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Mathematics 0580/23 May/June 2019: question paper and mark scheme

Cambridge IGCSE Mathematics (0580), Paper 2 (Extended), May/June 2019. Read both free below, or download them. Done the paper? Get it marked by AI against this mark scheme.

0580_s19_qp_230580_s19_ms_230580/23/M/J/19

Paper
Paper 2 (Extended)
Total marks
70
Time
1 hour 30 minutes
Code on the paper
0580/23/M/J/19
0580_s19_ms_23.pdf

0580/23 mark scheme, question by question

Each question as it's printed, and the mark scheme's points for it, as text. Diagrams, tables and graphs are in the PDFs above.

Question 11 mark

Question

Write 1.8972 correct to 2 decimal places. …… [1]

Mark scheme

1 1.90 cao 1

Question 21 mark

Question

Factorise 2x 2 - x . …… [1]

Mark scheme

2 x(2x – 1) 1

Question 31 mark

Question

Giulio’s reaction times are measured in two games. In the first game his reaction time is 13 of a second. In the second game his reaction time is 18 of a second. Find the difference between the two reaction times. …… s [1]

Mark scheme

3 5 1 or 0.208 or 0.2083… 24

Question 41 mark

Question

The table shows the different methods of travel for 20 people going to work. Method of travel Frequency Car 10 Walk 5 Bike 3 Bus 2 Which type of average, mean, median or mode, can be used for this information? …… [1]

Mark scheme

4 Mode 1

Question 52 marks

Question

(a) Find the co-ordinates of the point where the line y = 3x - 8 crosses the y-axis. (…… , ……) [1] (b) Write down the gradient of the line y = 3x - 8 . …… [1]

Mark scheme

5(a) (0, –8) 1 5(b) 3 1

Question 62 marks

Question

Calculate. (a) - 12 ' - 2 …… [1] 3 (b) 23 + 2 …… [1]

Mark scheme

6(a) 6 1 6(b) 2.15 or 2.154… 1

Question 72 marks

Question

Here is a list of numbers. 2 21 3 13 31 121 51 0.7 From this list, write down (a) a prime number, …… [1] (b) an irrational number. …… [1]

Mark scheme

7(a) 31 or 121 1 7(b) 13 1

Question 82 marks

Question

The scatter diagram shows the number of people and the number of phones in each of 8 buildings. 70 60 50 40 Number of phones 30 20 10 0 0 10 20 30 40 50 60 70 80 Number of people (a) One of the buildings contains 42 people. Write down the number of phones in this building. …… [1] (b) What type of correlation is shown in the scatter diagram? …… [1] 12 7

Mark scheme

8(a) 32 1 8(b) Positive 1

Question 92 marks

Question

Without using a calculator, work out # . 35 9 You must show all your working and give your answer as a fraction in its simplest form. …… [2]

Mark scheme

9 84 4 7 12 1 4 1 M1 Accept any correct cancelling or × or × or × 315 35 3 5 9 5 3 4 A1 cao 15

Question 102 marks

Question

Rearrange 2 (w + h) = P to make w the subject. w = …… [2]

Mark scheme

10 P P − 2h 2 P [w =] – h or final M1 for w + h = or 2w + 2h = P 2 2 2 answer

Question 112 marks

Question

Complete this statement with an expression in terms of m. 18m 3 + 9m 2 + 14m + 7 = (9m 2 + 7) (……) [2]

Mark scheme

11 2m + 1 2 B1 for 2m + c or km + 1 (k ≠ 0)

Question 122 marks

Question

NOT TO SCALE 217° 6.2 cm The diagram shows a sector of a circle with radius 6.2 cm and sector angle 217°. Calculate the area of this sector. …… cm2 [2]

Mark scheme

12 72.8 or 72.79 to 72.80… 2 217 M1 for × π × 6.22 360

Question 133 marks

Question

6 cm NOT TO SCALE 4 cm The diagram shows a pyramid with a square base. The triangular faces are congruent isosceles triangles. (a) Write down the number of planes of symmetry of this pyramid. …… [1] (b) Using a ruler and compasses only, construct an accurate drawing of one of the triangular faces of the pyramid. [2]

Mark scheme

13(a) 4 1 13(b) Accurate drawing with correct 2 B1 for accurate drawing without the correct construction arcs arcs

Question 143 marks

Question

One solution of the equation ax 2 + a = 150 is x = 7 . (a) Find the value of a. a = …… [2] (b) Find the other solution. x = …… [1]

Mark scheme

14(a) 3 2 M1 for a × 72 + a = 150 oe 14(b) –7 1

Question 153 marks

Question

A is the point (7, 12) and B is the point (2, - 1) . Find the length of AB. …… [3] b#h

Mark scheme

15 13.9 or 13.92 to 13.93 3 ( 7 − 2 ) + (12 − −1) 2 2 M2 for oe or M1 for ( 7 − 2 ) + (12 − −1) oe 2 2

Question 163 marks

Question

A= 2 A = 10 , correct to the nearest whole number. h = 4 , correct to the nearest whole number. Work out the upper bound for the value of b. …… [3] x 3 + 5x 2

Mark scheme

16 6 nfww 3 B1 for 10 + 0.5 or 4 – 0.5 soi 2A M1 for [b = ] soi h

Question 173 marks

Question

Simplify , giving your answer as a single fraction. x 2 - 25 …… [3]

Mark scheme

17 x2 3 B1 for x2(x + 5) final answer B1 for (x – 5)(x + 5) x −5

Question 183 marks

Question

y is inversely proportional to the square of (x + 1) . y = 0.875 when x = 1. Find y when x = 4 . y = …… [3]

Mark scheme

18 0.14 oe 3 k M1 for y = ( x + 1)2 their k M1 for y = ( 4 + 1)2 OR 0.875 (1 + 1) 2 M2 for ( 4 + 1)2 or M1 for y(4 + 1)2 = 0.875(1 + 1)2

Question 194 marks

Question

K J 104° N NOT TO SCALE M d° 22° L J, K, L and M are points on the circumference of a circle with diameter JL. JL and KM intersect at N. Angle JNK = 104° and angle MLJ = 22° . Work out the value of d. d = …… [4]

Mark scheme

19 36 4 B1 for angle KNL or MNJ = 76 B2 for angle LJM or LKM = 68 or B1 for angle LMJ = 90 or LKJ = 90 or LCM = 136 (C = centre) OR B1 for MKJ = 22 B2 for LJM or LKM = 68 or B1 for LKJ = 90 or KJL = 54 OR B1 for MNL = 104 B1 for LMN = 54 B1 for LMJ = 90

Question 204 marks

Question

(a) 40 children were asked if they have a computer or a phone or both. The Venn diagram shows the results. Have a computer Have a phone 7 8 23 2 (i) A child is chosen at random from the children who have a computer. Write down the probability that this child also has a phone. …… [1] (ii) Complete the Venn diagram. Do not have a computer Do not have a phone [2] (b) In this Venn diagram, shade the region ( A , Bl ) + C . A B C [1] 3 4 1 4

Mark scheme

20(a)(i) 8 1 oe 15 20(a)(ii) E Do not have Do not have 2 B1 for 2 or 3 correct out of 4 regions a computer a phone 23 2 7 8 20(b) E 1 A B C

Question 214 marks

Question

A =e o B =e o 5 0 -3 2 Find (a) 5A, f p [1] (b) A + B , f p [1] (c) AB. f p [2]

Mark scheme

21(a)  15 20  1    25 0  21(b) 4 8 1    2 2 21(c)  −9 20  2 B1 for two correct elements    5 20 

Question 224 marks

Question

D C N t NOT TO SCALE A s B ABCD is a parallelogram. N is the point on BD such that BN : ND = 4 : 1. AB = s and AD = t . Find, in terms of s and t, an expression in its simplest form for (a) BD, BD = …… [1] (b) CN . CN = …… [3]

Mark scheme

22(a) –s+t 1 22(b) 4 1 3 M2 for correct unsimplified e.g. – s – t oe simplified 4 1 5 5 – t + ( −s + t ) or – s – ( −s + t ) 5 5 JJJG JJJG or M1 for a correct route e.g. CB + BN JJJG 4 or [ BN = ] ( −s + t ) or 5 JJJG 1 [ DN =] – ( −s + t ) 5

Question 235 marks

Question

160 students record the amount of time, t hours, they each spend playing computer games in a week. This information is shown in the cumulative frequency diagram. 160 140 120 100 Cumulative 80 frequency 60 40 20 0 0 2 4 6 8 10 12 t Time (hours) (a) Use the diagram to find an estimate of (i) the median, …… hours [1] (ii) the interquartile range. …… hours [2] (b) Use the diagram to complete this frequency table. Time (t hours) 01tG2 21tG4 41tG6 61tG8 8 1 t G 10 10 1 t G 12 Frequency 20 24 12 4 [2]

Mark scheme

23(a)(i) 5 1 23(a)(ii) 2.4 to 2.6 2 B1 for [LQ=] 3.4 to 3.6 or [UQ=] 6 23(b) 26, 74 2 B1 for each

Question 245 marks

Question

y 8 7 6 5 4 3 2 1 –5 –4 –3 –2 –1 0 1 2 3 4 5 6 7 8 x –1 –2 By shading the unwanted regions of the grid, draw and label the region R which satisfies the following three inequalities. yG2 x13 y G x+4 [5]

Mark scheme

24 Correct lines and region indicated 5 B1 for y = 2 solid line B1 for x = 3 dashed line B1 for y = x + 4 solid line B2, B1 or B0 for region

Question 256 marks

Question

K J NOT TO E SCALE D A O F C B H G The diagram shows two regular pentagons. Pentagon FGHJK is an enlargement of pentagon ABCDE, centre O. (a) Find angle AEK. Angle AEK = …… [4] (b) The area of pentagon FGHJK is 73.5 cm2. The area of pentagon ABCDE is 6 cm2. Find the ratio perimeter of pentagon FGHJK : perimeter of pentagon ABCDE in its simplest form. …… : …… [2]

Mark scheme

25(a) 126 4 360 − 180 – ( 360 ÷ 5 )  M3 for or 2 360 − 180 × ( 5 − 2 ) ÷ 5 2 180 × ( 5 − 2 ) 360 or M2 for or 180 – 5 5 360 or M1 for 180 × (5 – 2) or 5 25(b) 7:2 2 73.5 6 M1 for or 6 73.5

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Where can I find the 0580/23 May/June 2019 mark scheme?

On this page, free: the mark scheme for IGCSE Mathematics 0580/23, May/June 2019 (0580_s19_ms_23), and the question paper (0580_s19_qp_23), to read or download, with each question's marking points written out underneath.

How many marks is 0580/23 out of?

Mathematics 0580/23 for May/June 2019 is out of 70 marks, with 1 hour 30 minutes to answer it.

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Yes. Upload your answers to 0580/23/M/J/19 as a PDF or photos, and CIE Buddy marks every question against this paper's official mark scheme, using Cambridge's marking rules. You get your score, each lost mark explained on your own script, and the topics to revise. It's a guide, not an official Cambridge grade.