Question 118 marks
Question
The thiosulfate ion, S2O32–, reacts in acidic conditions as shown. S2O32–(aq) + 2H+(aq) S(s) + SO2(g) + H2O(l) You will investigate how the concentration of the thiosulfate ions affects the rate of this reaction. The rate can be measured by timing how long it takes for the solid sulfur that is formed to make the solution too cloudy to see through. Small amounts of SO2 gas may be produced during this reaction. Care must be taken to avoid inhaling this SO2 gas. It is very important that as soon as each experiment is complete the beaker containing the reaction mixture is emptied into the quenching bath. FA 1 is 0.100 mol dm–3 sodium thiosulfate, Na2S2O3. FA 2 is 2.00 mol dm–3 hydrochloric acid, HCl. distilled water (a) Method Experiment 1 ●● Fill the burette labelled FA 1 with FA 1. ●● Run 45.00 cm3 of FA 1 from the burette into the 100 cm3 beaker. ●● Use the measuring cylinder to measure 10.0 cm3 of FA 2. ●● Add the FA 2 to the FA 1 in the beaker and start timing immediately. ●● Stir the mixture once and place the beaker on the printed insert. ●● Look down through the solution in the beaker at the print on the insert. ●● Stop timing as soon as the precipitate of sulfur makes the print on the insert just invisible. ●● Record this reaction time to the nearest second in your results table. ●● Empty the contents of the beaker into the quenching bath. ●● Wash out the beaker thoroughly. ●● Shake the beaker to remove any excess water. Experiment 2 ●● Fill a second burette with distilled water. ●● Refill the burette labelled FA 1 with FA 1. ●● Run 20.00 cm3 of FA 1 into the 100 cm3 beaker. ●● Run 25.00 cm3 of distilled water into the same beaker. ●● Use the measuring cylinder to measure 10.0 cm3 of FA 2. ●● Add the FA 2 to the FA 1 in the beaker and start timing immediately. ●● Stir the mixture once and place the beaker on the printed insert. ●● Look down through the solution in the beaker at the print on the insert. ●● Stop timing as soon as the precipitate of sulfur makes the print on the insert just invisible. ●● Record this reaction time to the nearest second in your results table. ●● Empty the contents of the beaker into the quenching bath. ●● Wash out the beaker thoroughly. ●● Shake the beaker to remove any excess water. Experiments 3–5 Carry out three further experiments to investigate how the reaction time changes with different volumes of FA 1. Note that the combined volume of FA 1 and distilled water must always be 45.00 cm3. Do not use a volume of FA 1 that is less than 20.00 cm3. Record all your results in a table. You should include the volume of FA 1, the volume of distilled water, the reaction time and the reaction rate for each of your five experiments. The rate of reaction can be calculated using the following expression. 500 rate = reaction time I II III IV V VI VII VIII IX [9] (b) On the grid, plot a graph of the rate (y-axis) against the volume of FA 1 (x-axis). Label any anomalous points. Draw a line of best fit. I II III IV [4] (c) In these experiments, the volume of FA 1 is related to the concentration of the thiosulfate ions. From your graph state the relationship between the rate of reaction and the concentration of the thiosulfate ions. . …… . …… [1] (d) Assume that the error in the time measured for each experiment was ± 2 s. Calculate the minimum value for the reaction rate you observed in Experiment 2. Show your working. minimum rate for Experiment 2 = …… [2] (e) (i) A student suggested that, using a 250 cm3 beaker, the time recorded for Experiment 1 would be the same. Discuss whether the student is correct. . …… . …… [1] (ii) A student carried out a further experiment using the same procedure as in (a). The student used 5.00 cm3 of FA 1, 40.00 cm3 of distilled water and 10.0 cm3 of FA 2. The print on the insert never became invisible. Explain why. . …… . …… [1] [Total: 18]
Mark scheme
1(a) I Constructs a table for results 1 4 columns, 2 rows (or vice versa) No data needed for this mark. II Correct headings and units given on page 4. 1 (Volume of) FA 1 and (Volume of distilled) water in cm3 or / cm3 or (cm3) (reject ml) Time in seconds or /s or (s). Rate in s–1 or / s–1 or (s–1) (reject 1 / s) Ignore 500. III Precision of readings 1 All times recorded to the nearest second and all volumes of FA 1 and water recorded to the nearest 0.05 cm3. A minimum of 4 experiments must be carried out and these must include volumes of FA 1 = 45.00 and 20.00 cm3 for this mark. IV 3 additional volumes chosen with intervals not less than 5.00 cm3 and all volumes of FA 1 ⩾ 25.00 cm3 1 (Allow 4 extra expts: 25, 30, 35, 40 cm3) V In all 3 additional experiments water is added to make a total of 45.00 cm3 (i.e. total FA 1 + water) 1 VI Reaction times all decreasing as volume of FA 1 increases for all five experiments. 1 Calculate the ratio t20 / t45 to 2 dp. If either/both expts 1 and 2 are omitted then VII and VIII are not available. VII Award 1 mark for ratio between 2.10 and 2.60. 1 VIII Award 2 marks for ratio between 2.20 and 2.50. 1 IX All rates correctly calculated using 500/ time for at least 3 expts. 1 All recorded to a minimum of 2 sf. 1(b) I Rate on y-axis and volume of FA 1 on the x-axis and some numbers for scales and 1 with unambiguous names or units. II Linear scales chosen so that the graph occupies more than half the available length for both axes (count origin if included 1 only if used by a point or extrapolation to x- or y-axis) (7 vertical, 5 horizontal big squares used) III All points recorded and accurately plotted. 1 (A point needed for all rates calculated, minimum 4 rates) If the point should be on a line it must be on the line. If the point should not be on a line it must not be on a line and must be correct to within half a small square. IV Line of best fit drawn (straight or smoothly curved line) 1 Ignore points marked anomalous 1(c) Answer must match candidate’s graph. 1 (Rate is) proportional (to conc of thiosulfate) 1(d) I Shows use of: time for experiment 2 (20 cm3) and time +2 or –2 (or ±2 or shows use of 2) 1 500 1 II Shows use of: (candidate time for expt 2) + 2 1(e)(i) Concludes: Time would be greater AND 1 as depth of solution is less or sulfur is spread over a larger (cross-sectional) area. 1(e)(ii) Concludes: Not enough S / ppt / solid is produced (to obscure insert) 1