Describe the activity of the enzyme shown in Fig. 1.1.
…… [3]
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4
(d) (i) Circle the name of an organ that secretes protease.
gall bladder pancreas rectum salivary gland
[1]
(ii) Circle the name of an organ where protease acts.
large intestine mouth oesophagus small intestine
[1]
(e) A different protease enzyme is found in the stomach.
The stomach contains hydrochloric acid.
Describe two functions of hydrochloric acid in the stomach.
1 ……
2 ……
[2]
(f) The stomach is also involved in physical digestion.
Describe the function of the stomach in physical digestion.
…… [1]
[Total: 13]
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5
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6
Mark scheme
1(a) Enzymes are biological catalysts ; 3 boxes 2, 5 and 6
Enzymes are found in plant cells ; R each additional line
Enzymes increase the rate of reactions ;
1(b) substrate: protein ; 2
products: amino acids ;
1(c) any three from: 3
activity of enzyme increases and decreases ;
maximum activity at / optimum at, pH9 ;
activity has a steeper increase from pH8-9 AW / activity has a steeper
decrease from pH9–10 AW ;
zero activity at pH12 ;
AVP ; e.g. data quote with units
1(d)(i) pancreas circled ; 1 R each additional circle
1(d)(ii) small intestine circled ; 1 R each additional circle
1(e) kills, microorganisms / bacteria / pathogens / AW ; 2
provides optimum pH for enzymes (activity) ;
1(f) any one from: 1
churn / contract to mix, (food) ;
breaks food into smaller pieces ;
(a) Fig. 2.1 shows a diagram of a cell found in the lungs of a human.
D
A
C
B
Fig. 2.1
(i) State the names of structures A and B in Fig. 2.1.
A ……
B ……
[2]
(ii) State the functions of structures C and D in Fig. 2.1.
C ……
D ……
[2]
(b) (i) State the name of the structures that form the gas exchange surface in the lungs.
…… [1]
(ii) State the name of the gas which is excreted by the lungs.
…… [1]
* 0000800000007 * DFD
7
(c) (i) Urea is excreted by the body.
Table 2.1 shows parts of the body that urea passes through during excretion.
The structures are not in the correct order.
Table 2.1
A bladder
B blood
C kidney
D ureter
E urethra
Identify the order of parts of the body that urea passes through during excretion.
Write the letters from Table 2.1 in the correct order, in the boxes provided.
One has been done for you.
B
[2]
(ii) State the names of two other substances that are excreted by the kidneys.
…… [2]
[Total: 10]
* 0000800000008 * DFD
8
Mark scheme
2(a)(i) A (cell) membrane ; 2
B cytoplasm ;
2(a)(ii) C contains genetic information AW / controls (activities of) the cell ; 2
D site of (aerobic) respiration / release of energy ;
2(b)(i) alveoli /alveolus ; 1
2(b)(ii) carbon dioxide ; 1 A water vapour
2(c)(i) B C D A E 2 one mark for C at the beginning AND E at
the end
one mark for D before A
2(c)(ii) (excess) ions ; 2
(excess) water ;
(a) Complete the sentences about transpiration.
Transpiration is the loss of water vapour from leaves.
Water evaporates from the surfaces of the …… cells
into the …… spaces.
Water vapour moves out of the leaves through the ……
by the process of …… .
[4]
(b) A student investigated the effect of temperature on the rate of transpiration in a leafy shoot, using the apparatus shown in Fig. 3.1.
leafy shoot reservoir ruler
water capillary air tube bubble reservoir
Fig. 3.1
The rate of transpiration was estimated by measuring the distance moved by the air bubble every 3 minutes.
This was repeated at six different temperatures.
The results are shown in Table 3.1.
Table 3.1
temperature distance moved by the air rate of transpiration
/ °C bubble in 3 minutes / mm / mm per minute
20 18 6
25 45
30 54 18
35 66 22
40 69 23
45 69 23
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(i) Using the data in Table 3.1, calculate the rate of transpiration at 25 °C.
…… mm per minute [1]
(ii) The list shows six conclusions.
Tick () three conclusions for the data shown in Table 3.1.
As temperature increases, the distance moved by the air bubble decreases.
As temperature increases, the rate of transpiration decreases.
As temperature increases, the rate of transpiration increases and then remains constant.
From 20 °C to 30 °C, the rate of transpiration triples.
From 20 °C to 45 °C, the rate of transpiration increases by 17 mm per minute.
The maximum rate of transpiration was 22 mm per minute.
[3]
[Total: 8]
* 0000800000010 * DFD
10
Mark scheme
3(a) (spongy) mesophyll ; 4
air ;
stomata ; A guard cells
diffusion ;
3(b)(i) 15 (mm per minute) ; 1
3(b)(ii) 3 boxes 3, 4 and 5
As temperature increases, the rate of transpiration increases and then R each additional tick
remains constant ;
From 20 ⁰C to 30 ⁰C the rate of transpiration triples ;
From 20 ⁰C to 45 ⁰C the rate of transpiration increases by
17 mm per minute ;
(a) Describe what is meant by the term fertilisation.
…… [2]
(b) Fig. 4.1 is a diagram of a sperm cell.
H G
Fig. 4.1
(i) Complete Table 4.1 by stating the names and functions of the parts labelled G and H in Fig. 4.1.
Table 4.1
letter in name function
Fig. 4.1
G
H
[4]
(ii) State the name of the organ that produces sperm.
…… [1]
(iii) State the sex chromosomes in a male human.
…… [1]
(iv) State the probability that a human baby will be a boy.
…… [1]
[Total: 9]
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11
Mark scheme
4(a) fusion of the nuclei ; 2
of / from, gametes ;
4(b)(i) 4
letter in
name function
Fig. 4.1
contains / stores / releases, enzymes
G acrosome ;
(needed to penetrate egg) ;
(for) movement / swimming
H flagellum ;
/ propulsion ;
4(b)(ii) testis / testes ; 1
4(b)(iii) XY ; 1
4(b)(iv) 0.5 ; 1 A 50%
Humans have increased food production over time.
(a) Fig. 5.1 shows how rice production increased from 1960 to 2010 in one country.
500
450
400
350
300 rice production
/ million tonnes 250
200
150
100
50
0
1960 1965 1970 1975 1980 1985 1990 1995 2000 2005 2010 year
Fig. 5.1
(i) Using the information in Fig. 5.1, state the five‑year period which shows the greatest increase in rice production.
from …… to …… [1]
(ii) Using the information in Fig. 5.1, calculate the percentage increase in rice production from 1960 to 1990.
Give your answer to the nearest whole number.
Space for working.
……%
[3]
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12
(b) State three methods that humans use to increase crop plant production.
1 ……
2 ……
3 ……
[3]
(c) Fig. 5.2 is a photograph of intensive farming of sheep.
Fig. 5.2
(i) Describe the advantages of intensive farming of livestock.
…… [3]
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13
(ii) One of the disadvantages of intensive farming of livestock is that untreated sewage from the animals can enter aquatic ecosystems.
State two effects of untreated sewage on aquatic ecosystems.
1 ……
2 ……
[2]
[Total: 12]
* 0000800000014 * DFD
14
Mark scheme
5(a)(i) 1980 to 1985 ; 1
5(a)(ii) 133 (%) ; 3 MP1 correct readings from graph
MP2 correct value calculated to any
number of decimal places i.e. ((200 ÷ 150)
× 100 = )133.33 recurring
MP3 evidence of correct rounding to a
whole number
ecf from previous step
5(b) any three from: 3
fertiliser use ;
herbicide use ;
insecticide use ;
selective breeding ;
use of agricultural machinery ;
monoculture ;
genetic modification ;
AVP ; e.g. clear more land / irrigation
5(c)(i) any three from: 3
less energy used, for movement / maintain body temperature ;
(so) more energy used for growth / AW ;
increased yield / more product / more people able to be fed ;
more profit / cheaper product ;
less land needed (for livestock) / more land available for other uses ;
idea of easier to care for animals ;
use, technology / machinery, so less manual labour needed AW ;
protection from predators ;
AVP ;
5(c)(ii) any two from: 2
pollution ;
fish / other aquatic life, die (due to lack of oxygen) ;
decreased biodiversity ;
food chains / webs, are affected / described ;
spread / cause, of disease / pathogen ;
habitat destruction ;
AVP ; e.g. less oxygen in the water
(a) Yoghurt can be made by adding the bacteria Lactobacillus bulgaricus to milk.
(i) State the genus name for these bacteria.
…… [1]
(ii) State two reasons why bacteria are useful in biotechnology processes such as making yoghurt.
1 ……
2 ……
[2]
(b) Fig. 6.1 shows the nutritional information for 100 g of a type of yoghurt.
carbohydrate 4.7 g
fat 3.3 g
fibre 0.0 g
protein 3.5 g
Fig. 6.1
(i) A person wants to eat 45 g of protein.
The person ate 200 g of yoghurt.
Using the information in Fig. 6.1, calculate the mass of protein the person needs to eat,
in addition to the yoghurt, to reach 45 g of protein.
mass of protein in 200 g of yoghurt …… g
mass of additional protein the person needs to eat …… g
[2]
(ii) State the importance of fats in the diet.
…… [1]
* 0000800000015 * DFD
15
(iii) Yoghurt does not contain fibre.
State one principal dietary source of fibre.
…… [1]
(c) Yeast is another microorganism that is used in biotechnology.
Anaerobic respiration in yeast is used in bread‑making.
(i) State the word equation for anaerobic respiration in yeast.
…… [2]
(ii) Describe the role of anaerobic respiration in yeast during bread‑making.
…… [1]
(iii) State one other use of yeast in biotechnology.
…… [1]
[Total: 11]
* 0000800000016 * DFD
16
Mark scheme
6(a)(i) Lactobacillus ; 1
6(a)(ii) any two from: 2
rapid reproduction rate ;
ability to make complex molecules ;
AVP ; e.g.no / low, ethical concerns
6(b)(i) 7 (g) ; 2
38 (g) ;
6(b)(ii) (stores or source, of) energy / protects organs / insulation / AVP ; 1
6(b)(iii) whole grain products / fruit / vegetables / beans / nuts / AVP ; 1
6(c)(i) glucose → ; 2
alcohol + carbon dioxide ; A products in either order
A ethanol for alcohol
6(c)(ii) (carbon dioxide gas) makes dough rise / AW ; 1
6(c)(iii) (production of) biofuel / AVP ; 1 e.g. brewing / fermentation
(a) Fig. 7.1 shows a plant in a light‑proof box.
light-proof box plant shoot
plant pot
plant roots
Fig. 7.1
The plant was placed on its side in the light‑proof box.
(i) Complete Fig. 7.2 by drawing the expected appearance of the shoot and roots of the plant after a week.
light-proof box
plant pot
plant
Fig. 7.2
[2]
(ii) State the name of the tropic response shown by the plant in Fig. 7.2.
…… [1]
* 0000800000017 * DFD
17
(b) State the function of a root hair cell, and describe how it is adapted for its function.
function ……
adaptation ……
[4]
[Total: 7]
* 0000800000018 * DFD
18
Mark scheme
7(a)(i) shoot drawn bending upwards ; 2
root drawn bending downwards ;
7(a)(ii) gravitropism ; 1
7(b) any four from: 4
function:
absorption ;
of water ;
of mineral ions ;
adaptation:
large surface area / elongated shape ;
to increase, diffusion / osmosis / active transport ;
(a) Fig. 8.1 is a photograph of a human eye.
S
T
Fig. 8.1
(i) State the name of structure S in Fig. 8.1.
…… [1]
(ii) State the function of structure T in Fig. 8.1.
…… [1]
(b) Eyelash length is a human characteristic controlled by a single gene. People can have either short eyelashes or long eyelashes.
(i) Describe what is meant by the term gene.
…… [2]
(ii) Suggest one reason why eyelash length in humans could be an example of discontinuous variation.
…… [1]
* 0000800000019 * DFD
19
(c) The allele for long eyelashes is represented by the letter E.
The allele for short eyelashes is represented by the letter e.
• The genotype of a male was ee.
• The genotype of a female was Ee.
(i) Table 8.1 shows some terms used to describe these genotypes.
Place ticks () in the boxes in Table 8.1 to show the correct descriptions for
these genotypes.
Table 8.1
homozygous homozygous genotype heterozygous dominant recessive
ee
Ee
[2]
(ii) A male with the genotype ee had a child with a female with the genotype Ee.
Complete the Punnett square to show the:
• gametes of the male and the female
• possible genotypes of the offspring from this cross
• ratio of long eyelashes to short eyelashes in the offspring from this cross.
male
female
The ratio of long eyelashes to short eyelashes in the offspring is …… [3]
[Total: 10]
* 0000800000020 * DFD
20
Mark scheme
8(a)(i) pupil ; 1
8(a)(ii) controls how much light enters the, pupil / eye ; 1
8(b)(i) length of DNA ; 2
that codes for a protein ;
8(b)(ii) any one from: 1
two categories / two phenotypes / no intermediates / AW ;
controlled by, genes / one gene ;
8(c)(i) ee homozygous recessive ticked ; 2 R each additional tick
Ee heterozygous ticked ;
8(c)(ii) male gametes shown as e and e and female gametes shown as E and e ; 3 ecf from previous MP
offspring genotypes shown as Ee and ee ;
(ratio is) 1:1 ; male
e e
E Ee Ee
female
e ee ee
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Biology 0610/33 for October/November 2025 is out of 80 marks, with 1 hour 15 minutes to answer it, across 8 questions.
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