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Biology 9700/34 May/June 2022: question paper and mark scheme

Cambridge AS & A Level Biology (9700), Paper 3 (Advanced Practical Skills 2), May/June 2022. Read both free below, or download them. Done the paper? Get it marked by AI against this mark scheme.

9700_s22_qp_349700_s22_ms_349700/34/M/J/22

Paper
Paper 3 (Advanced Practical Skills 2)
Total marks
40
Time
2 hours
Questions
2
Code on the paper
9700/34/M/J/22
9700_s22_ms_34.pdf

9700/34 mark scheme, question by question

Each question as it's printed, and the mark scheme's points for it, as text. Diagrams, tables and graphs are in the PDFs above.

Question 120 marks

Question

In industry it is important that scientists are able to estimate the concentration of chemicals in plant extracts such as fruit juice. Sucrose is a non-reducing sugar that can be hydrolysed to form reducing sugars. You will prepare known concentrations of a reducing sugar by serial dilution. You will then use the known concentrations to estimate the concentration of a reducing sugar produced by hydrolysis of a sucrose solution. You are provided with the materials shown in Table 1.1. Table 1.1 labelled contents hazard volume / cm3 R 1.0% reducing sugar solution none 50 harmful B Benedict’s solution 30 irritant W distilled water none 100 If any solution comes into contact with your skin, wash off immediately under cold water. It is recommended that you wear suitable eye protection. (a) You will need to carry out a serial dilution of the 1.0% reducing sugar solution, R, to reduce the concentration by half between each successive dilution. You will need to prepare four concentrations of solution in addition to the 1.0% reducing sugar solution, R. After the serial dilution is completed, you will need to have 10 cm3 of each concentration available to use. (i) Complete Fig. 1.1 to show how you will prepare your serial dilution. Fig. 1.1 shows the first two beakers you will use to make your serial dilution. You will need to draw three additional beakers. For each beaker add labelled arrows to show: • the volume of reducing sugar solution transferred • the volume of distilled water, W, added. Under each beaker, state the concentration of reducing sugar solution. 0 cm3 of W 20 cm3 of …… 1.0% reducing sugar, R …… 10 cm3 of 1.0% reducing sugar solution to use Fig. 1.1 [3] Carry out step 1 to step 11. step 1 Set up a water-bath and heat it to boiling ready for step 6. step 2 Prepare the concentrations of reducing sugar solution, as decided in (a)(i), in the beakers provided. step 3 Label the test-tubes with the concentrations you prepared in step 2. step 4 Put 2 cm3 of each reducing sugar concentration into the appropriately labelled test-tube. Put these test-tubes into a test-tube rack. step 5 Put 2 cm3 of Benedict’s solution, B, into each of the test-tubes from step 3. Shake gently to mix. step 6 Put the test-tube labelled 1.0% into the boiling water-bath. Start timing. step 7 Measure the time taken to the first appearance of a colour change in the test-tube. If there is no colour change after 120 seconds, stop timing and record as ‘more than 120’. step 8 Record the result from step 7 in (a)(ii). step 9 Remove the test-tube from the water-bath. Put the test-tube in the test-tube rack. step 10 Repeat step 6 to step 9 with the remaining concentrations of reducing sugar. step 11 Turn off the water-bath. You will need this again in step 16 and in step 23. (ii) Record your results in an appropriate table. [5] (iii) State one significant source of error when measuring the dependent variable in this investigation. …… [1] (iv) Suggest how you could improve the procedure to reduce the error you stated in (a)(iii). …… [1] Question 1 continues on page 6. You will: • carry out the test for non-reducing sugar on the unknown concentration of sucrose, U • estimate the concentration of the reducing sugar fructose in U. You are provided with the materials shown in Table 1.2. You will also need to use the Benedict’s solution, B, shown in Table 1.1. Table 1.2 labelled contents hazard volume / cm3 unknown concentration of sucrose U none 20 solution H dilute hydrochloric acid irritant 10 10 g sodium hydrogencarbonate A none – powder If any solution comes into contact with your skin, wash off immediately under cold water. It is recommended that you wear suitable eye protection. Carry out step 12 to step 27. step 12 Heat the water-bath to boiling ready for step 16 and step 23. step 13 Label a clean test-tube U. step 14 Put 2 cm3 of U into the test-tube labelled U. step 15 Put 2 cm3 of H into this test-tube. Shake gently to mix. step 16 Put test-tube U into the boiling water-bath. Leave the test-tube for 2 minutes. step 17 After 2 minutes, remove the test-tube from the water-bath and put it into the beaker labelled For cooling. step 18 Leave the test-tube in the beaker for 3 minutes. step 19 After 3 minutes, use a spatula to put a small amount of A into test-tube U. The mixture will fizz and rise up the test-tube. step 20 Repeat step 19 until there is no more fizzing and there is a small amount of A in the bottom of the test-tube. step 21 Put 4 cm3 of B into test-tube U. step 22 Shake the test-tube gently to mix. step 23 Put test-tube U into the boiling water-bath. Start timing. step 24 Measure the time taken to the first appearance of a colour change in the test-tube. If there is no colour change after 120 seconds, stop timing and record as ‘more than 120’. step 25 Record the result in (a)(v). step 26 Remove the test-tube from the water-bath. Put the test-tube in the test-tube rack. step 27 Turn off the water-bath. (v) State the result for U. result for U …… [1] (vi) Using results from (a)(ii) and (a)(v), estimate the concentration of reducing sugars in U. concentration of reducing sugars in U …… % Calculate the concentration of fructose in U. Explain how you determined this concentration. concentration of fructose in U …… % explanation …… [2] (b) A student investigated the effect of different concentrations of sucrose solution on the mass of pieces of potato tissue. The mass of each piece of potato tissue was measured before and after soaking in different concentrations of sucrose for 1 hour and the change in mass calculated. Table 1.3 shows the results of this investigation. Table 1.3 concentration of sucrose solution change in mass / mol dm–3 /g 0 +0.60 0.2 +0.31 0.4 0.00 0.6 –0.29 0.8 –0.45 1.0 –0.66 (i) Plot a graph of the data shown in Table 1.3 on the grid in Fig. 1.2. Use a sharp pencil. Fig. 1.2 [4] (ii) Using your knowledge of water potential, explain the difference in the change of mass between the potato piece in the 0.4 mol dm–3 sucrose solution and the potato piece in the 1.0 mol dm–3 sucrose solution. …… [3] [Total: 20]

Mark scheme

1(a)(i) 1 0.5%, 0.25%, 0.125%, 0.0625% (labels under the correct sequence of beakers) ; 3 2 shows transfer of 10 cm3 to each of the four beakers ; 3 shows addition of 10 cm3 to each of the four beakers ; 1(a)(ii) 1 heading for independent variable: 5 concentration of reducing sugar and percentage (concentration) or % ; 2 heading for dependent variable: time and s or seconds and no units in the body of the table ; 3 records times for each concentration ; 4 results record the correct trend ; 5 results recorded as whole seconds ; 1(a)(iii) difficult to judge the time to the first colour change ; 1 1(a)(iv) repeat experiment three times and calculate the mean ; 1 1(a)(v) records time for U and units ; 1 1(a)(vi) estimates concentration of reducing sugars in U from results in (a)(ii) and (a)(v) ; 2 reference to sucrose being hydrolysed to fructose and glucose so only half of reducing sugars is fructose ; 1(b)(i) 1 x-axis: concentration of sucrose solution / mol dm–3 4 and y-axis : change in mass / g ; 2 scale on x-axis: 0.2 to 2 cm, labelled at least every 2 cm and y-axis: 0.2 to 2 cm, labelled at least every 2 cm ; 3 correct plotting of all points using small crosses or small dots in circles ; 4 plots joined with the lines passing through all points and line is either a smooth curve or joined plot to plot ; 1(b)(ii) 1 the potato piece in 0.4 mol dm–3 stayed the same mass because the water potential in the cells was equal to the 3 solution ; 2 the potato piece in 1.0 mol dm–3 lost mass because the water potential in the cells was higher than the surrounding solution so water moved out of the cells ; 3 correct reference to osmosis ; must have difference and explanation for mp1 and mp2

Question 220 marks

Question

M1 is a slide of a stained transverse section through a plant root. (a) (i) Draw a large plan diagram of the whole section on M1. Use a sharp pencil. Use one ruled label line and label to identify the epidermis. [4] (ii) Observe the epidermis and the layer of cells beneath it on the section of the root on M1. Select a group of four adjacent cells: two cells from the epidermis and two cells from the layer below the epidermis. Each cell must touch at least two of the other cells. • Make a large drawing of this group of four cells. • Use one ruled label line and label to identify a cell wall of one cell. [5] (b) Fig. 2.1 is a photomicrograph of a stained transverse section through a root of a different type of plant. Fig. 2.1 Identify three observable differences, other than size and colour, between the root section on M1 and the root section shown in Fig. 2.1. Record three observable differences in Table 2.1. Table 2.1 feature M1 Fig. 2.1 [4] (c) Fig. 2.2 is the same photomicrograph as that in Fig. 2.1, with the line X–Y drawn across its width. X Y 3.4 mm Fig. 2.2 (i) In Fig. 2.2 the line X–Y is drawn across the diameter of the root section. Use the line X–Y and the scale bar to calculate the actual diameter of the root section. Show your working and use appropriate units. actual diameter of the root section = …… [3] (ii) Calculate the area of the root section in Fig. 2.2, using the actual diameter from (c)(i) and the equation: area = πr 2 Show your working and use appropriate units. area of root section = …… [2] (iii) Suggest why the answer to (c)(ii) is an estimate of the area of the root section shown in Fig. 2.2 rather than the actual area. …… [1] (iv) Suggest how a more accurate estimate of the area of the root section shown in Fig. 2.2 could be made. …… [1] [Total: 20]

Mark scheme

2(a)(i) 1 uses most of the available space and draws at least two layers of tissue ; 4 2 draws whole root and no cells ; 3 draws at least two layers around the vascular tissue in the centre of the root ; 4 label line and label to the epidermis ; 2(a)(ii) 1 uses most of the available space and all the lines sharp and continuous ; 5 2 draws only four cells and each cell touching at least two other cells ; 3 cell wall drawn as two lines and three lines where cells touch ; 4 correct proportions of the cells ; 5 label line and label to one cell wall ; 2(b) records only differences ; 4 any three correct differences from e.g.: feature M1 Fig. 2.1. epidermis thinner thicker ; cortex wider narrower ; endodermis present absent ; central tissue parenchyma cells xylem vessels ; 2(c)(i) 1 correct measurement of the scale bar and correct measurement of the line X–Y ; 3 2 to find the magnification, shows the length of the scale bar divided by 3.4 and shows the length of the line X–Y divided by the figure for the magnification ; 3 correct answer with the appropriate units ; 2(c)(ii) shows the diameter of the root divided by 2 ; 2 records the answer to area in μm2 or mm2 or cm2 ; 2(c)(iii) the root section is not a true circle /AW ; 1 2(c)(iv) take more measurements of the diameter at different points and calculate the mean ; 1

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Where can I find the 9700/34 May/June 2022 mark scheme?

On this page, free: the mark scheme for AS & A Level Biology 9700/34, May/June 2022 (9700_s22_ms_34), and the question paper (9700_s22_qp_34), to read or download, with each question's marking points written out underneath.

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Biology 9700/34 for May/June 2022 is out of 40 marks, with 2 hours to answer it, across 2 questions.

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