Chemistry 0620/42 February/March 2025: question paper and mark scheme
Cambridge IGCSE Chemistry (0620), Paper 4 Theory (Extended), February/March 2025. Read both free below, or download them. Done the paper? Get it marked by AI against this mark scheme.
Using numbers only, state the:
(a) percentage of oxygen in clean, dry air …… [1]
(b) typical operating temperature, in °C, used in the Haber process …… [1]
(c) number of atoms in a diatomic molecule …… [1]
(d) maximum number of electrons in the second electron shell of an atom …… [1]
(e) number of hydrogen atoms in an alkane with 7 carbon atoms …… [1]
(f) number of particles in one mole, in standard form. …… [1]
[Total: 6]
This question is about ionic compounds.
(a) State what is meant by the term ionic bond.
…… [2]
(b) Potassium sulfide, K2S, is an ionic compound.
Complete the dot-and-cross diagram in Fig. 2.1 of the ions in potassium sulfide.
Show the charges on the ions.
K S K
Fig. 2.1
[3]
(c) Ionic compounds form giant ionic lattices.
(i) Fig. 2.2 shows part of the giant ionic lattice structure of sodium chloride.
Complete the diagram in Fig. 2.2 to show the ions present. Use ‘+’ for sodium ions and ‘–’ for chloride ions. One chloride ion has been completed for you.
–
Fig. 2.2
[2]
(ii) State the name given to any positive ion.
…… [1]
(d) Ionic compounds can be decomposed by the passage of an electric current using inert electrodes.
(i) State the name of this process.
…… [1]
(ii) Write the ionic half-equation for the reaction which takes place at the anode when molten potassium bromide, KBr, is decomposed by the passage of an electric current.
…… [2]
(iii) Name the products and state the observations at the negative and positive electrodes when dilute aqueous potassium bromide, KBr, is decomposed by the passage of an electric current.
product at the negative electrode
observations at the negative electrode
products at the positive electrode
…… and ……
observations at the positive electrode
[5]
[Total: 16]
Mark scheme
2(a) M1 (strong) (electrostatic) attraction between ions 2
M2 ions have opposite charges
2(b) M1 8 dots in third shell of each K 3
M2 6 crosses and 2 dots in third shell of S
M3 ‘+’ charge on each K ion on correct answer line
and ‘2–‘ charge on S ion on correct answer line
2(c)(i) M1 3 correctly positioned positive ions next to given negative 2
M2 all ions correct
2(c)(ii) cation(s) 1
2(d)(i) electrolysis 1
2(d)(ii) 2Br– → Br2 + 2e– 2
M1 any negative Br species losing electron(s)
M2 correct ionic half equation
2(d)(iii) M1 hydrogen 5
M2 bubbles
M3 oxygen M4 water
M5 bubbles
The halogens are a group of elements in the Periodic Table.
Chlorine is a member of this group.
(a) State the group number of the halogens.
…… [1]
(b) State how many halogens there are in this group.
…… [1]
(c) Suggest the identity of the halogen which:
(i) has the highest density
…… [1]
(ii) is the most reactive.
…… [1]
(d) State the name of the negative ions (anions) formed by halogens.
…… [1]
(e) State how many occupied electron shells there are in a bromine atom.
…… [1]
(f) Name the noble gas which has the same electronic configuration as a Br – ion.
…… [1]
(g) Aqueous chlorine, Cl 2, reacts with aqueous potassium iodide, KI.
One of the products formed is iodine, I2.
(i) Complete and balance the ionic equation for the reaction between Cl 2 and I – ions.
State symbols are not required.
Cl 2 + …… I – …… + I2
[2]
(ii) Explain why this reaction is defined as a redox reaction.
Give your answer in terms of electron transfer.
…… [2]
(h) Give the colour and state of iodine at room temperature and pressure.
colour ……
state ……
[2]
[Total: 13]
Carbonyl chloride, COCl 2, is manufactured by reacting carbon monoxide with chlorine.
CO(g) + Cl 2(g) COCl 2(g) ΔH = –105 kJ / mol
The process takes place in a closed system, and an equilibrium is reached.
The conditions for this process are 200 °C and 200 kPa.
(a) Explain what is meant by the term closed system.
…… [1]
(b) State what the symbol ΔH represents.
…… [1]
(c) State how the value of ΔH shows that the forward reaction is exothermic.
…… [1]
(d) Deduce the value of ΔH for the reverse reaction. Include a sign in your answer.
…… [1]
(e) Complete Table 4.1 to show the effect, if any, on the concentration of COCl 2(g) at equilibrium when the following changes to the conditions are applied.
Use only the words increases, decreases or no change.
Table 4.1
effect on the concentration of change to conditions
COCl 2(g) at equilibrium
the temperature is increased
some CO is added
the pressure is increased
a catalyst is added
[4]
(f) The equation for the reaction can be represented as shown in Fig. 4.1.
Cl
C O + Cl Cl C O ΔH = –105 kJ / mol
Cl
Fig. 4.1
Table 4.2 shows some bond energies.
Table 4.2
bond C≡O Cl –Cl C–Cl bond energy in kJ / mol 1075 240 340
Use the bond energies in Table 4.2 and the value of ΔH for the reaction to calculate the bond energy, in kJ / mol, of the C=O bond.
Use the following steps.
• Calculate the energy needed to break the bonds in the reactants.
…… kJ
• Calculate the energy released when the bonds in carbonyl chloride form.
…… kJ
• Calculate the bond energy of the C=O bond.
…… kJ / mol
[3]
(g) Complete the dot-and-cross diagram in Fig. 4.2 of a molecule of carbonyl chloride.
Show outer shell electrons only.
Cl
C O
Cl
Fig. 4.2
[3]
[Total: 14]
Mark scheme
4(a) no reactants or products can enter or leave 1
4(b) enthalpy change (of reaction) 1
4(c) (The value of ΔH is) negative 1
4(d) +105 (kJ / mol) 1
4(e) decreases 4
increases
increases
no change
4(f) M1 Bond energy in breaking bonds 3
= 1075 + 240 = (+) 1315
M2 Bond energy of COCl2 = 1315 – (–105) = 1420
M3 C=O = 1420 – 2 × C–Cl
= 1420 – (2 × 340) = (+) 740
4(g) M1 both single bonding dot and cross pairs correct 3
M2 double C=O bond dot and cross pairs are correct
M3 Complete diagram is correct
Manganese is the element with atomic number 25 in the Periodic Table.
Calcium is the element with atomic number 20 in the Periodic Table.
(a) Complete Table 5.1 to show the number of protons, neutrons and electrons in the 55Mn atom and the 42Ca2+ ion.
Table 5.1
55Mn 42Ca2+
protons
neutrons
electrons
[3]
(b) Manganese forms several oxides. The formulae of some of these oxides are shown.
MnO
Mn2O3
Mn3O4
MnO2
Mn2O7
(i) Suggest why manganese is expected to form coloured oxides.
…… [1]
(ii) State which other property of manganese is shown by the formation of several oxides.
…… [1]
(iii) State the formula of manganese(II) oxide.
…… [1]
(c) Mn3O4 is found in an ore of manganese. Manganese metal can be extracted from Mn3O4 using aluminium as the reducing agent.
(i) Define the term reducing agent.
…… [2]
(ii) Complete the symbol equation by inserting the formula of the missing product and balancing the equation.
…… Mn3O4 + …… Al …… + …… Mn
[2]
(d) MnO2 reacts with dilute hydrochloric acid as shown in the equation.
MnO2 + 4HCl MnCl 2 + 2H2O + Cl 2
(i) Calculate the volume of chlorine gas formed, in cm3, at r.t.p. when excess MnO2 reacts with 50.0 cm3 of 0.200 mol / dm3 HCl .
Use the following steps.
• Calculate the number of moles of HCl used.
…… mol
• Determine the number of moles of Cl 2 formed.
…… mol
•
Calculate the volume of Cl 2 formed.
…… cm3
[3]
(ii) Describe a test for chlorine gas.
test ……
observations ……
[1]
(iii) Explain, in terms of collision theory, why decreasing the temperature decreases the rate of this reaction.
…… [3]
[Total: 17]
Mark scheme
5(a) 3
55Mn 42Ca2+
protons 25 20
neutrons 30 22
electrons 25 18
Each row ✔
5(b)(i) (Mn is a) transition element 1
5(b)(ii) variable oxidation state 1
5(b)(iii) MnO 1
5(c)(i) a substance that reduces another substance and is itself oxidised 2
M1 ‘a substance’ reduces another substance
M2 is itself oxidised
5(c)(ii) 3Mn3O4 + 8Al → 4Al2O3 + 9Mn 2
M1 Al2O3
M2 correct equation
5(d)(i) M1 50 × 0.200÷1000 = 0.01(00) 3
M2 0.01÷4 = 0.0025(0) / 2.5(0) × 10–3
M3 = 0.0025 × 24000 = 60(.0)
5(d)(ii) (damp) litmus (paper) 1
and
is bleached / goes white
5(d)(iii) M1 kinetic energy of particles decreases
M2 frequency of collisions between particles decreases
M3 lower percentage / proportion / fraction of collisions / particles have energy greater than / equal to activation energy
OR
Fewer of the collisions / particles have energy greater than / equal to activation energy
The structural formulae of two compounds, A and B, are shown.
A B
CH2=CHCH3 CH3CH=CHCH3
A and B are members of the same homologous series.
(a) Give two reasons why the structural formulae of A and B show they are members of the same homologous series.
1 ……
2 ……
[2]
(b) Explain why A and B are both hydrocarbons.
…… [1]
(c) Write the symbol equation for the complete combustion of A.
…… [2]
(d) Deduce the empirical formula of A.
…… [1]
(e) Name compound B.
…… [1]
(f) A structural isomer of B is a member of the same homologous series.
Draw the displayed formula of this structural isomer of B.
[1]
(g) Compound B reacts with aqueous bromine at room temperature to form product C.
The equation is shown.
B C
CH3CH=CHCH3 + Br2 CH3CHBrCHBrCH3
(i) State why this is an addition reaction.
…… [1]
(ii) Describe the colour change in aqueous bromine during this reaction.
from …… to …… [1]
(iii) Name product C.
…… [1]
(h) Under certain conditions, one mole of B reacts with oxygen to form two moles of carboxylic acid D.
Carboxylic acid D has two carbon atoms.
(i) Draw the displayed formula of carboxylic acid D.
[1]
(ii) Name carboxylic acid D.
…… [1]
(iii) Complete the symbol equation for this reaction.
CH3CH=CHCH3 + …… ……
[1]
[Total: 14]
The Periodic Table of Elements
Group
I II III IV V VI VII VIII
1 2
H He hydrogen helium
Key 1 4
3 4 atomic number 5 6 7 8 9 10
Li Be atomic symbol B C N O F Ne lithium beryllium name boron carbon nitrogen oxygen fluorine neon
7 9 relative atomic mass 11 12 14 16 19 20
11 12 13 14 15 16 17 18
Na Mg Al Si P S Cl Ar sodium magnesium aluminium silicon phosphorus sulfur chlorine argon
23 24 27 28 31 32 35.5 40
19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36
K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr potassium calcium scandium titanium vanadium chromium manganese iron cobalt nickel copper zinc gallium germanium arsenic selenium bromine krypton
39 40 45 48 51 52 55 56 59 59 64 65 70 73 75 79 80 84
37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54
Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe rubidium strontium yttrium zirconium niobium molybdenum technetium ruthenium rhodium palladium silver cadmium indium tin antimony tellurium iodine xenon
12
85 88 89 91 93 96 – 101 103 106 108 112 115 119 122 128 127 131
55 56 57–71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86
lanthanoids
Cs Ba Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po At Rn caesium barium hafnium tantalum tungsten rhenium osmium iridium platinum gold mercury thallium lead bismuth polonium astatine radon
133 137 178 181 184 186 190 192 195 197 201 204 207 209 – – –
87 88 89–103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 actinoids
Fr Ra Rf Db Sg Bh Hs Mt Ds Rg Cn Nh Fl Mc Lv Ts Og francium radium rutherfordium dubnium seaborgium bohrium hassium meitnerium darmstadtium roentgenium copernicium nihonium flerovium moscovium livermorium tennessine oganesson
– – – – – – – – – – – – – – – – –
57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 lanthanoids La Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu lanthanum cerium praseodymium neodymium promethium samarium europium gadolinium terbium dysprosium holmium erbium thulium ytterbium lutetium
139 140 141 144 – 150 152 157 159 163 165 167 169 173 175
89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 actinoids Ac Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No Lr actinium thorium protactinium uranium neptunium plutonium americium curium berkelium californium einsteinium fermium mendelevium nobelium lawrencium
– 232 231 238 – – – – – – – – – – –
The volume of one mole of any gas is 24 dm3 at room temperature and pressure (r.t.p.).
Mark scheme
6(a) M1 (have a) general formula of CnH2n 2
M2 (have a) C=C functional group
6(b) compounds made of C and H only 1
6(c) 2C3H6 + 9O2 → 6CO2 + 6H2O 2
M1 CO2 + H2O as only products
M2 correct equation
6(d) CH2 1
6(e) but-2-ene 1
6(f) displayed formula of but-1-ene 1
6(g)(i) only one product is formed 1
6(g)(ii) orange to colourless 1
6(g)(iii) 2,3-dibromobutane 1
6(h)(i) displayed formula of ethanoic acid 1
6(h)(ii) ethanoic acid 1
6(h)(iii) CH3CH=CHCH3 + 2O2 → 2CH3COOH 1
Checked your answers against these? Let AI mark the whole paper, on your own working.
Examiners follow the generic marking principles at the front of the scheme, then each question's points: method (M), accuracy (A) and independent (B) marks, error carried forward where the scheme allows it, and positive marking, so you're credited for what you got right.
Check your answers against it
Done this paper? Upload your script and CIE Buddy's AI marker marks it question by question against this exact scheme, puts the ticks on your own working and says what each lost mark needed.
Where can I find the 0620/42 February/March 2025 mark scheme?+
On this page, free: the mark scheme for IGCSE Chemistry 0620/42, February/March 2025 (0620_m25_ms_42), and the question paper (0620_m25_qp_42), to read or download, with each question's marking points written out underneath.
How many marks is 0620/42 out of?+
Chemistry 0620/42 for February/March 2025 is out of 80 marks, with 1 hour 15 minutes to answer it, across 6 questions.
Can I get my 0620/42 answers marked?+
Yes. Upload your answers to 0620/42/F/M/25 as a PDF or photos, and CIE Buddy marks every question against this paper's official mark scheme, using Cambridge's marking rules. You get your score, each lost mark explained on your own script, and the topics to revise. It's a guide, not an official Cambridge grade.