Biology 0610/32 February/March 2020: question paper and mark scheme
Cambridge IGCSE Biology (0610), Paper 3 Theory (Core), February/March 2020. Read both free below, or download them. Done the paper? Get it marked by AI against this mark scheme.
(a) Fig. 1.1 shows six species of reptiles.
A
B
C D
E F
Fig. 1.1
(i) Use the key to identify each species. Write the letter of each species (A–F) in the correct empty box beside the key.
Key:
organism has a shell (hard covering on
1 (a) go to 2 its back)
(b) organism does not have a shell go to 3
2 (a) organism has flat limbs (flippers) Caretta caretta
(b) organism has legs and feet Chelonoidis nigra
3 (a) organism has limbs go to 4
(b) organism has a long body and no limbs Crotalus viridis
4 (a) organism has ridges on its back go to 5
(b) organism has no ridges on its back Varanus bengalensis
5 (a) organism has a coiled tail Chamaeleo calyptratus
(b) organism has a straight tail Alligator mississippiensis
[5]
(ii) Define the term species.
…… [2]
(b) The binomial system of naming organisms tells us the species and the genus of the organism.
State the genus name for Chamaeleo calyptratus.
…… [1]
(c) Table 1.1 shows some features of animals.
Place ticks (✓) next to two features of most reptiles.
Table 1.1
compound eyes
fertilisation is internal
wings
lay eggs
moist skin
[2]
(d) State two features of cells that are shared by all living organisms.
1 ……
2 ……
[2]
[Total: 12]
Mark scheme
1(a)(i) 5 6 correct = 5 marks
4 or 5 correct = 4 marks
3 correct = 3 marks
2 correct = 2 marks
B 1 correct = 1 mark
E
C
F
D
A
;;;;;
1(a)(ii) a group of organisms ; 2
that reproduce to produce fertile offspring ;
1(b) Chamaeleo ; 1
1(c) ticks in the boxes for: 2 R each additional tick
fertilisation is internal ;
lay eggs ;
1(d) any two from: 2 apply list rule
genetic material ;
cytoplasm ;
cell membrane ;
AVP ;;
(a) A class of students measured their breathing rates during different activities.
Average breathing rates for the class were calculated.
Student A compared her own breathing rates to the average breathing rates of the class.
Fig. 2.1 shows the results.
25
Key:
20 student A breathing 15 rate
/ breaths 10 class average per minute
5
0 resting walking running type of activity
Fig. 2.1
(i) Compare student A’s results with the class averages.
…… [2]
(ii) Calculate the percentage increase in breathing rate between resting and running for student A.
Give your answer to the nearest whole number.
……%
[2]
(b) State two ways in which the composition of inspired air differs from expired air.
1 ……
2 ……
[2]
(c) Fig. 2.2 is a diagram of the human gas exchange system.
Fig. 2.2
Complete Fig. 2.2 by labelling these structures in the spaces provided:
• alveoli
• bronchus
• bronchiole
• diaphragm
• trachea.
[3]
(d) A large surface area is a feature of gas exchange surfaces.
State two other features of gas exchange surfaces.
1 ……
2 ……
[2]
[Total: 11]
Mark scheme
2(a)(i) student A has an overall lower breathing rate (for all activities) 2
/ student A’s breathing rate increased less than the class
average (for all activities) / AW ;
biggest difference in breathing rate is, walking / running ;
data quote with units ;
2(a)(ii) 67(%) ;; 2 MP1 – correct calculation
MP2 – correct rounding to a whole number
2(b) any two from: 2 apply list rule
contains more oxygen ;
contains less carbon dioxide ;
contains less water (vapour) ;
2(c) correctly labelled diagram ;;; 3 5 correct = 3 marks
3 or 4 correct = 2 marks
left side in this order: right side in this order: 1 or 2 correct = 1 mark
bronchus trachea
bronchiole diaphragm
alveoli
2(d) any two from : 2
thin ;
ventilated ;
good blood supply ;
AVP ;; e.g. small diffusion distance / moist / AW
(a) The length of hair in cats is controlled by a single gene.
• The allele for short hair is dominant – H
• The allele for long hair is recessive – h
Fig. 3.1 is a photograph of two cats.
cat A cat B
Fig. 3.1
(i) Table 3.1 shows some of the genetic and physical features of the cats in Fig. 3.1.
Complete Table 3.1.
Table 3.1
cat A cat B
phenotype long hair ……
genotype …… HH or ……
[3]
(ii) State the genotype of a pure-breeding short-haired cat.
…… [1]
(iii) Two cats with the genotypes HH and hh were bred together.
Predict the percentage of offspring that are heterozygous.
……% [1]
(b) The statements describe features of continuous or discontinuous variation.
Identify the type of variation each statement describes.
Write the letter C for continuous variation or D for discontinuous variation in the spaces provided.
Height is an example of this type of variation. ……
There are no intermediate phenotypes with this type of variation. ……
This type of variation results in a limited number of phenotypes. ……
[2]
(c) A student wrote a definition of variation as:
‘the similarities between individuals of the same kingdom’.
Identify the two incorrect words in the student’s definition.
1 ……
2 ……
[2]
[Total: 9]
Mark scheme
3(a)(i) 3
cat A cat B
phenotype long hair short hair ;
genotype hh ; HH or Hh ;
3(a)(ii) HH ; 1
3(a)(iii) 100 (%) ; 1
3(b) C 2 all 3 correct = 2 marks
D 2 or 1 correct = 1 mark
D
;;
3(c) similarities ; 2 apply list rule
kingdom ; either order
(a) A study estimated the percentage effectiveness of different types of birth control.
Table 4.1 shows examples of four different categories of birth control:
• barrier
• chemical
• natural
• surgical.
Table 4.1
example of birth control category percentage effectiveness
abstinence 100
contraceptive injection 94–99
femidom 79–95
IUS chemical 99
vasectomy 100
(i) Complete Table 4.1 to show the different categories of each example of birth control.
One has been done for you. [4]
(ii) State the two most effective examples of birth control from Table 4.1.
…… [1]
(iii) State two examples of birth control from Table 4.1 that prevent the spread of sexually transmitted infections (STIs).
1 ……
2 ……
[2]
(b) Complete the sentences about STIs using words from the list.
Each word can be used once, more than once or not at all.
AIDS bacteria blood food
infection ingesting injecting
pregnancy sexually variation virus
…… transmitted infections are transmitted via body fluids.
Human immunodeficiency …… is an example of an STI.
HIV can be transmitted through transfusions of contaminated ……
and by …… drugs.
HIV infection may eventually lead to …… .
[5]
[Total: 12]
Mark scheme
4(a)(i) 4
example of birth control category
abstinence natural ;
contraceptive injection chemical ;
femidom barrier ;
IUS chemical
vasectomy surgical ;
4(a)(ii) abstinence and vasectomy ; 1
4(a)(iii) abstinence ; 2 apply list rule
femidom ; either order
4(b) sexually ; 5
virus ;
blood ;
injecting ;
AIDS ;
(a) Fig. 5.1 is a photograph of a giant panda.
Fig. 5.1
State the name of the vertebrate group that giant pandas belong to.
…… [1]
(b) Giant pandas live in mountainous regions in central China.
Researchers estimated the numbers of giant pandas in these areas over several years.
The results are shown in Fig. 5.2.
2500
2000 estimated
1500 number of giant pandas
1000
500
0
1977 1988 2003 2014 year
Fig. 5.2
The population of giant pandas was at its lowest in 1988.
(i) State the estimated number of giant pandas in 1988.
…… [1]
(ii) Calculate the change in population size of giant pandas between 1977 and 2014.
…… [1]
(c) In 1988 the population size became so low that giant pandas were considered an endangered species.
Suggest reasons why species such as the giant panda become endangered.
…… [4]
(d) Giant pandas are no longer endangered due to successful conservation programmes.
Suggest how conservation programmes have helped to increase numbers of giant pandas.
…… [3]
[Total: 10]
Mark scheme
5(a) mammal(s) ; 1
5(b)(i) 1100 ; 1
5(b)(ii) (2450 – 1900) = 550 (giant pandas) ; 1 A 540 to 560
5(c) climate change / e.g. of effect ; 4
habitat destruction ;
hunting / specimen collection ;
pollution / e.g. of ;
introduced species ;
disease ;
AVP ;; e.g. lack of food / natural disasters / war
/ (increased or new) predation
5(d) monitoring / protecting, species ; 3
protecting habitat ;
education ;
captive breeding programmes ;
zoos / wildlife parks ;
AVP ;; e.g. providing food / legislation / laws to protect species
/ ban hunting
(a) Complete the definition of the term transpiration.
Transpiration is the loss of water vapour from plant leaves by ……
of water at the surfaces of the …… cells followed by diffusion of
water vapour through the …… .
[3]
(b) Fig. 6.1 is a graph showing how temperature affects water loss in a plant with many leaves.
water loss
temperature
Fig. 6.1
(i) Half of the leaves were removed from the plant.
Predict the effect on water loss in this plant and sketch a line on Fig. 6.1 to show your prediction. [2]
(ii) Describe the effect of humidity on the rate of transpiration.
…… [1]
(c) Water is an important substance for plants.
(i) Describe two uses of water in plants.
1 ……
2 ……
[2]
(ii) State the name of the vessels that transport water in plants.
…… [1]
(iii) State the name of the cells where water enters a plant.
…… [1]
[Total: 10]
Mark scheme
6(a) evaporation ; 3
mesophyll ;
stomata / stoma ;
6(b)(i) line drawn under existing trend line ; 2
in the same pattern ;
6(b)(ii) as humidity increases the rate of transpiration decreases ; ora 1
6(c)(i) as a solvent ; 2 A transport nutrients
(a reactant for) photosynthesis ;
to support cells / plant ;
6(c)(ii) xylem ; 1
6(c)(iii) root hair (cell) ; 1
(a) Fig. 7.1 is a diagram of the alimentary canal and associated organs.
A
B
C
D
E
Fig. 7.1
The boxes on the left show the letters on Fig. 7.1.
The boxes in the middle show some of the names of the parts in Fig. 7.1.
The boxes on the right show the functions of the parts.
Draw lines to link each part with its correct letter and function.
letter on name of
Fig. 7.1 the part function
A anus contains hydrochloric acid to kill bacteria
B mouth production of amylase, protease and lipase
C pancreas production of saliva
salivary
D site of egestion glands
E stomach site of ingestion
[6]
(b) The anus is part of the large intestine.
State the names of two other parts of the large intestine.
1 ……
2 ……
[2]
(c) State where mechanical digestion occurs in the alimentary canal.
…… [1]
(d) Protein and fats are two of the components of a balanced diet.
State the names of three other components of a balanced diet.
1 ……
2 ……
3 ……
[3]
[Total: 12]
Mark scheme
7(a) 6 for each column of lines:
5 correct links = 3 marks
contains hydrochloric 3 or 4 correct links = 2 marks
A anus
acid to kill bacteria 1 or 2 correct links = 1 mark
R any additional lines
production of amylase,
B mouth
protease and lipase
C pancreas production of saliva
D salivary glands site of egestion
E stomach site of ingestion
;;;;;;
7(b) colon ; 2 apply list rule
rectum ;
7(c) mouth / stomach / A / C ; 1
7(d) 3 apply list rule
carbohydrate ; I examples, e.g. sugar
(named) vitamins ;
(named) minerals ;
water ;
fibre / roughage ;
(a) The box on the left contains the phrase ‘intensive livestock farming’.
The boxes on the right contain some sentence endings.
Draw two lines from the box on the left to make two correct sentences.
conditions increase the risk of the spread of disease.
enables natural selection to take place.
Intensive livestock farming
involves keeping livestock in their natural environment.
results in lots of animal waste which can pollute water.
[1]
(b) Intensive farming produces large volumes of greenhouse gases.
(i) State two greenhouses gases produced by intensive farming.
1 ……
2 ……
[2]
(ii) State one effect of the pollution caused by greenhouse gases.
…… [1]
[Total: 4]
Mark scheme
8(a) 1 both correct for 1 mark
R additional lines
conditions increase the risk of
spread of disease.
enables natural selection to take
place.
Intensive
livestock
farming
involves keeping livestock in their
natural environment.
results in lots of animal waste which
can pollute water.
;
8(b) methane ; 2 apply list rule
carbon dioxide ;
AVP ; e.g. water vapour
8(c) climate change / global warming / enhanced greenhouse effect 1 A examples e.g. melting of ice caps or altered
/ AVP ; weather patterns or extinction of organisms
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On this page, free: the mark scheme for IGCSE Biology 0610/32, February/March 2020 (0610_m20_ms_32), and the question paper (0610_m20_qp_32), to read or download, with each question's marking points written out underneath.
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Biology 0610/32 for February/March 2020 is out of 80 marks, with 1 hour 15 minutes to answer it, across 8 questions.
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