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Chemistry 9701/52 May/June 2020: question paper and mark scheme

Cambridge AS & A Level Chemistry (9701), Paper 5 Planning, Analysis and Evaluation, May/June 2020. Read both free below, or download them. Done the paper? Get it marked by AI against this mark scheme.

9701_s20_qp_529701_s20_ms_529701/52/M/J/20

Paper
Paper 5 Planning, Analysis and Evaluation
Total marks
30
Questions
2
Code on the paper
9701/52/M/J/20
9701_s20_ms_52.pdf

9701/52 mark scheme, question by question

Each question as it's printed, and the mark scheme's points for it, as text. Diagrams, tables and graphs are in the PDFs above.

Question 113 marks

Question

A student plans to carry out an experiment to find the relative molecular mass, Mr, of a soluble acidic gas, X, by finding the mass of a measured volume of gas X. Gas X can be prepared by the reaction between concentrated sulfuric acid and copper. Two methods of gas collection are available to the student, as shown. concentrated concentrated gas sulfuric acid sulfuric acid syringe measuring cylinder copper copper turnings turnings gas X clamp water heat heat beehive water shelf trough method A method B (a) (i) Explain why the first sample of gas collected from either apparatus should not be used for the Mr determination of gas X. . …… . …… [1] (ii) Give two reasons, other than your answer to (a)(i), why, for this experiment, the apparatus in method A is less suitable than the apparatus in method B for collecting a sample of gas X. reason 1 . …… . …… reason 2 . …… . …… [2] (b) The student is told to use the U-tube shown to find the mass of a sample of gas X. gas X U-tube gas syringe soda lime A 100.0 cm3 sample of pure gas X is placed in a gas syringe. The gas syringe is attached to a U-tube containing small lumps of solid soda lime, a mixture of sodium hydroxide and calcium hydroxide. All of gas X is slowly passed into the U-tube and the mass of gas X absorbed determined. The temperature and the pressure of the room are recorded. (i) State the measurements that are needed to determine the mass of gas X absorbed. . …… . …… [1] (ii) Suggest why soda lime is used to absorb gas X. . …… . …… [1] (c) Gas X can cause respiratory distress. State an appropriate precaution that should be taken when doing this experiment. . …… . …… [1] (d) Experiment 1 is carried out at a temperature of 21 °C, a pressure of 9.8 × 104 Pa, and uses 100 cm3 of pure gas X. (i) Calculate the number of moles of gas X present in Experiment 1. You should assume that gas X behaves like an ideal gas and so use PV = nRT. R = 8.31 J K–1 mol–1 moles of gas X = …… mol [2] (ii) The sample of gas X is found to have a mass of 0.251 g. Explain how the student should use this information and their results to determine the Mr of X. . …… . …… . …… [1] (iii) Not all of gas X is absorbed by the soda lime. State what effect, if any, this has on the student’s calculated value of the Mr of gas X. . …… . …… [1] (iv) In Experiment 2, the same mass of gas X is used, but the student did not record the temperature and pressure. The calculated Mr of X for Experiment 2 is higher than the value calculated by the student for Experiment 1. P State and explain how the value of changes from Experiment 1 to Experiment 2. T . …… . …… . …… [1] (e) State how the reliability of the results in Experiment 1 could be improved. . …… . …… [1] (f) A different gas, methylamine, is alkaline. State a change that would have to be made to the apparatus so that the Mr of methylamine could be determined. . …… . …… [1] [Total: 13]

Mark scheme

1(a)(i) The sample will contain air from the apparatus OR gas mixture not pure gas 1 1(a)(ii) M1 Gas is soluble so should not be collected over water 1 M2 There is a danger of suck-back 1 1(b)(i) Mass of U-tube + soda lime before the experiment 1 AND Mass of U-tube + soda lime after the experiment 1(b)(ii) Soda lime is alkaline / a neutralisation reaction will occur. 1 1(c) Carry out the experiment in a fume cupboard 1 1(d)(i) M1 use of correct T (294 K) and V (100 × 10–6 m3) 1 M2 Correct use of pV = nRT (9.8 × 104 × 100 × 10–6 / 8.31 × 294) = 4.01 × 10–3 1 1(d)(ii) divide mass of X by the number of moles calculated in (d)(i) 1 OR 0.251/ 1(d)(i) = 62.6 1(d)(iii) (Smaller mass of gas X absorbed, so) lower Mr value 1 1(d)(iv) P/T is less 1 AND Because if Mr is higher, n is less and therefore P/T is less 1(e) Repeat the experiment (×3) and take an average 1 1(f) Replace the soda lime with an acid (to absorb the alkaline gas) 1

Question 217 marks

Question

Each student in a class of nine students performs an experiment to find the formula of a chloride of iron. Each student prepares the chloride of iron by passing a stream of chlorine gas over a sample of iron wire as shown in the diagram. excess chlorine gas iron wire dry chlorine gas chloride heat of iron (a) Each student carries out the following steps in the order shown in the list. Some of the measurement steps are missing from the list. ●● Weigh the reaction tube containing a quantity of iron wire. ●● Set up the apparatus as shown in the diagram. ●● Start the flow of dry chlorine gas. ●● Heat the iron wire until it has completely reacted. ●● Allow the apparatus to cool, with chlorine gas still flowing. ●● Weigh the side-arm conical flask containing the chloride of iron. (i) State the two additional measurement steps that each student must perform in order to find the formula of the chloride of iron. 1 . …… 2 . …… [1] (ii) The flow of dry chlorine gas must start before the iron wire is heated. Explain why. . …… . …… [1] (iii) State an assumption that has to be made for the measurements made in this experiment to be valid. . …… . …… [1] (b) (i) The class results are shown in the table. mass of mass of mass of amount amount of student iron wire iron chloride chlorine of iron chlorine atoms /g /g /g / mol / mol 1 0.57 1.64 2 1.10 3.16 3 1.40 4.03 4 1.95 5.61 5 2.18 5.89 6 2.75 7.90 7 3.05 8.77 8 3.45 9.80 9 3.90 11.18 Calculate the mass of chlorine that reacts with the iron wire in each experiment. Record each mass to two decimal places. Calculate the amount of iron, in mol, and amount of chlorine atoms, in mol, that reacts in each experiment. Record the number of moles to three significant figures. [Ar: Fe, 55.8; Cl, 35.5] [3] (ii) Plot a graph on the grid of the amount of chlorine atoms against the amount of iron. Use a cross (×) to plot each data point. Draw a line of best fit through the plotted points. You should consider whether (0,0) should be on the line of best fit. [2] 0.22 0.20 0.18 0.16 0.14 0.12 amount of chlorine atoms 0.10 / mol 0.08 0.06 0.04 0.02 0.00 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 amount of iron / mol (iii) Circle the point on the graph you consider to be most anomalous. Suggest one reason why this anomaly may have occurred during this experimental procedure. . …… . …… [2] (c) Use the graph to determine the gradient of the line of best fit. State the coordinates of both points you used in your calculation. These must be on your line of best fit. Give your answer to three significant figures. coordinates 1 …… coordinates 2 …… gradient = …… [2] (d) The formula of the chloride of iron produced in this experiment is FeCl 3. State how the results student 4 obtains could be used to determine this formula. . …… . …… . …… [1] (e) (i) Student 3 weighs the conical flask using a balance accurate to two decimal places and records its mass. After the chloride of iron is produced the mass increases by 4.03 g. Calculate the percentage error in measuring the mass of this chloride of iron. percentage error = …… % [1] (ii) Student 8 follows the same procedure as student 3. State whether the results from student 8 will have more or less percentage error than those from student 3. Explain your answer. . …… . …… [1] (f) Another student suggested that the chloride of iron could also be prepared by the reaction between iron wire and hydrochloric acid. (i) A sample of a chloride of iron prepared in this way contains 44% iron by mass. Show that the formula of this chloride of iron is FeCl 2. [Ar: Fe, 55.8; Cl, 35.5] [1] (ii) Explain, using the electrode potential values in the table, why the methods in (a) and (f) do not produce the same chlorides of iron. electrode reaction potential, Eo / V Fe2+(aq) + 2e– Fe(s) –0.44 2H+(aq) + 2e– H2(g) 0.00 Fe3+(aq) + e– Fe2+(aq) +0.77 . …… . …… . …… . …… [1] [Total: 17]

Mark scheme

2(a)(i) The mass of the empty reaction tube 1 AND The mass of the empty side-arm conical flask 2(a)(ii) The iron could react with oxygen or air (instead of the chlorine) 1 2(a)(iii) any one from: 1 • The mass of air in the flask is equal to mass of chlorine in the flask • All the iron (wool) has reacted • Any residue in the reaction tube is iron 2(b)(i) 3 Student Mass of Mass of Mass of Moles Moles of iron / g iron chlorine / of iron chlorine chloride / g g 1 0.57 1.64 1.07 0.0102 0.0301 2 1.10 3.16 2.06 0.0197 0.0580 3 1.40 4.03 2.63 0.0251 0.0741 4 1.95 5.61 3.66 0.0349 0.103 5 2.18 5.89 3.71 0.0391 0.105 6 2.75 7.90 5.15 0.0493 0.145 7 3.05 8.77 5.72 0.0547 0.161 8 3.45 9.80 6.35 0.0618 0.179 9 3.90 11.18 7.28 0.0699 0.205 M1 Mol of iron (column 5) M2 Mol of chlorine (column 6) [ M3 all entries to 3 SF 2(b)(ii) 2 M1 5 points plotted correctly M2 Line of best fit drawn 2(b)(iii) M1 Circle around the point at 0.0391,0.105 1 M2 Viable reason why the number of moles of chlorine is too small. 1 e.g. not all the mass of iron chloride formed was collected in the conical flask OR Iron chloride dust particles escaped with excess chlorine gas 2(c) M1 Coordinates read and recorded correctly 1 M2 Gradient calculated 1 2(d) Calculate the moles of each element and find the mole ratio 1 2(e)(i) 2 x 0.005/4.03 x 100 = 0.248% 1 2(e)(ii) Lower percentage error 1 AND Larger mass used 2(f)(i) (55.8/126.8) x 100 = 44.0 1 OR empirical formula calculation 44/55.8 : 56/35.5 0.7885 : 1.5775 1 : 2 FeCl2 2(f)(ii) In method (f) conversion of Fe to Fe2+ takes place as Eϴcell is + 0.44V 1 AND Conversion of to Fe2+ to Fe3+ is not feasible as Eϴcell is – 0.77V

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Where can I find the 9701/52 May/June 2020 mark scheme?

On this page, free: the mark scheme for AS & A Level Chemistry 9701/52, May/June 2020 (9701_s20_ms_52), and the question paper (9701_s20_qp_52), to read or download, with each question's marking points written out underneath.

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Chemistry 9701/52 for May/June 2020 is out of 30 marks, across 2 questions.

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