Question 11 mark
Question
A concert starts at 19 50 and finishes 2 hours 42 minutes later. Work out the time the concert finishes. …… [1] 1
Mark scheme
1 22 32 or 10 32 pm 1
Mathematics 0580/21 October/November 2024: question paper and mark scheme
Cambridge IGCSE Mathematics (0580), Paper 2 (Extended), October/November 2024. Read both free below, or download them. Done the paper? Get it marked by AI against this mark scheme.
0580_w24_qp_210580_w24_ms_210580/21/O/N/24
- Paper
- Paper 2 (Extended)
- Total marks
- 70
- Time
- 1 hour 30 minutes
- Code on the paper
- 0580/21/O/N/24
0580/21 mark scheme, question by question
Each question as it's printed, and the mark scheme's points for it, as text. Diagrams, tables and graphs are in the PDFs above.
Question 21 mark
Question
Find the reciprocal of 1 . 4 …… [1]
Mark scheme
2 4 1 or 0.8 5
Question 32 marks
Question
Use one of the symbols 1, 2 or = to make each statement true. 2 …… 0.2861 7 99 …… 11% 900 1 3 …… 4 0 [2]
Mark scheme
3 < 2 B1 for two correct = =
Question 42 marks
Question
Safia has a piece of fabric of length 5.6 m. She cuts the fabric into two parts, with lengths in the ratio 3 : 4. Calculate the length of the longer part. …… m [2]
Mark scheme
4 3.2 2 5.6 M1 for [×k ] where k = 1, 3 or 4 3+ 4
Question 52 marks
Question
Work out. 6 (a) 3 e o -4 f p [1] 4 -7 (b) e o + e o -1 5 f p [1]
Mark scheme
5(a) 18 1 −12 5(b) −3 1 4
Question 63 marks
Question
The diagram shows a right-angled triangle ABC and a quadrilateral AEDC. C y° 17° NOT TO SCALE D z° 122° x° 34° A E B Find the value of (a) x x = …… [1] (b) y y = …… [1] (c) z. z = …… [1]
Mark scheme
6(a) 58 1 6(b) 39 1 6(c) 251 1
Question 71 mark
Question
Factorise. 28x - 35 …… [1]
Mark scheme
7 7(4x – 5) final answer 1
Question 82 marks
Question
Edith invests $3000 in a savings account. The account pays simple interest at a rate of 2.6% per year. Calculate the total interest earned at the end of 3 years. $ …… [2]
Mark scheme
8 234 2 3000 × 2.6 [×3] M1 for 100
Question 93 marks
Question
NOT TO `x + 132j ° SCALE x° The diagram shows part of a regular polygon. The interior angle of the polygon is 132° larger than the exterior angle. Calculate the number of sides of this polygon. …… [3]
Mark scheme
9 15 3 B2 for [x =] 24 OR M1 for x + x + 132 = 180 oe soi 360 M1 for oe provided this gives an their x integer answer
Question 103 marks
Question
Jacinda plays a game with her friend. She can win, lose or draw the game. The probability that she wins the game is 0.28 . (a) Jacinda is twice as likely to draw the game as to lose the game. Work out the probability that she loses the game. …… [2] (b) Jacinda plays the game 150 times. Find the expected number of times that she wins. …… [1] 1 4
Mark scheme
10(a) 0.24 oe 2 M1 for 1 – 0.28 oe 10(b) 42 1
Question 113 marks
Question
Without using a calculator, work out 5 - 3 . 3 7 You must show all your working and give your answer as a mixed number in its simplest form. …… [3]
Mark scheme
11 B1 Correct step for dealing with mixed numbers 16 25 1 4 or 2 − Allow 16k or 25k 3 7 3 7 3k 7k M1 Correct method to find common denominator 112 75 7 12 and [ 2] and e.g. 5 7 and 3 12 21 21 21 21 21 21 16 A1 1 cao 21
Question 123 marks
Question
Solve the simultaneous equations. You must show all your working. 5x + 6y = 9 3x - 2y = -17 x = …… y = …… [3]
Mark scheme
12 Correctly eliminating one variable M1 x = –3 A1 If A0 scored SC1 for 2 values satisfying one of the original equations. y=4 A1
Question 135 marks
Question
(a) A sequence has nth term 3n 2 - 1. Find the second term in this sequence. …… [1] (b) The table shows the first five terms of sequences A and B. 1st term 2nd term 3rd term 4th term 5th term nth term Sequence A –6 –2 2 6 10 Sequence B 3 17 55 129 251 Complete the table to show the nth term of each sequence. [4]
Mark scheme
13(a) 11 1 13(b) 4n –10 oe final answer 4 B2 for 4n – 10 oe final answer or B1 for 4n + j or kn − 10 (k ≠ 0) or 4n – 10 seen then spoilt and 2n3 + 1 oe final answer B2 for 2n3 + 1 oe final answer or B1 for any cubic expression in n or 3rd difference = 12 or for correct answer seen then spoilt
Question 144 marks
Question
Two solid steel statues are mathematically similar. The smaller statue has height 12 cm and the larger statue has height 15 cm. The larger statue has a mass 2.5 kg. The density of steel is 8 g/cm 3 . Calculate the volume of the smaller statue. [Density = mass ÷ volume.] …… cm 3 [4]
Mark scheme
14 160 4 2500 123 M3 for V ÷ = 3 oe 8 15 figs 25 12 3 or for answer figs 16 from × 3 8 15 or B2 for 1.28 [kg] OR M1 for 2500 ÷ 8 oe or 312.5 seen 3 3 12 15 M1 for or oe 15 12
Question 155 marks
Question
Students in class P take a test. These statistics show information about their marks. • lower quartile = 38 • median = 53 • interquartile range = 28 • range = 81 • highest mark = 96 (a) Draw a box-and-whisker plot to represent this information. 0 20 40 60 80 100 Test marks [3] (b) Students in class Q take the same test. For class Q, the median is 49 and the interquartile range is 35. Make two comments comparing the distribution of marks for class P with that of class Q. 1. …… 2. …… [2]
Mark scheme
15(a) Correct box-and-whisker plot 3 B1 for UQ = 66 or Lowest = 15 soi L = 15 M1 for at least 3 values correct within box and LQ = 38 whisker plot Median = 53 UQ = 66 H = 96 15(b) Class Q scored fewer marks on 2 B1 for each average [as median is lower] oe Class Q have a larger spread of marks [as IQR is higher] oe
Question 164 marks
Question
R cm NOT TO 6 cm SCALE 18 cm The diagram shows a sphere of radius 6 cm and a cylinder of height 18 cm and radius R cm. The volume of the sphere is equal to the volume of the cylinder. Calculate the curved surface area of the cylinder. Give your answer in terms of r. 4 [The volume, V, of a sphere with radius r is V = rr 3 ] 3 …… cm 2 [4]
Mark scheme
16 144 π cao 4 4 × π × 63 2 M2 for [ R =] 3 oe 18 × π 4 or M1 for × π × 63 = π × R 2 × 18 oe 3 M1 for 2 × π × theirR ×18 oe [ − −] 7 ± ([ −] 7 ) − 4 ( 3)( −16 ) ([ −] 7 ) − 4 ( 3) ( −16 ) ) or better
Question 174 marks
Question
Solve. 3x 2 - 7x - 16 = 0 You must show all your working and give your answers correct to 2 decimal places. x = …… or x = …… [4]
Mark scheme
17 2 B2 2 B1 for oe 2×3 p+ q p− q and if in the form or then r r B1 for p = – (–7) and r = 2(3) 3.75 and –1.42 B2 B1 for each or SC1 for answers 3.8 or 3.754… and –1.4 or –1.42… or –1.421 or 3.75 and –1.42 seen in working or –3.75 and 1.42 as final answers
Question 186 marks
Question
g (x) = 4 x + 3 (a) Find x when g (x) = 1. …… [1] 1o (b) Find g -1 e . 16 …… [2] 19 % = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10} P = {odd numbers} Q = {multiples of 3} R = {square numbers} (a) Find P + Q + R . { …… } [1] (b) (i) Find Q , R . { …… } [1] (ii) Find n `P + (Q , R)lj . …… [1]
Mark scheme
18(a) –3 1 18(b) –5 2 1 M1 for or 4–2 42
Question 19
Question
In the question paper above.
Mark scheme
19(a) 9 1 19(b)(i) 1, 3, 4, 6, 9 1 19(b)(ii) 2 1 FT 5 – numbers of odds in (b)(i)
Question 205 marks
Question
S 4 cm NOT TO SCALE 18 cm T 28° P Q R 9 cm The diagram shows two right-angled triangles PQS and RQT. PQR and QTS are straight lines. Calculate angle QTR. Angle QTR = …… [5]
Mark scheme
20 63.7 or 63.68 to 63.69 5 9 M4 for tan [QTR] = oe 18sin 28 − 4 OR M3 for 18sin28 – 4 or M2 for 18sin28 QS or M1 for = sin 28 oe 18 and 9 M1 for tan [QTR] = oe theirQT
Question 213 marks
Question
Solve the equation 3 tan x + 5 = 1 for 0° G x G 360° . x = …… or x = …… [3]
Mark scheme
21 126.9 and 306.9 3 B2 for one correct answer 4 or M1 for tan x = – oe 3 If M1 or 0 scored, SC1 for two angles with a difference of 180
Question 226 marks
Question
The graph of y = (x + 2) (x - 1) 2 is shown on the grid. y 4 3 2 1 -2 -1 0 1 2 x -1 (a) Show that y = (x + 2) (x - 1) 2 can be written as y = x 3 - 3x + 2 . [2] (b) By drawing a suitable straight line, solve the equation 2x 3 - 5x = 0 . x = …… or x = …… or x = …… [4] Question 23 is printed on the next page.
Mark scheme
22(a) x2 – x – x + 1 M1 or x2 + 2x– x – 2 A correct unsimplified expansion A1 e.g. x3 + 2x2 –x2 –2x – x2 –2x + x + 2 oe leading to [y = ] x3 – 3x + 2 22(b) y = 2 – 0.5x ruled B2 B1 for [y =] 2 – 0.5x soi or for y = 2 – kx drawn or for y = k – 0.5x drawn –1.5 to –1.6 B2 B1 for two correct values 0 1.5 to 1.6
Question 232 marks
Question
(x - 5) 2 + k = x 2 - px - 21 Find the value of p and the value of k. p = …… k = …… [2]
Mark scheme
23 [p = ] 10 2 B1 for each [k = ] –46
Checked your answers against these? Let AI mark the whole paper, on your own working.
Mark my 0580/21How this paper is marked
Examiners follow the generic marking principles at the front of the scheme, then each question's points: method (M), accuracy (A) and independent (B) marks, error carried forward where the scheme allows it, and positive marking, so you're credited for what you got right.
Check your answers against it
Done this paper? Upload your script and CIE Buddy's AI marker marks it question by question against this exact scheme, puts the ticks on your own working and says what each lost mark needed.
Other variants, October/November 2024
Find another Mathematics paper
Every IGCSE Mathematics mark schemeQuestion papers and mark schemes © Cambridge University Press & Assessment. CIE Buddy is independent and not connected to Cambridge.
0580/21 questions
Where can I find the 0580/21 October/November 2024 mark scheme?
On this page, free: the mark scheme for IGCSE Mathematics 0580/21, October/November 2024 (0580_w24_ms_21), and the question paper (0580_w24_qp_21), to read or download, with each question's marking points written out underneath.
How many marks is 0580/21 out of?
Mathematics 0580/21 for October/November 2024 is out of 70 marks, with 1 hour 30 minutes to answer it.
Can I get my 0580/21 answers marked?
Yes. Upload your answers to 0580/21/O/N/24 as a PDF or photos, and CIE Buddy marks every question against this paper's official mark scheme, using Cambridge's marking rules. You get your score, each lost mark explained on your own script, and the topics to revise. It's a guide, not an official Cambridge grade.