Chemistry 0620/43 May/June 2023: question paper and mark scheme
Cambridge IGCSE Chemistry (0620), Paper 4 Theory (Extended), May/June 2023. Read both free below, or download them. Done the paper? Get it marked by AI against this mark scheme.
Some symbol equations and word equations, A to J, are shown.
A H+ + OH– → H2O
B Cr3+ + 3OH– → Cr(OH)3
C methane + chlorine → chloromethane + hydrogen chloride
D propene + bromine → 1,2-dibromopropane
E C10H22 → C8H18 + C2H4
F chlorine + aqueous potassium bromide → bromine + aqueous potassium chloride
G methane + oxygen → carbon monoxide + water
H C2H5COOH + CH3OH → C2H5COOCH3 + H2O
I hydrogen + oxygen → water
J 6CO2 + 6H2O → C6H12O6 + 6O2
Use the equations to answer the questions that follow.
Each equation may be used once, more than once, or not at all.
Give the letter, A to J, for the equation which represents:
[Total: 6]
Question 2 starts on the next page.
Mark scheme
1(a) J 1
1(b) D 1
1(c) B 1
1(d) G 1
1(e) F 1
1(f) C 1
(a) The symbols of the elements in Period 3 of the Periodic Table are shown.
Na Mg Al Si P S Cl Ar
Use the symbols of the elements in Period 3 to answer the questions that follow.
Each symbol may be used once, more than once, or not at all.
Give the symbol of the element that:
(vi) has an oxidation number of –1 when it forms a compound with hydrogen.
. …… [1]
(b) The relative atomic masses of elements can be calculated from the relative masses of isotopes and their percentage abundances.
(i) Identify the isotope to which all relative masses are compared.
. …… [1]
(ii) Table 2.1 shows the relative masses and the percentage abundances of the two isotopes in a sample of magnesium.
Table 2.1
relative mass of isotope percentage abundance of isotope
24 85
26 15
Calculate the relative atomic mass of magnesium to one decimal place.
relative atomic mass = …… [2]
(c) An ion contains 10 electrons, 13 protons and 14 neutrons.
(i) State the nucleon number of the ion.
. …… [1]
(ii) Identify the element that forms this ion.
. …… [1]
[Total: 11]
Mark scheme
2(a)(i) Al 1
2(a)(ii) Ar 1
2(a)(iii) Cl 1
2(a)(iv) Al 1
2(a)(v) S 1
2(a)(vi) Cl 1
2(b)(i) 12C 1
2(b)(ii) M1 24 × 85(%) + 26 × 15(%) 2
M2 2430 / 100 = 24.3
2(c)(i) 27 1
2(c)(ii) Aluminium / Al 1
Magnesium forms ionic compounds.
(a) Magnesium reacts with fluorine to form the ionic compound magnesium fluoride.
The electronic configurations of an atom of magnesium and an atom of fluorine are shown in
Fig. 3.1.
magnesium atom fluorine atom
Mg F
Fig. 3.1
(i) Ions are formed by the transfer of electrons from magnesium atoms to fluorine atoms.
Complete the dot-and-cross diagrams in Fig. 3.2 to show the electronic configurations of one magnesium ion and one fluoride ion. Show the charges on the ions.
magnesium ion fluoride ion
Mg F
Fig. 3.2
[3]
(ii) Deduce the formula of magnesium fluoride.
. …… [1]
(iii) When solid magnesium fluoride is dissolved in water it forms a solution that conducts electricity.
State one other change that can be made to solid magnesium fluoride to allow it to conduct electricity.
. …… [1]
(b) Silicon tetrachloride, SiCl 4, and silicon(IV) oxide, SiO2, are covalent compounds.
Complete the dot-and-cross diagram in Fig. 3.3 to show the electronic configuration in a molecule of silicon tetrachloride. Show outer shell electrons only.
Cl
Cl Si Cl
Cl
Fig. 3.3
[2]
(c) The melting points of silicon tetrachloride and silicon(IV) oxide are shown in Table 3.1.
Table 3.1
melting point / °C silicon tetrachloride –69 silicon(IV) oxide 1710
(i) Silicon tetrachloride has a low melting point because it has weak forces of attraction between particles.
Name the type of particles that are held together by these weak forces of attraction.
. …… [1]
(ii) Explain, in terms of structure and bonding, why silicon(IV) oxide has a high melting point.
. ……
. ……
. ……
. …… [2]
[Total: 10]
Mark scheme
3(a)(i) M1 eight crosses in second shell of Mg 3
M2 7 dots and 1 cross in second shell of F
M3 ‘2+’ charge on Mg ion on correct answer line
and ‘–‘ charge on F ion on correct answer line
3(a)(ii) MgF2 1
3(a)(iii) melting 1
3(b) M1 4 dot and cross single bonds 2
M2 3 pairs of non-bonding e on each Cl and no non-bonding e on Si
3(c)(i) molecule(s) 1
3(c)(ii) M1 covalent bonds 2
M2 strong bonds
and
giant (covalent) structure
Hydrogen is produced by the reaction between zinc and dilute sulfuric acid, H2SO4.
Zn(s) + H2SO4(aq) → ZnSO4(aq) + H2(g)
(a) A student carries out an experiment using excess zinc and dilute sulfuric acid.
The student measures the volume of hydrogen produced at regular time intervals using the apparatus shown in Fig. 4.1.
Lumps of zinc are used.
gas syringe
dilute sulfuric acid lumps of zinc
Fig. 4.1
The rate of reaction decreases as the reaction progresses. The rate eventually becomes zero.
(i) Explain why the rate of reaction decreases as the reaction progresses.
. ……
. …… [1]
(ii) Explain why the rate of reaction eventually becomes zero.
. ……
. …… [1]
(b) The experiment is repeated using powdered zinc instead of lumps of zinc.
All other conditions remain the same.
Explain, in terms of collision theory, why the rate of reaction increases if powdered zinc is used.
. ……
. ……
. …… [2]
(c) The equation for the reaction is shown.
Zn(s) + H2SO4(aq) → ZnSO4(aq) + H2(g)
25.0 cm3 of 2.00 mol / dm3 H2SO4(aq) is added to excess zinc.
Calculate the volume of H2 formed at room temperature and pressure (r.t.p.). The volume of one mole of any gas is 24 dm3 at r.t.p.
Use the following steps.
● Calculate the number of moles of H2SO4 used.
…… mol
● Deduce the number of moles of H2 produced.
…… mol
● Calculate the volume of H2 formed at r.t.p.
…… dm3
[3]
(d) Hydrogen can also be produced by the reaction of zinc with dilute hydrochloric acid.
(i) Write a symbol equation for this reaction.
. …… [2]
(ii) State the test for hydrogen gas.
test . ……
positive result . ……
[1]
[Total: 10]
Mark scheme
4(a)(i) concentration (of sulfuric acid particles) decreases 1
OR
frequency of collisions between particles decreases
4(a)(ii) all the (sulfuric) acid has reacted 1
4(b) M1 greater surface area (of zinc) 2
M2 frequency of collisions between (zinc and acid) particles increases
4(c) M1 mol H2SO4 = 2.00 x 25.0/1000 = 0.05(00) 3
M2 mol H2 = M1 = 0.05(00)
M3 vol H2 = M2 × 24 = 1.2(0)
4(d)(i) Zn + 2HCl → ZnCl2 + H2 2
M1 ZnCl2
M2 equation correct
4(d)(ii) lighted splint and (squeaky) pop 1
This question is about electricity and chemical reactions.
(a) Aqueous copper(II) sulfate is an electrolyte.
The electrolysis of aqueous copper(II) sulfate using inert electrodes forms:
● copper at the cathode
● oxygen at the anode.
(i) State what is meant by the term electrolyte.
. ……
. …… [2]
(ii) State the term given to the Roman numeral, (II), in the name copper(II) sulfate.
. …… [1]
(iii) State what happens to the colour of the aqueous copper(II) sulfate as this electrolysis progresses.
. …… [1]
(iv) Write an ionic half-equation for the formation of copper at the cathode.
. …… [2]
(v) Give the formula of the ion that forms oxygen at the anode.
. …… [1]
(b) The electrolysis of aqueous copper(II) sulfate is repeated using copper electrodes.
State what happens to the anode.
. …… [1]
(c) Spoons can be electroplated with silver.
(i) Name the substances used as:
the anode (positive electrode) ……
the cathode (negative electrode) ……
the electrolyte. ……
[3]
(ii) State two reasons why spoons are electroplated.
1 . ……
2 . ……
[2]
(d) Hydrogen–oxygen fuel cells can be used to produce electricity to power cars.
Petrol produces carbon dioxide and carbon monoxide when it powers cars.
(i) State one adverse effect of carbon dioxide and carbon monoxide.
carbon dioxide ……
carbon monoxide ……
[2]
(ii) State one disadvantage, other than cost, of using hydrogen–oxygen fuel cells to power cars compared to using petrol.
. …… [1]
[Total: 16]
Mark scheme
5(a)(i) M1 ionic compound 2
M2 molten and / or aqueous
5(a)(ii) oxidation number (of copper) 1
5(a)(iii) fades / (becomes) colourless 1
5(a)(iv) Cu2+ + 2e → Cu 2
M1 Cu2+ and (any number of) e on left hand side
M2 equation correct
5(a)(v) OH– 1
5(b) anode dissolves 1
5(c)(i) M1 silver 3
M2 spoon
M3 (aqueous or solution) of silver nitrate
5(c)(ii) M1 prevent corrosion 2
M2 improve appearance
5(d)(i) M1 carbon dioxide: (increased) global warming 2
M2 carbon monoxide: toxic
5(d)(ii) needs high pressure to store hydrogen 1
This question is about nitrogen and compounds of nitrogen.
(a)
Ammonia is manufactured by the reaction between nitrogen and hydrogen in the Haber process.
The equation is shown.
N2(g) + 3H2(g) 2NH3(g)
(i) State the source of nitrogen for the Haber process.
. …… [1]
(ii) State the source of hydrogen for the Haber process.
. …… [1]
(iii) State the typical conditions used in the Haber process.
temperature …… °C
pressure . …… atm
[2]
(iv) Name the catalyst used in the Haber process.
. …… [1]
(v) State what is meant by the term catalyst.
. ……
. …… [2]
(b) Ammonia is converted into nitric acid.
(i) The first stage is the conversion of ammonia into nitrogen monoxide, NO.
The equation is shown.
4NH3(g) + 5O2(g) 4NO(g) + 6H2O(g)
The reaction is carried out at a temperature of 900 °C and a pressure of 7 atm.
The forward reaction is exothermic.
Using explanations that do not involve cost:
● explain why a temperature less than 900 °C is not used
. ……
● explain why a pressure greater than 7 atm is not used.
. ……
[2]
(ii) In the second stage, nitrogen monoxide reacts with water and oxygen to produce nitric acid.
Balance the symbol equation for the reaction.
……NO + ……O2 + ……H2O → ……HNO3[1]
(c) A student makes aqueous copper(II) nitrate by adding an excess of solid copper(II) carbonate to dilute nitric acid.
(i) Write the symbol equation for this reaction.
. …… [2]
(ii) State two observations that indicate the copper(II) carbonate is in excess.
1 . ……
2 . ……
[2]
(iii) Name one compound, other than copper(II) carbonate, that can be added to dilute nitric acid to produce aqueous copper(II) nitrate.
. …… [1]
[Total: 15]
Mark scheme
6(a)(i) air 1
6(a)(ii) methane 1
6(a)(iii) M1 450 (°C) 2
M2 200 (atm)
6(a)(iv) iron 1
6(a)(v) M1 (a substance which) increases the rate of a reaction 2
M2 remains unchanged at the end of the reaction
6(b)(i) temperature change: 2
M1 low(er) rate (of reaction)
pressure change:
M2 (position of) equilibrium shifts to the left hand side/ towards reactants
6(b)(ii) 4NO + 3O2 + 2H2O →.4HNO3 1
6(c)(i) CuCO3 + 2HNO3 → Cu(NO3)2 + CO2 + H2O 2
M1 Cu(NO3)2
M2 correct equation
6(c)(ii) M1 undissolved solid 2
M2 effervescence stops on addition of more copper(II) carbonate
6(d)(iii) copper(II) oxide or 1
copper(II) hydroxide
This question is about organic compounds.
(a) Propane and chlorine react at room temperature. An equation for the reaction is shown.
C3H8 + Cl 2 → C3H7Cl + HCl
(i) State the condition required for this reaction.
. …… [1]
(ii) Draw the displayed formulae of two structural isomers with the formula C3H7Cl.
[2]
(b) Alkenes are a homologous series of hydrocarbons.
(i) State two characteristics that all members of the same homologous series have in common.
1 . ……
2 . ……
[2]
(ii) Addition polymers are made from alkenes.
Complete Fig. 7.1 to show one repeat unit of the addition polymer formed from but-2-ene.
C C
Fig. 7.1
[2]
(c) A repeat unit of a condensation polymer is shown in Fig. 7.2.
The polymer is made from two monomers.
O O
C CH2 C O CH2CH2 O
Fig. 7.2
(i) Draw the structures of the monomers used to produce the polymer in Fig. 7.2.
[2]
(ii) Name the type of condensation polymer in Fig. 7.2.
. …… [1]
(iii) Name the two homologous series to which the monomers in (i) belong.
1 . ……
2 . ……
[2]
[Total: 12]
The Periodic Table of Elements
Group
I II III IV V VI VII VIII
1 2
H He hydrogen helium
Key 1 4
3 4 atomic number 5 6 7 8 9 10
Li Be atomic symbol B C N O F Ne lithium beryllium name boron carbon nitrogen oxygen fluorine neon
7 9 relative atomic mass 11 12 14 16 19 20
11 12 13 14 15 16 17 18
Na Mg Al Si P S Cl Ar sodium magnesium aluminium silicon phosphorus sulfur chlorine argon
23 24 27 28 31 32 35.5 40
19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36
K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr potassium calcium scandium titanium vanadium chromium manganese iron cobalt nickel copper zinc gallium germanium arsenic selenium bromine krypton
39 40 45 48 51 52 55 56 59 59 64 65 70 73 75 79 80 84
37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54
Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe rubidium strontium yttrium zirconium niobium molybdenum technetium ruthenium rhodium palladium silver cadmium indium tin antimony tellurium iodine xenon
16
85 88 89 91 93 96 – 101 103 106 108 112 115 119 122 128 127 131
55 56 57–71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86
lanthanoids
Cs Ba Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po At Rn caesium barium hafnium tantalum tungsten rhenium osmium iridium platinum gold mercury thallium lead bismuth polonium astatine radon
133 137 178 181 184 186 190 192 195 197 201 204 207 209 – – –
87 88 89–103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 actinoids
Fr Ra Rf Db Sg Bh Hs Mt Ds Rg Cn Nh Fl Mc Lv Ts Og francium radium rutherfordium dubnium seaborgium bohrium hassium meitnerium darmstadtium roentgenium copernicium nihonium flerovium moscovium livermorium tennessine oganesson
– – – – – – – – – – – – – – – – –
57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 lanthanoids La Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu lanthanum cerium praseodymium neodymium promethium samarium europium gadolinium terbium dysprosium holmium erbium thulium ytterbium lutetium
139 140 141 144 – 150 152 157 159 163 165 167 169 173 175
89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 actinoids Ac Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No Lr actinium thorium protactinium uranium neptunium plutonium americium curium berkelium californium einsteinium fermium mendelevium nobelium lawrencium
– 232 231 238 – – – – – – – – – – –
The volume of one mole of any gas is 24 dm3 at room temperature and pressure (r.t.p.).
Mark scheme
7(a)(i) ultraviolet (light) 1
7(a)(ii) M1 displayed formula of 2
1–chloropropane
M2 displayed formula of 2–chloropropane
7(b)(i) any 2 from: 2
(same) general formula
(same / similar) chemical properties or reactions
(contain the same) functional group
7(b)(ii) M1 single bond between the two C atoms (and nothing on continuation bonds) 2
M2 1 CH3 group and 1 H on first carbon and 1 CH3 group and 1 H on second carbon and whole structure correct
7(c)(i) M1 structural formula of 2
propan-1,3-dioic acid
M2 structural formula of
ethan-1,2-diol
7(c)(ii) polyester 1
7(c)(iii) M1 carboxylic acids 2
M2 alcohols
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Chemistry 0620/43 for May/June 2023 is out of 80 marks, across 7 questions.
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