Question 11 mark
Question
Write down the temperature that is 7 °C below -3 °C. …… °C [1]
Mark scheme
1 –10 1
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Cambridge IGCSE Mathematics (0580), Paper 2 (Extended), October/November 2019. Read both free below, or download them. Done the paper? Get it marked by AI against this mark scheme.
0580_w19_qp_230580_w19_ms_230580/23/O/N/19
Each question as it's printed, and the mark scheme's points for it, as text. Diagrams, tables and graphs are in the PDFs above.
Question
Write down the temperature that is 7 °C below -3 °C. …… °C [1]
Mark scheme
1 –10 1
Question
Calculate 256 0.25 + 4 # 8 . …… [1]
Mark scheme
2 6 1
Question
Here is a list of numbers. 87 77 57 47 27 From this list, write down (a) a cube number, …… [1] (b) a prime number. …… [1]
Mark scheme
3(a) 27 1 3(b) 47 1
Question
Find the highest common factor (HCF) of 84 and 105. …… [2]
Mark scheme
4 21 2 M1 for [84 =] 2 × 2 × 3 × 7 or [105 =] 3 × 5 × 7 or 3 × 7 as final answer or B1 for 3 or 7 as final answer
Question
Write in standard form. (a) 72 000 …… [1] (b) 0.0018 …… [1]
Mark scheme
5(a) 7.2 × 104 1 5(b) 1.8 × 10–3 1
Question
Expand and simplify (x + 3) (x + 5) . …… [2]
Mark scheme
6 x2 + 8x + 15 final answer 2 M1 for three terms correct from x2 + 3x + 5x + 15
Question
Find the gradient of the line that is perpendicular to the line 2y = 3 + 5x. …… [2]
Mark scheme
7 2 2 5 − or – 0.4 M1 for gradient = oe soi 5 2
Question
When sin x° = 0.36, find (a) the acute angle x°, …… [1] (b) the obtuse angle x°. …… [1]
Mark scheme
8(a) 21.1 or 21.10… 1 8(b) 158.9 or 158.8 to 158.9 1 FT 180 – their (a) providing answer is an obtuse angle
Question
A cuboid measures 5 cm by 7 cm by 9.5 cm. NOT TO SCALE 7 cm 5 cm 9.5 cm Work out the surface area of this cuboid. …… cm2 [3]
Mark scheme
9 298 3 M2 for [2 ×] (5 × 7 + 5 × 9.5 + 7 × 9.5) oe or M1 for one correct area, 5 × 7 or 5 × 9.5 or 7 × 9.5
Question
5n is the mean of the three numbers 391, n and n - 1. Find the value of n. n = …… [3]
Mark scheme
10 30 3 391 + n + n −1 M1 for = 5n oe 3 M1 for correct first step for solving their equation 390 + 2 n e.g. 391+ n + n −1 = 3 × 5n , = 5n 3
Question
Factorise. (a) 12x + 15 …… [1] (b) xy - 2x + 3y - 6 …… [2]
Mark scheme
11(a) 3(4x + 5) final answer 1 11(b) (x + 3)(y – 2) final answer 2 B1 for y(x + 3) – 2(x + 3) or x(y – 2) + 3(y – 2) or correct answer seen then spoilt
Question
A is the point (2, 1) and B is the point (9, 4). Find the length of AB. …… [3]
Mark scheme
12 7.62 or 7.615 to 7.616 3 M2 for ( 9 − 2 )2 + ( 4 − 1)2 oe or M1 for ( 9 − 2 ) + ( 4 − 1) oe or 58 2 2
Question
A straight line joins the points (3k, 6) and (k, -5). The line has a gradient of 2. Find the value of k. k = …… [3]
Mark scheme
13 2.75 oe 3 M2 for 6 − −5 = 2 ( 3k − k ) oe or better 6 − −5 or M1 for oe 3k − k If 0 scored, SC1 for − 2.75 oe as answer
Question
Find the nth term of each sequence. 1 1 1 1 1 (a) , , , , , ... 2 4 6 8 10 …… [1] (b) 1, 5, 25, 125, 625, ... …… [2] 2 1 2
Mark scheme
14(a) 1 1 oe final answer 2n 14(b) 5n – 1 oe final answer 2 M1 for recognition of terms being powers of 5
Question
Without using a calculator, work out + # . 3 4 3 Write down all the steps of your working and give your answer as a fraction in its simplest form. …… [4]
Mark scheme
15 2 1 1 2 1 M1 M1 for correct first step to deal with oe or × 1 + multiplication 12 2 3 3 4 8 2 2 5 M1 M1 for correct working for common [ + ] oe × 2 12 12 3 4 denominator with their oe or correct 12 evaluation of bracket 5 A2 10 cao A1 for oe 6 12
Question
Ten athletes compete in both the 100 metre race and the triple jump. Their results are shown in the scatter diagram. 13.4 13.3 13.2 13.1 13.0 Time for 100 m 12.9 (seconds) 12.8 12.7 12.6 12.5 12.4 14.5 14.6 14.7 14.8 14.9 15.0 15.1 15.2 15.3 15.4 15.5 Distance in the triple jump (m) (a) One of these athletes jumps 15.12 m in the triple jump. Write down his time for the 100 metre race. …… s [1] (b) The values for two other athletes are shown in the table. Distance in the 14.74 15.2 triple jump (m) Time for 100 m 13.2 12.76 (seconds) On the scatter diagram, plot these points. [1] (c) On the scatter diagram, draw a line of best fit. [1] (d) What type of correlation is shown in the scatter diagram? …… [1]
Mark scheme
16(a) 12.88 1 16(b) two correct points plotted 1 16(c) ruled line of best fit 1 16(d) negative 1
Question
y 7 6 5 4 3 2 1 –5 –4 –3 –2 –1 0 1 2 3 4 5 x –1 –2 –3 –4 –5 By shading the unwanted regions on the grid, draw and label the region R that satisfies the following inequalities. -2 1 x G 3 y G x+3 [4]
Mark scheme
17 4 B1 for x = –2 dashed ruled line and x = 3 solid ruled line B1 for y = x + 3 solid ruled line B2 for indication of correct region or B1 for shading that satisfies two of the inequalities, e.g. two of x > –2, x ⩽ 3 and y⩽x+3
Question
(a) M = {x | x is an integer and 2 G x 1 6} (i) Find n(M). …… [1] (ii) Write down a set N where N 1 M and N ! Q . { …… } [1] (b) In each Venn diagram, shade the required region. C D A B (A , B)l E (C + D l ) , E [2]
Mark scheme
18(a)(i) 4 1 18(a)(ii) At least one and fewer than four 1 numbers from {2, 3, 4, 5} 18(b) E 2 B1 for each A B E C D E
Question
18 16 14 12 10 Speed (m/s) 8 6 4 2 0 0 10 20 30 40 50 60 70 Time (s) The diagram shows the speed–time graph for 70 seconds of a car journey. (a) Calculate the deceleration of the car during the first 20 seconds. …… m/s2 [1] (b) Calculate the total distance travelled by the car during the 70 seconds. …… m [3]
Mark scheme
19(a) 3 1 0.3 or 10 19(b) 760 3 M2 for correct complete area statement 1 e.g. 70 × 10 + × 20 × 6 oe 2 or M1 for one of these area calculations 1 70 × 10, × 20 × 6, 50 × 10 or 2 1 × (16 + 10) × 20 2
Question
t is inversely proportional to the square of (x + 1). When x = 2, t = 5. (a) Write t in terms of x. t = …… [2] (b) When t = 1.8, find the positive value of x. x = …… [2] - 3 10
Mark scheme
20(a) 45 2 k final answer M1 for t = ( x + 1) 2 ( x + 1)2 20(b) 4 2 M1 for 1.8 × (x + 1)2 = their 45 or better
Question
(a) Work out the inverse of the matrix e o. 1 -5 f p [2] (b) Work out the value of x and the value of y in this matrix calculation. 1 5 -4 1 x 46 e oe o=e o 2 y 2 9 6 65 x = …… y = …… [3]
Mark scheme
21(a) 1 −5 −10 2 −5 −10 oe isw M1 for k or det = 5 soi 5 −1 −3 −1 −3 21(b) [x = ] 6 3 B1 for x = 6 [y = ] 7 B2 for y = 7 or M1 for 2 × 1 + 9y = 65 or 2 × − 4 + 2y = 6
Question
A container is made from a cylinder and a cone, each of radius 5 cm. The height of the cylinder is 12 cm and the height of the cone is 4.8 cm. 4.8 cm NOT TO 12 cm SCALE 5 cm The cylinder is filled completely with water. The container is turned upside down as shown below. NOT TO SCALE d Calculate the depth, d, of the water. 1 [The volume, V, of a cone with radius r and height h is V = rr 2 h.] 3 d = …… cm [5] Question 23 is printed on the next page.
Mark scheme
22 15.2 5 M4 for 2 1 2 π × 5 × 12 − × π × 5 × 4.8 ÷ π × 5 3 (2 ) 1 or M3 for π × 52 × 12 − × π × 52 × 4.8 3 or M1 for π × 52 ×12 1 M1 for × π × 52 × 4.8 3
Question
The time, t minutes, it takes each of 50 students to travel to school is recorded. The table shows the results. Time (t minutes) 0 1 t G 10 10 1 t G 15 15 1 t G 20 20 1 t G 40 Frequency 7 19 16 8 (a) Write down the modal class. …… 1 t G …… min [1] (b) On the grid, complete the histogram to show the information in the table. 4 3 Frequency density 2 1 0 0 10 20 30 40 t Time (minutes) [3]
Mark scheme
23(a) 10 [< t ⩽] 15 1 23(b) Correct histogram 3 B1 for each correct block 4 If 0 scored, SC1 for correct frequency densities 3.8, 3.2, 0.4 soi by correct heights 3 2 1 0 t Time (minutes)
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Mathematics 0580/23 for October/November 2019 is out of 70 marks, with 1 hour 30 minutes to answer it.
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