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Biology 9700/53 May/June 2024: question paper and mark scheme

Cambridge AS & A Level Biology (9700), Paper 5 Planning, Analysis and Evaluation, May/June 2024. Read both free below, or download them. Done the paper? Get it marked by AI against this mark scheme.

9700_s24_qp_539700_s24_ms_539700/53/M/J/24

Paper
Paper 5 Planning, Analysis and Evaluation
Total marks
30
Time
1 hour 15 minutes
Questions
2
Code on the paper
9700/53/M/J/24
9700_s24_ms_53.pdf

9700/53 mark scheme, question by question

Each question as it's printed, and the mark scheme's points for it, as text. Diagrams, tables and graphs are in the PDFs above.

Question 119 marks

Question

Blood vessels must be able to withstand and maintain varying blood pressures. There are several methods that could be used to determine the strength of a blood vessel. One method is called the circumferential tensile strength (CTS) test, as shown in Fig. 1.1. clamp stand hook ring of blood vessel mass hanger 10 g masses Fig. 1.1 The ring of blood vessel, shown in Fig. 1.1, was cut from a length of artery or vein that was prepared by removing surrounding tissues. A student wanted to use the apparatus in Fig. 1.1 to determine the mass needed to break an artery and the mass needed to break a vein. (a) (i) Identify the independent variable and the dependent variable in this investigation. independent variable …… dependent variable …… [1] (ii) The student was provided with lengths of a large artery, lengths of a large vein and standard laboratory apparatus. Describe how the student could use the CTS test to determine the mass needed to break an artery and the mass needed to break a vein. Your method should be set out in a logical order and be detailed enough to let another person follow it. …… [6] Another student investigated how the length of a ring of vein and the length of a ring of artery increases as more mass is added. The student used the apparatus shown in Fig. 1.2 with the ring of vein. clamp stand hook ring of vein part of metre rule mass hanger 10 g masses Fig. 1.2 The results for the ring of vein are shown in Table 1.1. Table 1.1 mass added / g length of ring of vein / mm percentage increase in length of ring of vein 0 21 0 10 36 20 38 81 30 40 90 40 41 50 41 (b) (i) Complete Table 1.1 by calculating the percentage increase in length of the ring of vein for 10 g, 40 g and 50 g. [2] (ii) Explain why the student calculated the percentage increase in length of the ring of vein. …… [1] (iii) On the grid in Fig. 1.3, plot a graph of the data shown in Table 1.1. Fig. 1.3 [3] (iv) The student carried out the same investigation using a muscular artery instead of a vein. Predict the shape of the curve you would expect for the muscular artery. On Fig. 1.3: • sketch the curve you predicted for the muscular artery • label this curve with the word artery. [2] (v) Explain the shape of the curve you sketched for the muscular artery in Fig. 1.3. …… [2] (vi) Another student suggested that the experiment should be repeated with more rings from the same blood vessels. Suggest two other ways the student could modify the method to improve the quality of the results. …… [2] [Total: 19]

Mark scheme

Examiners should consider the context and scientific use of any keywords when awarding marks. Although keywords may be present, marks should not be awarded if the keywords are used incorrectly.

Question 26 marks

Question

Gibberellins are a group of plant hormones that are involved in the elongation of plant stems. A student investigated the effect of two different concentrations of a gibberellin, known as GA3, on stem elongation of 10-day old pea seedlings. The student was given a stock solution of GA3 with a concentration of 2.85 × 10–4 mol dm–3. (a) Describe a method the student could use to make a solution of GA3 with a concentration of 1.90 × 10–6 mol dm–3 and state the dilution factor used. …… [2] (b) In the investigation, the student: • used the two concentrations of GA3: 2.85 × 10–4 mol dm–3 (high concentration GA3) and 1.90 × 10–6 mol dm–3 (low concentration GA3) • applied the high concentration GA3 to one batch of 10-day-old pea seedlings • applied the low concentration GA3 to another batch of 10-day-old pea seedlings • applied distilled water to a third batch of 10-day-old pea seedlings, as a control • standardised all other variables • measured the length of the stem of each seedling every two days until the seedlings were 20 days old • calculated the rate of stem elongation in cm day–1. State one way in which the student could standardise the measuring of stem length. …… [1] (c) The results of the investigation are shown in Table 2.1. Table 2.1 age of seedling mean stem length mean stem mean stem length / days with high length with low with distilled water concentration GA3 concentration GA3 added / cm added / cm added / cm 10 2 2 2 12 4 2 3 14 7 5 4 16 6 12 7 18 20 15 8 20 25 21 8 rate of stem elongation 2.3 0.6 (i) Complete Table 2.1 by calculating the rate of stem elongation in cm day–1 for the seedlings with low concentration GA3 added. [1] (ii) A scientist stated that they did not have enough confidence in the results in Table 2.1 to make any conclusions. State one reason to support the statement made by the scientist. …… [1] (iii) Describe how the student could modify the investigation to increase confidence in the results. …… [1] (d) The student found a study on the internet that considered the effect of different wavelengths of light on the concentration of two types of gibberellins, GA1 and GA8, in pea plants. In the study, 60 pea seeds were germinated and kept in the dark (no light) for seven days. The pea seedlings were divided into four batches of 15: • batch 1 remained in the dark • batch 2 was exposed to blue light (470 nm) • batch 3 was exposed to red light (680 nm) • batch 4 was exposed to far-red light (750 nm). After 4 hours the concentrations of GA1 and GA8 in the seedlings were measured. Table 2.2 shows the results. Table 2.2 batch wavelength of colour of mean GA1 concentration mean GA8 concentration light / nm light ± standard deviation ± standard deviation / ng g–1 fresh mass / ng g–1 fresh mass 1 – dark 2.87 ± 0.72 3.07 ± 0.10 2 470 blue light 0.21 ± 0.05 3.90 ± 0.13 3 680 red light 0.31 ± 0.10 5.03 ± 0.21

Mark scheme

The examiner should not choose between contradictory statements given in the same question part, and credit should not be awarded for any correct statement that is contradicted within the same question part. Wrong science that is irrelevant to the question should be ignored.

Question 411 marks

Question

750 far-red light 1.38 ± 0.26 4.00 ± 0.72 The student calculated the standard error (SE) and 95% confidence intervals (95% CI) for the data shown in Table 2.2. The formulae that the student used were: s SE = n 95% CI = x ± (2 × SE) key to symbols s = standard deviation n = sample size (number of observations) x = mean Table 2.3 shows the calculated values for SE and 95% CI for the data from Table 2.2. Table 2.3 batch SE for GA1 mean ± 95% CI for SE for GA8 mean ± 95% CI for / ng g–1 fresh mass GA1 / ng g–1 fresh mass GA8 / ng g–1 fresh mass / ng g–1 fresh mass 1 0.186 2.87 ± 0.37 0.026 3.07 ± 0.05 2 0.013 0.21 ± 0.03 0.034 3.90 ± 0.07 3 0.026 0.31 ± 0.05 0.054 5.03 ± 0.11 4 …… …… 0.186 4.00 ± 0.37 Complete Table 2.3 to show the calculated values for SE and mean ± 95% CI for the data from far-red light for GA1 (batch 4). [2] (e) Fig. 2.1 shows the bar chart of the results from the study. 5.00 Key 4.00 GA1 mean 3.00 gibberellin GA8 concentration / ng g–1 fresh mass 2.00 1.00 1 2 3 4 batch Fig. 2.1 Use Fig. 2.1, Table 2.2 and Table 2.3 to state three conclusions about the effect of different wavelengths of light on the concentrations of GA1 and GA8 in plants. …… [3] [Total: 11] The boundaries and names shown, the designations used and the presentation of material on any maps contained in this question paper/insert do not imply official endorsement or acceptance by Cambridge Assessment International Education concerning the legal status of any country, territory, or area or any of its authorities, or of the delimitation of its frontiers or boundaries.

Mark scheme

The error carried forward (ecf) principle should be applied, where appropriate. If an incorrect answer is subsequently used in a scientifically where necessary and any exceptions to this general principle will be noted.

Question 5

Question

In the question paper above.

Mark scheme

‘List rule’ guidance For questions that require n responses (e.g. State two reasons …): The response should be read as continuous prose, even when numbered answer spaces are provided. Incorrect responses should not be awarded credit but will still count towards n. Read the entire response to check for any responses that contradict those that would otherwise be credited. Credit should not be awarded for any responses that are contradicted within the rest of the response. Where two responses contradict one another, this should be treated as a single incorrect response. Non-contradictory responses after the first n responses may be ignored even if they include incorrect science. PUBLISHED

Question 6

Question

In the question paper above.

Mark scheme

Calculation specific guidance Correct answers to calculations should be given full credit even if there is no working or incorrect working, unless the question states ‘show your working’. For questions in which the number of significant figures required is not stated, credit should be awarded for correct answers when rounded For answers given in standard form (e.g. a × 10n) in which the convention of restricting the value of the coefficient (a) to a value between 1 Unless a separate mark is given for a unit, a missing or incorrect unit will normally mean that the final calculation mark is not awarded.

Question 7

Question

In the question paper above.

Mark scheme

Guidance for chemical equations PUBLISHED ; separates marking points / alternative answers for the same point A accept (for answers correctly cued by the question, or by extra guidance) R reject I ignore () the word / phrase in brackets is not required, but sets the context AW alternative wording (where responses vary more than usual) underline actual word given must be used by candidate (grammatical variants accepted) max indicates the maximum number of marks that can be given ora or reverse argument mp marking point (with relevant number) ecf error carried forward AVP alternative valid point PUBLISHED Question Answer Marks 1(a)(i) independent variable 1 type of blood vessel / artery and vein and dependent variable mass required to break (the blood vessel) ; PUBLISHED Question Answer Marks 1(a)(ii) any six from: 6 1 method to cut the blood vessel ; 2 method to measure blood vessel of, same / stated, length / AW ; 3 idea of discard samples that are damaged ; 4 idea of waiting (to see if the blood vessel breaks) before adding the next (10 g) mass ; 5 use, artery and vein / blood vessels, from the same source ; 6 add (10 g) masses, to the mass hanger, until the blood vessel breaks ; 7 idea of measuring mass of mass hanger / including mass of mass hanger ; 8 for each type of blood vessel, measure / note / record / AW, (total) mass when the blood vessel broke ; 9 use at least three measurements for each type of blood vessel and calculate a mean ; 10 safety comment with hazard and precaution ; hazard risk precaution knife / scalpel injury cut away from hand blood vessels biohazard / pathogens / allergy gloves / mask / PPE / use disinfectant / wash hands mass hanger falling injury suitable precaution to prevent injury 11 idea of repeat procedure with smaller mass intervals near to breaking mass ; PUBLISHED Question Answer Marks 1(b)(i) 2 mass added / g length of vein / mm percentage increase in length of ring of vein 0 21 0 10 36 71 20 38 81 30 40 90 40 41 95 50 41 95 three values correct ;; one or two correct max 1 1(b)(ii) 1 to make a valid comparison (with other blood vessels / veins) ; 1 2 allows comparison as, initial / starting, length (of veins) is, not constant / AW ; 1(b)(iii) 1 correct orientation for axes and linear scale ; 3 2 axes labelled and units; 3 all points plotted correctly and line drawn accurately ; 1(b)(iv) 1 curve for artery starts at same point as the vein ; 2 2 curve for artery below curve for vein and does not intersect ; PUBLISHED Question Answer Marks 1(b)(v) any two from: 2 1 starts at, same point / origin, as using percentage increase ; 2 (muscular) arteries have a thicker, wall / tunica media / muscle layer (than the vein) or 3 (muscular) arteries have more (smooth) muscle (than the vein) ; 4 idea of (muscular artery) withstands more (blood) pressure so stretches less (than the vein) ; 1(b)(vi) any two from: 2 1 use smaller mass intervals ; 2 extend the range of the masses added ; 3 use a, force meter / Newton meter / data logger / AW, (to apply force) ; 4 attach a, pointer / fiducial mark, to the ring of blood vessel (to improve length measurement / removing parallax) ; 5 use, same / stated, width of blood vessel ; PUBLISHED Question Answer Marks 2(a) 1 cm3 of stock solution to 149 cm3 of distilled water ; 2 (dilution factor is) 150 ; 2(b) any one from: 1 1 measure from, top of the soil / bottom of stem / AW, to top of the stem / AW ; 2 straighten the stem (while measuring length) ; 3 place string along stem, and measure length of string ; 2(c)(i) 1.9 ; 1 2(c)(ii) any one from: 1 1 (mean stem) length was measured, in / to the nearest, cm ; 2 many anomalies in the results / identified anomaly ; 3 no statistical test carried out ; 2(c)(iii) any one from: 1 1 measure lengths in mm ; 2 idea of repeat high concentration GA3 experiment (to check anomaly) ; 3 measure, at same time every day / for more days ; 4 measure more seedlings / increase sample size ; 2(d) (SE =) 0.067 ; 2 (95% CI =) 1.38 ± 0.13 ; PUBLISHED Question Answer Marks 2(e) any three from: 3 1 highest (concentration of) GA8 with, red light / 680 nm or lowest (concentration of) GA1 with, blue light / 470 nm or highest (concentration of) GA1, in the dark / with no light ; 2 lower (concentration of) GA1 for all wavelengths of light (compared to dark) or higher (concentration of) GA8 for all wavelengths of light (compared to dark) ; 3 95% CI, does not overlap (for the lower concentration of GA1 for all wavelengths of light), so there is a significant difference or 95% CI, does not overlap, (higher concentration of GA8 for all of the wavelengths of light), so there is a significant difference ;

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Where can I find the 9700/53 May/June 2024 mark scheme?

On this page, free: the mark scheme for AS & A Level Biology 9700/53, May/June 2024 (9700_s24_ms_53), and the question paper (9700_s24_qp_53), to read or download, with each question's marking points written out underneath.

How many marks is 9700/53 out of?

Biology 9700/53 for May/June 2024 is out of 30 marks, with 1 hour 15 minutes to answer it, across 2 questions.

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Yes. Upload your answers to 9700/53/M/J/24 as a PDF or photos, and CIE Buddy marks every question against this paper's official mark scheme, using Cambridge's marking rules. You get your score, each lost mark explained on your own script, and the topics to revise. It's a guide, not an official Cambridge grade.