Mathematics 0580/21 May/June 2024: question paper and mark scheme
Cambridge IGCSE Mathematics (0580), Paper 2 (Extended), May/June 2024. Read both free below, or download them. Done the paper? Get it marked by AI against this mark scheme.
y
8
7
6
A 5
4
3 C
2
1
B
–8 –7 –6 –5 –4 –3 –2 –1 0 1 2 x
3 4 5
–1
–2
The diagram shows two sides of a parallelogram ABCD.
Find the coordinates of point D.
( …… , …… ) [2]
Mark scheme
1 (–3, 7) 2 B1 for correct diagram
or correct coordinates for their point D
or for ( −3, k ) or ( k , 7 )
Geetha has a box of toys.
She picks a toy at random from the box.
The probability that she picks a wooden toy is 0.6 .
(a) Work out the probability that she does not pick a wooden toy.
…… [1]
(b) The box contains three types of toys, wooden, plastic or metal.
Type of toy Wooden Plastic Metal
Number of toys 14 14
Probability 0.6
Complete the table.
[2]
Mark scheme
2(a) 0.4 oe 1
2(b) 42 2 B1 for 42
0.2 0.2 B1 for 0.2 and 0.2
If B0 scored SC1 for their two probabilities
being half their (a)
The table shows some information about two sequences.
nth term 5th term
Sequence A 60 – 4n
Sequence B n2 – 300
(a) Complete the table.
[2]
(b) Find the smallest positive number in sequence B.
…… [2]
Mark scheme
3(a) 40 2 B1 for each
–275
3(b) 24 2 B1 for 324 or 289 or 300 or 17.3…
D
A 40° C
E
B
NOT TO
SCALE
x°
The diagram shows 5 kites that are congruent to kite ABCD.
Each kite is joined to the next kite along one edge.
Angle DAB = 40° and DCE is a straight line.
Find the value of x.
x = …… [3]
Mark scheme
6 145 3 M1 for 180 ÷ 6
or any angle congruent to BCD = 30
M1 for (360 – 40 – their 30) ÷ 2 oe
12.8 cm
J L
NOT TO
SCALE
12.8 cm
K
The diagram shows a shape made from a triangle JKL and a semicircle with diameter JL.
JKL is an isosceles right-angled triangle with JK = JL = 12.8 cm.
(a) Calculate the area of this shape.
…… cm2 [3]
(b) Calculate the perimeter of this shape.
…… cm [4]
Mark scheme
7(a) 146 or 146.2 to 146.3 3 1
M1 for × 12.8 × 12.8
2
2
1 12.8
M1 for × π ×
2 2
7(b) 51[.0] or 51.00 to 51.01… 4 1
M1 for × π ×12.8
2
12.8
M2 for 12.82 + 12.82 or oe
sin 45
or M1 for 12.82 + 12.82 oe
12.8
or sin 45 = oe
KL
Amir invests $1500 in an account.
The account pays compound interest at a rate of r % per year.
At the end of 8 years the value of his investment is $1656.73 .
Find the value of r.
r = …… [3]
Mark scheme
10 1.25 or 1.250… 3 1656.73
M2 for 8 oe
1500
or M1 for 1656.73 = 1500 ( k ) oe for any k
8
y
7
6
5
4
3
R
2
1
–1 0 x
1 2 3 4 5 6 7
–1
Find the inequalities that define the unshaded region, R.
…… [4]
Mark scheme
11 y<x 4 B1 for y < x
x<6 B1 for x < 6
1 ⩽ y ⩽ 5 oe B2 for 1 ⩽ y ⩽ 5
or B1 for y ⩾ 1 or y ⩽ 5
If B0 scored,
SC2 for y ⩽ x, x ⩽ 6 and 1 < y < 5 oe
or SC1 for three correct from
y = x, x = 6, y = 1 and y = 5
Solve the simultaneous equations.
You must show all your working.
3x
+ 5y = 5
2
4x - 3y = 46
x = ……
y = …… [4]
Mark scheme
12 Correctly equating one set of M1
coefficients
Correct method to eliminate one M1
variable
x = 10, y = –2 A2 A1 for x = 10
A1 for y = –2
If M0 scored SC1 for 2 values satisfying one of
the original equations.
48° NOT TO
SCALE
9 cm
The diagram shows a circle with radius 9 cm.
Calculate the area of the shaded major sector.
…… cm2 [3]
o o as a fraction in its simplest form.
Mark scheme
14 221 or 220.5 to 220.6 3 360 − 48
M2 for × π × 92
360
k
or M1 for × π × 92 where k < 360
360
or B1 for 312
y
8
7
6
5
4
3
2
1
– 3 – 2.5 – 2 – 1.5 – 1 – 0.5 0 0.5 1 1.5 x
–1
–2
–3
The diagram shows the graph of y = x 3 + 4x 2 - 2 for - 3 G x G 1.5 .
By drawing a suitable straight line, solve the equation x 3 + 4x 2 - 2 = 2x for - 3 G x G 1.5 .
x = …… or x = …… [3]
Mark scheme
18 y = 2x ruled B1
x = –0.5 to –0.55 B2 B1 for –0.5 to –0.55
x = 0.85 to 0.9 B1 for 0.85 to 0.9
Solve the equation 8 sin x + 6 = 1 for 0c G x G 360c.
x = …… or x = …… [3]
Mark scheme
20 218.7, 321.3 3 B2 for one correct
5
or M1 for sin x = – oe
8
If M1 or 0 scored, SC1 for two reflex angles
with a sum of 540 or two non-reflex angles with
a sum of 180
E 9.1 cm F
6.5 cm A B NOT TO
SCALE
H G
4 cm
D C
The diagram shows a cuboid.
HD = 4 cm, EH = 6.5 cm and EF = 9.1 cm.
Calculate the angle between CE and the base CDHG.
…… [4]
Mark scheme
21 33.2 or 33.18… 4 6.5
M3 for tan = oe
42 + 9.12
or M2 for 42 + 9.12 oe
or 42 + 9.12 + 6.52 oe
or M1 for recognising the angle ECH
Bag A and bag B each contain red counters and blue counters only.
Stephan picks a counter at random from bag A and Jen picks a counter at random from bag B.
The probability that Stephan picks a red counter is 0.4 .
The probability that Stephan and Jen both pick a red counter is 0.25 .
Find the probability that Stephan and Jen both pick a blue counter.
…… [4]
Mark scheme
22 0.225 oe 4 0.25
M3 for 1 – × (1 – 0.4 ) oe
0.4
OR
0.25
M2 for
0.4
or M1 for 0.4 × p = 0.25 oe
M1 for (1 –theirP(Jen red))×(1 – 0.4) oe
Checked your answers against these? Let AI mark the whole paper, on your own working.
Examiners follow the generic marking principles at the front of the scheme, then each question's points: method (M), accuracy (A) and independent (B) marks, error carried forward where the scheme allows it, and positive marking, so you're credited for what you got right.
Check your answers against it
Done this paper? Upload your script and CIE Buddy's AI marker marks it question by question against this exact scheme, puts the ticks on your own working and says what each lost mark needed.
Where can I find the 0580/21 May/June 2024 mark scheme?+
On this page, free: the mark scheme for IGCSE Mathematics 0580/21, May/June 2024 (0580_s24_ms_21), and the question paper (0580_s24_qp_21), to read or download, with each question's marking points written out underneath.
How many marks is 0580/21 out of?+
Mathematics 0580/21 for May/June 2024 is out of 70 marks, with 1 hour 30 minutes to answer it.
Can I get my 0580/21 answers marked?+
Yes. Upload your answers to 0580/21/M/J/24 as a PDF or photos, and CIE Buddy marks every question against this paper's official mark scheme, using Cambridge's marking rules. You get your score, each lost mark explained on your own script, and the topics to revise. It's a guide, not an official Cambridge grade.