Biology 9700/42 February/March 2024: question paper and mark scheme

Question

(a) Fig. 1.1 is a diagram of a nephron. Fig. 1.1 Label Fig. 1.1 using: • one labelling line and the letter A to identify a region that contains urine • one labelling line and the letter B to identify a region that contains podocytes • one labelling line and the letter C to identify a region of the nephron that is within the medulla of the kidney • one labelling line and the letter D to identify the afferent arteriole. [4] (b) The cells of the proximal convoluted tubule are adapted to carry out selective reabsorption. Describe and explain how these cells are adapted to carry out selective reabsorption. …… [4] [Total: 8]

Question

The scientist Gregor Mendel investigated differences in the length of the stem in the pea plant, Pisum sativum. In 1866, he published the results of his investigation into this trait (characteristic). Fig. 2.1 shows a diagram of a pea plant. internode Fig. 2.1 Mendel observed that the pea plants he grew either had tall stems or dwarf (short) stems. In his investigation, Mendel carried out crosses using pea plants with these two phenotypes. (a) From the results of these crosses, Mendel demonstrated that tall stems were dominant to dwarf stems in pea plants. It is now known that the stem length trait in pea plants is controlled by one gene that has two alleles: • a dominant allele, Le • a recessive allele, le. Describe a cross that could be carried out and how the results of the cross could be analysed to determine the genotype of a pea plant with a tall stem. …… [4] (b) The scientists P W Brian and H G Hemming identified that the difference in the length of the stem in pea plants was associated with the presence or absence of gibberellin. They published their findings in 1955. (i) Gibberellin leads to a response in plant cells by binding to specific receptor molecules. State the term used to describe a molecule, such as gibberellin, that binds to specific receptor molecules and leads to a response in cells. …… [1] (ii) Suggest the response of the cells in the internode region of the stem, as labelled in Fig. 2.1, to the presence of gibberellin and describe how this response affects the trait investigated by Mendel. …… [2] [Total: 7]

Question

Cystic fibrosis is an autosomal recessive genetic disease. People with cystic fibrosis have a homozygous recessive genotype. (a) Explain the meaning of the terms homozygous and recessive. homozygous …… recessive …… [2] (b) (i) In 2020: • there were 10 800 people with cystic fibrosis in the UK • the UK population was estimated to be 67 100 000 people. A proportion of people in the UK population are heterozygous for the gene that causes cystic fibrosis and do not have symptoms of the disease. Use the Hardy–Weinberg principle to calculate the number of people in the UK population who are expected to be heterozygous for the gene that causes cystic fibrosis. The two equations for the Hardy–Weinberg principle are provided. equation 1 p + q = 1 equation 2 p2 + 2pq + q2 = 1 p = frequency of the dominant allele q = frequency of the recessive allele p2 = frequency of the homozygous dominant genotype 2pq = frequency of the heterozygous genotype q2 = frequency of the homozygous recessive genotype The first stage of the calculation has been completed for you. 10 800 q2 = 67 100 000 q = p = 2pq = number of people in the UK expected to be heterozygous for the gene = …… [3] (ii) The Hardy–Weinberg principle provides a useful estimate of the number of people in the UK who are heterozygous for cystic fibrosis. However, the estimate is lower than the actual number. This underestimation occurs because not all the conditions of the Hardy–Weinberg principle apply. In the UK in 2020, the mean life expectancy of: • people with cystic fibrosis was approximately 50 years • all people was approximately 80 years. Explain how this information accounts for the underestimation of the number of people in the UK that are heterozygous for cystic fibrosis. …… [3] (c) A screening programme for cystic fibrosis was introduced in 2007 for all children born in the UK. Children are tested within seven days of their birth. Children identified from the screening programme as being at high risk of having cystic fibrosis can have a genetic test to confirm whether they have the disease. (i) Table 3.1 shows the median predicted life expectancy for people born in the UK who have cystic fibrosis. Predictions are shown for people born in 2008, 2012, 2016 and 2020. Table 3.1 year of median predicted life expectancy birth / years 2008 38.8 2012 43.5 2016 47.0 2020 50.6 Describe the trend shown in Table 3.1 and outline how early screening for cystic fibrosis may have contributed to this trend. …… [3] (ii) In many countries, a genetic test for cystic fibrosis is available to adults who do not have cystic fibrosis but have a family member who either has cystic fibrosis or is heterozygous for the gene that causes cystic fibrosis. These adults include partners, parents, offspring, brothers and sisters of the family member. The aim is to find out if any of these adults are heterozygous for the gene that causes cystic fibrosis. Discuss the ethical and social considerations of making a genetic test for cystic fibrosis available to these adults. …… [3] [Total: 14]

Question

Holstein Friesian cattle are a breed of cattle used by dairy farmers in many countries of the world for the high milk yield of their cows. Fig. 4.1 shows Holstein Friesian cattle. Fig. 4.1 Milk yield in Holstein Friesian cattle is affected by heat stress. Heat stress occurs when homeostatic mechanisms are not enough to keep the body temperature down to normal levels. One of the factors that contributes to heat stress is air temperature. Fig. 4.2 shows: • the mean daily air temperature in Central Europe • the mean monthly milk yield per cow of Holstein Friesian cattle in Central Europe. 30 850 25 800 20 750 mean mean daily air monthly milk temperature 15 700 yield per cow / °C / kg cow–1 10 650 5 600 0 550 Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec month key mean daily air temperature mean monthly milk yield per cow standard error (SE) bar Fig. 4.2 (a) With reference to Fig. 4.2, describe the trends in air temperature and milk yield from April to August. …… [2] (b) Many dairy farmers in tropical regions use cattle breeds that are tolerant to heat stress (heat-tolerant cattle). These heat-tolerant cattle: • can tolerate higher air temperatures than Holstein Friesian cattle before heat stress occurs • have milder symptoms of heat stress than Holstein Friesian cattle for the same high air temperatures. Where heat stress does not occur, heat-tolerant cattle produce a lower milk yield than Holstein Friesian cattle under the same conditions. Scientists compared DNA sequences of Holstein Friesian cattle and heat-tolerant cattle for a number of genes known to have an effect on body temperature. Twenty genes were found that had alleles associated only with heat-tolerant cattle. With reference to the information provided, including the data in Fig. 4.2: • state the type (pattern) of phenotypic variation shown by milk yield in cattle • identify factors that cause phenotypic variation in milk yield in cattle. In each case, give a reason for your choice. type (pattern) of phenotypic variation and reason for choice …… factors that cause phenotypic variation and reason for each choice …… [3] (c) The scientists found that one of the genes studied, PRLR, has a dominant allele known as SLICK. The SLICK allele was identified in Senepol cattle, a heat-tolerant breed, and is not found in Holstein Friesian cattle. Cattle with the SLICK allele have short hair due to reduced hair growth. Scientists have used selective breeding to introduce the SLICK allele into Holstein Friesian cattle. The milk yields of normal Holstein Friesian cattle and Holstein Friesian cattle with the SLICK allele are shown in Fig. 4.3, during: • March, when the mean daily air temperature is 5 °C. • September, when the mean daily air temperature is 14 °C. 900 key 800 Holstein Friesian cattle 700 Holstein Friesian cattle with SLICK allele 600 mean monthly 500 milk yield per cow / kg cow–1 400 300 200 100 0 March September month Fig. 4.3 With reference to Fig. 4.3, describe the effect of the SLICK allele on milk yield in Holstein Friesian cattle. …… [3] (d) The SLICK allele differs from the recessive allele by a single nucleotide deletion. This results in a frameshift mutation and introduces a premature stop codon in the PRLR gene. Scientists can use gene editing to replicate this mutation in Holstein Friesian cattle. This provides a way to introduce the SLICK allele into Holstein Friesian cattle without selective breeding. Compare gene editing and selective breeding for introducing the SLICK allele into Holstein Friesian cattle. Include similarities and differences in your answer. …… [6] [Total: 14]

Question

Complete the following paragraphs using the most appropriate word or words. The theory of evolution describes a process that can lead to the formation of new species from pre-existing species over …… . DNA sequence data of different species can be compared to show evolutionary relationships. Two species that have a more recent common ancestor share more …… in the DNA nucleotide sequences of their genomes than two species that are more distantly related. Mitochondrial DNA can also be used in the study of evolutionary relationships. Mitochondrial DNA is inherited only from the female gamete, and its nucleotide sequence is unaffected by …… during the production of gametes. DNA sequence data can be stored in large biological …… , allowing faster comparison of the nucleotide sequences of genomes using computer software. DNA sequence data can also be used to predict the …… sequences of proteins produced by a species. A …… can be used to detect many different mRNA molecules at the same time in studies that compare gene expression between different species. [6]

Question

A respirometer is a piece of apparatus that can be used to measure the rate of respiration of living tissue such as germinating peas. A simple respirometer is shown in Fig. 6.1. syringe wire gauze ruler germinating cm peas 0 U-shaped 1 tube test-tube 2 coloured 3 liquid potassium 4 hydroxide 5 solution Fig. 6.1 A student carried out an investigation to determine the effect of temperature on the rate of respiration of germinating peas. • The student set up the respirometer as shown in Fig. 6.1 and placed the respirometer in a water-bath at 10 °C. • After five minutes, the student used the syringe to adjust the position of the coloured liquid in the right-hand side of the U-shaped tube so that it lined up with 0 cm on the ruler. The student immediately started a timer. • The germinating peas used up oxygen, causing the coloured liquid in the U-shaped tube to move. • The student measured the distance moved by the coloured liquid after 20 minutes. • The student repeated the experiment at temperatures of 20 °C, 30 °C, 40 °C and 50 °C. (a) State the function of the potassium hydroxide solution used in the investigation. …… [1] (b) Suggest how the validity of the results could be assessed. …… [2] (c) Explain why the respirometer was left in the water-bath for five minutes before starting the experiment. …… [1] (d) The rate of movement of the coloured liquid in the U-shaped tube, calculated from the results, is shown in Table 6.1. Table 6.1 temperature / °C rate of movement / mm min–1 10 0.40 20 0.70 30 1.30 40 1.15 50 0.60 Plot a graph of the results shown in Table 6.1 on the grid in Fig. 6.2. Draw a curved line of best fit. 1.40 1.30 1.20 1.10 1.00 0.90 0.80 rate of movement 0.70 / mm min–1 0.60 0.50 0.40 0.30 0.20 0.10 0.00 0 10 20 30 40 50 temperature / °C Fig. 6.2 [2] (e) The rate of movement of the coloured liquid is related to the rate of respiration. Explain the effect of temperature on the rate of respiration shown in Table 6.1 and Fig. 6.2. …… [3] [Total: 9]

Question

(a) The light-dependent stage of photosynthesis occurs within chloroplasts. In this stage, electrons are emitted from the chlorophyll a molecules and passed to electron acceptors. If a redox indicator, such as DCPIP, is added to a suspension of illuminated chloroplasts, electrons will be transferred to DCPIP, causing the colour of the DCPIP to change from blue to colourless. A student investigated the effect of the wavelength of light (colour of light) on the rate of photosynthesis. • DCPIP was added to three colorimeter tubes, each containing a suspension of chloroplasts. The chloroplast suspensions were kept in the dark until required. • The colorimeter tubes were each exposed to light of a different colour: red, blue or green. The intensity of light was the same for all tubes, and each was exposed to light for four minutes. All other conditions were kept the same. • The absorbance of each chloroplast suspension was measured at one-minute intervals using a colorimeter. The results are shown in Fig. 7.1. 1.6 1.5 green light 1.4 1.3 1.2 absorbance 1.1 1.0 blue 0.9 light 0.8 red 0.7 light 0.6 0 1 2 3 4 time / min Fig. 7.1 (i) Explain why the chloroplast suspensions were kept in the dark until required. …… [1] (ii) Describe the results shown in Fig. 7.1. …… [3] (iii) With reference to the light-dependent stage of photosynthesis, explain the differences between the results shown in Fig. 7.1 for red light and for green light. …… [3] (b) Changes in the atmospheric carbon dioxide concentration, light intensity and temperature can affect the rate of photosynthesis. These three factors directly affect different processes of photosynthesis. Complete Table 7.1 using a tick (3) to identify the processes that can be directly affected by each factor or a cross (7) to identify the processes that are not directly affected by each factor. Indirect effects where a change in the rate of one process affects the rate of a different process should not be considered. A tick or a cross must be placed in the final column of every row. Table 7.1 factor process 3 or 7 Calvin cycle carbon dioxide …… concentration photophosphorylation Calvin cycle light intensity photophosphorylation Calvin cycle temperature photophosphorylation [3] [Total: 10]

Question

(a) Approximately 2 × 109 people in the world are currently infected with the bacterial disease tuberculosis (TB) caused by Mycobacterium tuberculosis. Early diagnosis is important so that treatment can begin. APOPO is a non-profit organisation that has trained African giant pouched rats, Cricetomys gambianus, to use their sense of smell to detect M. tuberculosis. They do this by sniffing a sample of thick mucus from the lungs of people who may have TB. The African giant pouched rats are able to detect the presence of M. tuberculosis with an accuracy of 87–93%. Fig. 8.1 shows an African giant pouched rat. Fig. 8.1 (i) The type of receptor cell used by African giant pouched rats to detect M. tuberculosis is the same as that used in human taste buds. Name this type of receptor cell. …… [1] (ii) Suggest why African giant pouched rats trained to detect M. tuberculosis may also be able to detect other species of Mycobacterium that cause TB. …… [2] (b) The African giant pouched rat belongs to the kingdom Animalia in the domain Eukarya. Complete Table 8.1 to show the full classification of the African giant pouched rat. Table 8.1 kingdom Animalia Chordata class Mammalia Rodentia family Nesomyidae species gambianus [2] (c) Differences between members of the domain Eukarya and members of the domain Bacteria include the presence or absence of particular membrane-bound cell structures. Outline other differences in the characteristic features of members of the domain Eukarya and members of the domain Bacteria. …… [4] (d) Describe, with reference to the structure of viruses, how viruses are classified. …… [2] [Total: 11]

Question

(a) An investigation was carried out to study the effect of different intensities of blue light on the percentage germination of barley seeds. Barley seeds were exposed to blue light for a period of seven days. All other variables were kept constant. The results are shown in Table 9.1. Table 9.1 light intensity percentage / arbitrary units (au) germination 0 (dark) 98.0 36 76.9 48 45.0 57 14.7 The effect of blue light on the concentration of abscisic acid (ABA) was also investigated. ABA concentration was measured at intervals over seven days in barley seeds exposed to blue light at an intensity of 57 arbitrary units. The results are shown in Table 9.2. Table 9.2 concentration of ABA day / arbitrary units (au) 0 100 1 90 3 350 5 351 7 381 For comparison, in the dark the concentration of ABA in barley seeds fell from 100 au at the start (day 0) to 45 au on day 1 and did not increase from day 1 to day 7. ABA is thought to affect gibberellin synthesis or activity. Using the information in Table 9.1 and Table 9.2, describe the effect of blue light on the germination of barley seeds and suggest an explanation for this effect. …… [4] (b) After germination, auxin is important in the growth of barley plants. Describe and explain the role of auxin in cell elongation. …… [7] [Total: 11]

Question

(a) Striated muscle is composed of myofibrils. Myofibrils contain several structural proteins including troponin, tropomyosin, actin and myosin. Outline the roles of these four structural proteins in the contraction of a sarcomere. …… [4] (b) Drugs that cause muscle paralysis (paralytic drugs) are used during surgery to stop the patient moving. One commonly used paralytic drug is succinylcholine, which works by preventing contraction of muscles. Succinylcholine is able to prevent muscles contracting because it has a similar shape to acetylcholine. Suggest how succinylcholine is able to prevent muscles contracting. …… [3] (c) Duchenne muscular dystrophy (DMD) is a genetic disease that is caused by a single gene. DMD affects striated muscle, and symptoms of the disease first appear at an early age. A fibrous protein, dystrophin, stabilises muscle fibres during contraction. A person with DMD produces non-functioning dystrophin or no dystrophin at all. The disease occurs in about four in 100 000 people and mainly affects boys. Suggest and explain why boys are more likely to have DMD than girls. …… [3] [Total: 10] The boundaries and names shown, the designations used and the presentation of material on any maps contained in this question paper/insert do not imply official endorsement or acceptance by Cambridge Assessment International Education concerning the legal status of any country, territory, or area or any of its authorities, or of the delimitation of its frontiers or boundaries.