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Chemistry 9701/12 October/November 2022: question paper and mark scheme

Cambridge AS & A Level Chemistry (9701), Paper 1 Multiple Choice, October/November 2022. Read both free below, or download them. Done the paper? Get it marked by AI against this mark scheme.

9701_w22_qp_129701_w22_ms_129701/12/O/N/22

Paper
Paper 1 Multiple Choice
Total marks
40
Time
1 hour 15 minutes
Code on the paper
9701/12/O/N/22
9701_w22_ms_12.pdf

9701/12 answers, question by question

Each question and its answer from the key, as text. Diagrams and graphs are in the question paper above.

Question 11 mark

Question

Why is the first ionisation energy of phosphorus greater than the first ionisation energy of silicon? A A phosphorus atom has one more proton in its nucleus. B The atomic radius of a phosphorus atom is greater. C The outer electron in a phosphorus atom is more shielded. D The outer electron in a phosphorus atom is paired.

Answer

A

Question 21 mark

Question

Sodium peroxide, Na2O2, is used to absorb carbon dioxide from the atmosphere and release oxygen in closed environments such as space capsules and submarines. 2Na2O2 + 2CO2 → 2Na2CO3 + O2 Which mass of sodium peroxide would be required to remove 2.4 dm3 of carbon dioxide from the atmosphere at room temperature and pressure? A 2.4 g B 3.9 g C 7.8 g D 15.6 g

Answer

C

Question 31 mark

Question

In which species are the numbers of protons, neutrons and electrons all different? 27 35 − 32 2 − 39 + A 13 Al B 17 Cl C 16 S D 19 K

Answer

D

Question 41 mark

Question

Calcium oxide and magnesium sulfide each react with acid. CaO(s) + 2H+(aq) → Ca2+(aq) + H2O(l) MgS(s) + 2H+(aq) → Mg2+(aq) + H2S(g) A mixture of these two compounds, X, reacts with exactly 0.125 mol of dilute hydrochloric acid. The amount of hydrogen sulfide formed is 0.0250 mol. What was the mass of calcium oxide in mixture X? A 1.4 g B 2.1 g C 2.8 g D 4.2 g

Answer

B

Question 51 mark

Question

Two moles of VO2+ ions react with one mole of zinc atoms in the presence of dilute acid. The products include Zn2+ ions and an ion, Y. Ion Y contains vanadium. Only zinc and vanadium change oxidation state in the reaction. What is ion Y? A VO3– B VO+ C VO2+ D VO22+

Answer

C

Question 61 mark

Question

The compound potassium bismuthate(V), KBiO3, is a powerful oxidising agent. What is the significance of the (V) in potassium bismuthate(V)? A It is the oxidation number of the bismuth atom. B It is the charge of the bismuthate ion. C It is the oxidation number of the bismuthate ion. D It is the sum of the charges of the two ions present.

Answer

A

Question 71 mark

Question

Hydrogen peroxide decomposes slowly at 20 °C to form water and oxygen. 2H2O2 2H2O + O2 equilibrium constant = Kc The reaction is faster when a catalyst is present. Which statement is correct? A The catalyst alters the Boltzmann distribution so that the reactant molecules have more energy. B The catalyst has no effect on the value of Kc. C The catalyst increases the value of Kc. D The catalyst provides a different reaction mechanism with a higher activation energy.

Answer

B

Question 81 mark

Question

A dimer, Q, is stable when solid but a dynamic equilibrium is set up in solution. Q(aq) 2R(aq) A solution of Q has an initial concentration of 0.50 mol dm–3. When equilibrium has been reached, [Q(aq)] has fallen to 0.25 mol dm–3. The changes in [Q(aq)] and [R(aq)] are plotted against time until equilibrium is reached. The value of Kc is then calculated. Which graph and value for Kc are correct? graph Kc / mol dm–3 0.5 Q 0.4 concentration 0.3 A / mol dm–3 1 0.2 0.1 R 0 0 time 0.5 Q 0.4 concentration 0.3 B / mol dm–3 0.25 0.2 0.1 R 0 0 time 0.5 Q 0.4 concentration 0.3 C 1 / mol dm–3 0.2 0.1 R 0 0 time 0.5 Q 0.4 concentration 0.3 D 2 / mol dm–3 0.2 0.1 R 0 0 time

Answer

C

Question 91 mark

Question

The reaction pathway for the forward reaction of a reversible reaction is shown. 30 energy / kJ mol–1 50 progress of reaction Which statement is correct? A The activation energy of the reverse reaction is +80 kJ mol–1. B The enthalpy change for the forward reaction is +30 kJ mol–1. C The enthalpy change for the forward reaction is +50 kJ mol–1. D The enthalpy change for the reverse reaction is +30 kJ mol–1.

Answer

A

Question 101 mark

Question

The enthalpy changes for the possible reactions W, X, Y and Z are given. W NaOH(aq) + HCl (aq) → NaCl (aq) + H2O(l) ΔH o = –56 kJ mol–1 X NaCl (aq) + H2O(l) → NaOH(aq) + HCl (aq) ΔH o = +56 kJ mol–1 Y 2HI(g) → H2(g) + I2(g) ΔH o = +11 kJ mol–1 Z H2(g) + I2(g) → 2HI(g) ΔH o = –11 kJ mol–1 Which statement about the activation energies of these reactions is correct? A X is greater than W; Z is greater than Y. B X is greater than W; Y is greater than Z. C W is greater than X; Z is greater than Y. D W is greater than X; Y is greater than Z.

Answer

B

Question 111 mark

Question

The Haber process is carried out with a nitrogen partial pressure of 50 kPa, a hydrogen partial pressure of 150 kPa, a temperature of 400 °C and an iron catalyst. N2(g) + 3H2(g) 2NH3(g) If all other conditions are kept the same, which change will result in a raised activation energy? A Both the nitrogen and hydrogen partial pressures are changed to 100 kPa. B The iron is removed. C The nitrogen partial pressure is increased to 150 kPa. D The temperature is increased to 500 °C.

Answer

B

Question 121 mark

Question

The compound (CH3)3NAl Cl 3 has a simple molecular structure. Which statement about (CH3)3NAl Cl 3 is correct? A (CH3)3NAl Cl 3 molecules attract each other by hydrogen bonds. B The Al atom in (CH3)3NAl Cl 3 has an incomplete valence shell of electrons. C The bonds around the Al atom are planar. D The molecules contain coordinate bonding.

Answer

D

Question 131 mark

Question

VSEPR theory should be used in answering this question. The dot-and-cross diagram for an ozone, O3, molecule is shown. O O O What is the predicted bond angle in this molecule? A 107° B 109.5° C 117° D 120°

Answer

C

Question 141 mark

Question

Each of the substances shown is gaseous. Which substance is most likely to show ideal behaviour in the conditions shown? temperature pressure substance /K / Pa A carbon dioxide 250 1.00 × 105 B hydrogen chloride 1000 1.00 × 106 C nitrogen 1000 1.00 × 105 D oxygen 250 1.00 × 106

Answer

C

Question 151 mark

Question

Which graph represents the variation of pressure p and volume V of a sample of an ideal gas at constant temperature? A B p p 0 0 0 0 V V C D p p 0 0 0 0 V V

Answer

D

Question 161 mark

Question

Use relevant enthalpy changes from the tables to answer this question. reaction ΔH / kJ mol–1 C(s) + 2H2(g) → CH4(g) –76 CH4(g) + 2O2(g) → CO2(g) + 2H2O(g) –890 CH4(g) → C(g) + 4H(g) 1648 3C(s) + 4H2(g) → C3H8(g) –105 bond enthalpy bond / kJ mol–1 H–H 436 C–C 350 C=C 610 C=O 805 Which value can be calculated for the enthalpy change for the following reaction? 2C(g) + 6H(g) → C2H6(g) A –2822 kJ mol–1 B –2122 kJ mol–1 C –1998 kJ mol–1 D –1772 kJ mol–1

Answer

A

Question 171 mark

Question

Element X requires strong heating to react with oxygen. Element X reacts with chlorine to give a covalently-bonded chloride. What could be the identity of element X? A magnesium B phosphorus C sodium D silicon

Answer

D

Question 181 mark

Question

The melting points of the Period 3 elements sodium to aluminium are shown in the table. element Na Mg Al melting point / K 371 923 932 Which factor explains the increase in melting points from sodium to aluminium? A the change in first ionisation energy from sodium to aluminium B the increase in electronegativity from sodium to aluminium C the increase in the Ar of the elements from sodium to aluminium D the increase in the number of outer electrons in each atom from sodium to aluminium

Answer

D

Question 191 mark

Question

The nitrates of beryllium, calcium, magnesium and strontium all decompose in the same way when heated. When 2.00 g of one of these anhydrous nitrates is decomposed, 1.32 g of gas is produced. What is the nitrate? A beryllium nitrate B calcium nitrate C magnesium nitrate D strontium nitrate

Answer

B

Question 201 mark

Question

In the diagram, each test-tube W, X, Y and Z contains 25 cm3 of a 0.1 mol dm–3 solution of a salt. W X Y Z 25 cm3 25 cm3 25 cm3 25 cm3 BaCl 2(aq) MgCl 2(aq) BaCl 2(aq) MgCl 2(aq) To test-tubes W and X, 25 cm3 of 0.1 mol dm–3 NaOH(aq) is added. To test-tubes Y and Z, 25 cm3 of 0.1 mol dm–3 H2SO4(aq) is added. In which of test-tubes W and X does the liquid have the higher pH and which of test-tubes Y and Z has the greater mass of precipitate? greater mass higher pH of precipitate A W Y B W Z C X Y D X Z

Answer

A

Question 211 mark

Question

What is the oxidation state of the chlorine-containing species that kills bacteria in drinking water? A –1 B +1 C +3 D +5

Answer

B

Question 221 mark

Question

Compound Q is a white crystalline solid which dissolves easily in water. When concentrated sulfuric acid is added to a dry sample of Q, steamy white fumes are formed. When these white fumes are passed into aqueous silver nitrate solution, a white precipitate forms. This precipitate is soluble in dilute ammonia solution. What is compound Q? A AgCl B NaBr C NaCl D PbBr2

Answer

C

Question 231 mark

Question

R is a solid. R fizzes when hydrochloric acid is added. R reacts with hot aqueous sodium hydroxide, giving off a gas which turns red litmus blue. What is the formula of R? A NH4CO3 B (NH4)2CO3 C (NH4)2HCO3 D (NH4)2SO4

Answer

B

Question 241 mark

Question

Photochemical smog is a type of air pollution produced in urban areas by the effect of sunlight on substances released from vehicle exhausts. Which mixture of primary pollutants leads to the formation of photochemical smog? A carbon dioxide and water vapour B carbon monoxide and unburnt hydrocarbons C nitrogen oxide and unburnt hydrocarbons D sulfur dioxide and water vapour

Answer

C

Question 251 mark

Question

T is an element in Period 3. The first ionisation energy of T is lower than that of the element with one less proton. The oxide of T does not react with water. What is the identity of T? A aluminium B silicon C sodium D sulfur

Answer

A

Question 261 mark

Question

The structure of tartaric acid is shown. tartaric acid OH O HO OH O OH Which statements about tartaric acid are correct? 1 A molecule of tartaric acid has more than one chiral centre. 2 The molecular formula of tartaric acid is C4H4O6. 3 One molecule of tartaric acid produces four hydrogen ions in aqueous solution. A 1, 2 and 3 B 1 and 2 only C 2 and 3 only D 1 only

Answer

D

Question 271 mark

Question

A carboxylic acid, P, has no chain isomers. It reacts with an alcohol, Q, that has only one positional isomer. What could be the ester formed from a reaction between P and Q? A butyl propanoate B ethyl butanoate C pentyl ethanoate D propyl pentanoate

Answer

A

Question 281 mark

Question

Which pair includes a hydrocarbon without a chiral centre? A CH3CH2CH2CH(CH3)CH2CH3 CH3CH(CH3)CH(CH3)CH2CH3 B CH3CH2CH2CH(CH2CH3)CH3 CH3CH2CH2CH(CH3)CH2CH3 C CH3CH2CH2CH(CH3)CH2CH3 CH3CH2CH(CH3)CH(CH3)2 D CH3CH(CH2CH3)CH(CH3)CH3 CH3CH(CH3)CH2CH(CH3)2

Answer

D

Question 291 mark

Question

What is the major product formed when compound R is warmed with an excess of HBr? R OH OH A B C D Br Br OH Br OH Br Br Br OH Br Br Br 30 cis-but-2-ene reacts with cold dilute acidified potassium manganate(VII) solution to give product X. cis-but-2-ene reacts with hot concentrated acidified potassium manganate(VII) solution to give product Y. Which row describing the reactions of X and Y is correct? when sodium metal is added to when sodium hydroxide solution is separate samples of X and Y added to separate samples of X and Y A both X and Y will react neither X nor Y will react B both X and Y will react only one of X and Y will react C only one of X and Y will react neither X nor Y will react D only one of X and Y will react only one of X and Y will react

Answer

A

Question 301 mark

Question

In the question paper above.

Answer

B

Question 311 mark

Question

For which reaction will the major organic product have the lowest relative molecular mass? A Bromoethane is heated under reflux with an aqueous solution of sodium hydroxide. B Bromoethane is heated under reflux with a solution of sodium cyanide in ethanol. C 2-bromopropane is heated under reflux with an aqueous solution of sodium hydroxide. D 2-bromopropane is heated under reflux with concentrated ethanolic sodium hydroxide.

Answer

D

Question 321 mark

Question

C4H9Cl reacts with warm dilute aqueous sodium hydroxide solution. Which isomer of C4H9Cl will form the most stable cation intermediate? A 1-chlorobutane B 2-chlorobutane C 1-chloro-2-methylpropane D 2-chloro-2-methylpropane 33 1.0 mol of an organic compound, J, requires 6.0 mol of oxygen for complete combustion. 1.0 mol of J reacts with sodium, producing 0.50 mol of a gas that gives a ‘pop’ with a lighted splint. J reacts with an excess of hot acidified potassium manganate(VII) to produce an organic compound which gives an orange-red precipitate with 2,4-DNPH reagent. Which compound is J? A but-1-ene B butan-2-ol C propan-2-ol D 2-methylpropan-2-ol

Answer

D

Question 331 mark

Question

In the question paper above.

Answer

B

Question 341 mark

Question

Structural isomerism and stereoisomerism should be considered when answering this question. 3-methylhexan-3-ol reacts with hot concentrated sulfuric acid to form several isomeric compounds with the molecular formula C7H14. 3-methylhexan-3-ol HO How many isomeric compounds could be formed in this reaction? A 3 B 4 C 5 D 6

Answer

C

Question 351 mark

Question

The table shows a student’s predictions for the reactions of three compounds. alkaline Fehling’s Tollens’ compound I2(aq) reagent reagent key 1 O = reaction occurs = no reaction O 2 O 3 Which rows show the correct predictions? A 1, 2 and 3 B 1 and 2 only C 1 and 3 only D 2 and 3 only

Answer

A

Question 361 mark

Question

Which mechanism describes the reaction of aldehydes and ketones with HCN + NaCN? A electrophilic addition B electrophilic substitution C nucleophilic addition D nucleophilic substitution

Answer

C

Question 371 mark

Question

Propyl propanoate can be synthesised in three steps using propanenitrile as the only organic starting material. In step 1, the nitrile is converted into compound X. In step 2, compound X is converted into compound Y. In step 3, compound Y is reacted with more of compound X to give propyl propanoate. step 1 step 2 step 3 CH3CH2CN X Y CH3CH2CO2CH2CH2CH3 Which reagents are suitable for carrying out step 1 and step 2? step 1 step 2 A HCl (aq) conc. H2SO4 B HCl (aq) LiAl H4 C NaOH(aq) conc. H2SO4 D NaOH(aq) NaBH4

Answer

B

Question 381 mark

Question

The ester CH3CH2CO2CH3 is hydrolysed by boiling with aqueous sodium hydroxide. Which compound is one of the products? A ethanol B propan-1-ol C sodium methanoate D sodium propanoate

Answer

D

Question 391 mark

Question

Compound V polymerises to form polymer W. A section of polymer W is shown. polymer W polymerisation Cl Cl Cl Cl Cl Cl V Cl Cl Cl What is the correct name of compound V? A 1,1,2-trichlorobutene B 1,1,2-trichloroethene C 1,1,2-trichloropropene D 1,1,2-trichloro-2-methylethene

Answer

C

Question 401 mark

Question

A molecule of an organic compound, P, contains three carbon atoms and shows a strong absorption at 1720 cm–1 in its infrared spectrum. P is reacted with an excess of hot acidified potassium dichromate(VI) forming organic product Q. Q shows a strong absorption at 1700 cm–1 and a strong, broad absorption centred at 2800 cm–1 in its infrared spectrum. bond functional group containing the bond characteristic infrared absorption range (in wavenumbers) / cm–1 C–O hydroxy, ester 1040–1300 C=C aromatic compound, alkene 1500–1680 C=O amide 1640–1690 carbonyl, carboxyl 1670–1740 ester 1710–1750 C≡N nitrile 2200–2250 C–H alkane 2850–2950 N–H amine, amide 3300–3500 O–H carboxyl 2500–3000 hydroxy 3200–3600 What is P? A propanal B propanone C propan-1-ol D propan-2-ol Important values, constants and standards molar gas constant R = 8.31 J K–1 mol–1 Faraday constant F = 9.65 × 104 C mol–1 Avogadro constant L = 6.022 × 1023 mol–1 electronic charge e = –1.60 × 10–19 C molar volume of gas Vm = 22.4 dm3 mol–1 at s.t.p. (101 kPa and 273 K) Vm = 24.0 dm3 mol–1 at room conditions ionic product of water Kw = 1.00 × 10–14 mol2 dm–6 (at 298 K (25 °C)) specific heat capacity of water c = 4.18 kJ kg–1 K–1 (4.18 J g–1 K–1) The Periodic Table of Elements Group 1 2 13 14 15 16 17 18 1 2 H He hydrogen helium Key 1.0 4.0 3 4 atomic number 5 6 7 8 9 10 Li Be atomic symbol B C N O F Ne lithium beryllium name boron carbon nitrogen oxygen fluorine neon 6.9 9.0 relative atomic mass 10.8 12.0 14.0 16.0 19.0 20.2 11 12 13 14 15 16 17 18 Na Mg Al Si P S Cl Ar sodium magnesium aluminium silicon phosphorus sulfur chlorine argon 23.0 24.3 3 4 5 6 7 8 9 10 11 12 27.0 28.1 31.0 32.1 35.5 39.9 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 at www.cambridgeinternational.org after the live examination series. K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr potassium calcium scandium titanium vanadium chromium manganese iron cobalt nickel copper zinc gallium germanium arsenic selenium bromine krypton 39.1 40.1 45.0 47.9 50.9 52.0 54.9 55.8 58.9 58.7 63.5 65.4 69.7 72.6 74.9 79.0 79.9 83.8 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 20 Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe rubidium strontium yttrium zirconium niobium molybdenum technetium ruthenium rhodium palladium silver cadmium indium tin antimony tellurium iodine xenon 85.5 87.6 88.9 91.2 92.9 95.9 – 101.1 102.9 106.4 107.9 112.4 114.8 118.7 121.8 127.6 126.9 131.3 55 56 57–71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 lanthanoids Cs Ba Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po At Rn caesium barium hafnium tantalum tungsten rhenium osmium iridium platinum gold mercury thallium lead bismuth polonium astatine radon 132.9 137.3 178.5 180.9 183.8 186.2 190.2 192.2 195.1 197.0 200.6 204.4 207.2 209.0 – – – 87 88 89–103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 actinoids Fr Ra Rf Db Sg Bh Hs Mt Ds Rg Cn Nh Fl Mc Lv Ts Og francium radium rutherfordium dubnium seaborgium bohrium hassium meitnerium darmstadtium roentgenium copernicium nihonium flerovium moscovium livermorium tennessine oganesson – – – – – – – – – – – – – – – – – 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 lanthanoids La Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu lanthanum cerium praseodymium neodymium promethium samarium europium gadolinium terbium dysprosium holmium erbium thulium ytterbium lutetium 138.9 140.1 140.9 144.4 – 150.4 152.0 157.3 158.9 162.5 164.9 167.3 168.9 173.1 175.0 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 actinoids Ac Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No Lr actinium thorium protactinium uranium neptunium plutonium americium curium berkelium californium einsteinium fermium mendelevium nobelium lawrencium – 232.0 231.0 238.0 – – – – – – – – – – – Assessment International Education Copyright Acknowledgements Booklet. This is produced for each series of examinations and is freely available to download To avoid the issue of disclosure of answer-related information to candidates, all copyright acknowledgements are reproduced online in the Cambridge

Answer

A

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Where can I find the 9701/12 October/November 2022 mark scheme?

On this page, free: the mark scheme for AS & A Level Chemistry 9701/12, October/November 2022 (9701_w22_ms_12), and the question paper (9701_w22_qp_12), to read or download, with each question's marking points written out underneath.

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Chemistry 9701/12 for October/November 2022 is out of 40 marks, with 1 hour 15 minutes to answer it.

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Yes. Upload your answers to 9701/12/O/N/22 as a PDF or photos, and CIE Buddy marks every question against this paper's official mark scheme, using Cambridge's marking rules. You get your score, each lost mark explained on your own script, and the topics to revise. It's a guide, not an official Cambridge grade.