Question 115 marks
Question
Group 1 elements form salts with ethanedioic acid. These salts are ethanedioates and have the formula (COOM)2•2H2O, where M is the Group 1 metal. Ethanedioate ions react with manganate(VII) ions as shown. 5(COO–)2(aq) + 2MnO4–(aq) + 16H+(aq) → 10CO2(g) + 2Mn2+(aq) + 8H2O(l) You will determine which metal is present in (COOM)2•2H2O by titrating a solution of this salt with manganate(VII) ions. FA 1 is 10.14 g dm–3 aqueous hydrated ethanedioate of metal M, (COOM)2•2H2O. FA 2 is 0.0200 mol dm–3 potassium manganate(VII), KMnO4. FA 3 is 1 mol dm–3 sulfuric acid, H2SO4. (a) Method ● Fill the burette with FA 2. ● ipette 25.0 cm3 of FA 1 into a conical flask. P ● Use the measuring cylinder to add approximately 20 cm3 of FA 3 into the conical flask. ● Place the conical flask on a tripod and gauze and heat carefully until the temperature of the solution is approximately 70 °C. ● Remove the flame. ● Carefully lift the hot conical flask and place it on the white tile under the burette. ● During titrations, add FA 2, slowly at first, until a permanent pale pink colour is formed. The pink colour on initial addition may take several seconds to disappear. ● If the reaction mixture turns brown, reheat it to about 70 °C. If the brown colour disappears, continue with the titration. If the brown colour remains, discard the contents of the flask and begin a new titration. ● Perform a rough titration with FA 2. Record your burette readings in the space below. The rough titre is …… cm3. ● Carry out as many accurate titrations as you think necessary to obtain consistent results. ● Make sure any recorded results show the precision of your practical work. ● Record in a suitable form below all your burette readings and the volume of FA 2 added in each accurate titration. I II III IV V VI VII [7] (b) From your accurate titration results, calculate a suitable mean value to be used in your calculations. Show clearly how you obtained this value. 25.0 cm3 of FA 1 required …… cm3 of FA 2. [1] (c) Calculations (i) Give your answers to (c)(ii), (c)(iii) and (c)(iv) to the appropriate number of significant figures. [1] (ii) Calculate the amount, in mol, of manganate(VII) ions, MnO4–, in the volume of FA 2 calculated in (b). amount of MnO4– = …… mol [1] (iii) Calculate the amount, in mol, of ethanedioate ions that reacted with the manganate(VII) ions in (c)(ii). amount of (COO–)2 = …… mol Hence calculate the concentration, in mol dm–3, of ethanedioate ions in FA 1. concentration of (COO–)2 = …… mol dm–3 [1] (iv) Calculate the relative formula mass, Mr, of the hydrated ethanedioate, (COOM)2•2H2O. Mr = …… [1] (v) Identify M. Show your working. M is …… . [2] (d) Explain why it is necessary to add FA 3 in each titration. . …… . …… [1] [Total: 15] Question 2 starts on the next page.
Mark scheme
1(a) I all the following data recorded 7 • two burette readings and titre for rough titration • initial and final burette readings for two (or more) accurate titrations II titre values shown for accurate titrations and appropriate headings and units in the accurate titration table • initial / start and (burette) reading / volume • final / end and (burette) reading / volume • titre or volume / FA 2 and used / added • unit: /cm3 or (cm3) or in cm3 (for each heading) or cm3 unit given for each volume recorded III all accurate burette readings are to nearest 0.05 cm3 IV the final accurate titre recorded is within 0.10 cm3 of any other accurate titre V, VI, VII award V if δ ⩽ 0.60 (cm3) award VI if δ ⩽ 0.40 (cm3) award VII if δ ⩽ 0.20 (cm3) where δ is the difference between the supervisor’s and candidate’s mean titre 1(b) candidate calculates mean correctly to 2 decimal places (dp) 1 • candidate must take the average of two (or more) titres that are within a total spread of not more than 0.20 cm3 • working / explanation must be shown or ticks must be put next to the two (or more) accurate readings selected • the mean should be quoted to 2 dp and be rounded to the nearest 0.01 cm3 1(c)(i) significant figures (sf) 1 all quoted answers in (c)(ii) – (c)(iv) are expressed to 3 or 4 sf 1(c)(ii) correctly calculates amount of MnO4− used 1 0.02 × vol in (b) amount of MnO4− = (mol) 1000 1(c)(iii) correctly uses equation and converts volume 1 amount of (COO−)2 that reacted = (c)(ii) × 5 (mol) 2 and concentration of (COO−)2 in FA 1 = amount of (COO−)2 × 1000 (mol dm−3) 25 1(c)(iv) correctly uses Mr = mass 1 moles Mr = 10.14 concentration from (c)(iii) 1(c)(v) identity of M 2 M from (c)(iv) − 124 M1: Ar of M = r 2 M2: identifies M as being the Group 1 element with the nearest Ar (Li ⩽ 14.9; 15.0 ⩽ Na ⩽ 31.0; 31.1 ⩽ K ⩽ 62.3; 62.3 ⩽ Rb ⩽ 111.4; 111.4 ⩽ Cs ⩽ 250) 1(d) explanation for use of acid 1 to provide H+ and for the reaction (to proceed) / as given in the equation / to acidify the KMnO4