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Biology 0610/42 February/March 2023: question paper and mark scheme

Cambridge IGCSE Biology (0610), Paper 4 Theory (Extended), February/March 2023. Read both free below, or download them. Done the paper? Get it marked by AI against this mark scheme.

0610_m23_qp_420610_m23_ms_420610/42/F/M/23

Paper
Paper 4 Theory (Extended)
Total marks
80
Time
1 hour 15 minutes
Questions
6
Code on the paper
0610/42/F/M/23
0610_m23_ms_42.pdf

0610/42 mark scheme, question by question

Each question as it's printed, and the mark scheme's points for it, as text. Diagrams, tables and graphs are in the PDFs above.

Question 114 marks

Question

(a) Fig. 1.1 is a simplified diagram of the circulatory system in humans. A F Y E B C D other organs Fig. 1.1 (i) State the letter from Fig. 1.1 that represents the blood vessel that contains blood with the highest concentration of oxygen. …… [1] (ii) State the letter from Fig. 1.1 that represents the hepatic portal vein. …… [1] (iii) State all the letters from Fig. 1.1 that represent arteries. …… [1] (iv) Explain the importance of the part labelled Y in Fig. 1.1. …… [2] (v) State the evidence from Fig. 1.1 that the diagram shows a double circulation system. …… [2] (b) Fig. 1.2 shows the pressure of blood flowing through different blood vessels as it travels around the body. (Venules are narrow vessels that connect capillaries to veins.) 18 16 14 12 blood 10 pressure / kPa 8 6 4 2 0 arteries X capillaries venules veins type of blood vessel Fig. 1.2 (i) Blood vessels X in Fig. 1.2 supply blood to skin-surface capillaries and have a role in maintaining a constant internal temperature. State the name of the blood vessels that are represented by the letter X in Fig. 1.2. …… [1] (ii) Explain reasons for the changes in pressure seen in the arteries in Fig. 1.2. …… [2] (iii) Using the information in Fig. 1.2, explain the structural adaptations of arteries and veins. …… [4] [Total: 14]

Mark scheme

1(a)(i) B; 1 1(a)(ii) C; 1 1(a)(iii) ADE; 1 A in any order 1(a)(iv) separates the left side and the right side of the heart / separates right atria 2 and ventricle from the left atria and ventricle ; keep deoxygenated blood and oxygenated blood separate ; 1(a)(v) blood flows through the heart twice in one circuit (of the body) ; 2 there are two separate blood circuits / pulmonary circuit and systemic circuit / described ; 1(b)(i) arterioles ; 1 1(b)(ii) any two from: 2 (change in pressure) caused by contraction of muscles (of the, heart / ventricle) ; pressure increases when the, heart / ventricles, contract / pumps ; pressure decreases when the, heart / ventricles, relax ; pressure decreases as you move further from the heart / AW ; AVP ; 1(b)(iii) any four from: 4 arteries: 1 thick / muscular, wall to withstand the high blood pressure ; 2 wall contains elastic tissue to stretch and recoil ; 3 (relatively) narrow / small, lumen maintains (high) blood pressure ; veins: 4 (relatively) large / wide, lumen to provide less resistance for blood flow / AW (at low pressure) ; 5 large lumen to carry larger volume of blood ; 6 valves to prevent backflow (caused by low pressure) ;

Question 211 marks

Question

A student investigated the digestion of starch. Fig. 2.1 shows the apparatus she used. distilled water distilled water dialysis dialysis tubing tubing starch solution starch solution + amylase test-tube A test-tube B Fig. 2.1 Dialysis tubing is used to represent a cell membrane. The dialysis tubing material allows small molecules to move across it, but not larger molecules. Test-tubes A and B were set up as shown in Fig. 2.1 and placed in a water-bath at 37 °C for 30 minutes. The liquid outside the dialysis tubing in test-tubes A and B was tested with Benedict’s solution at 0 minutes and after 30 minutes. Table 2.1 shows the results. Table 2.1 colour with Benedict’s solution colour with Benedict’s solution test-tube at 0 minutes at 30 minutes A blue blue B blue red (a) Using the information in Fig. 2.1 and Table 2.1, explain the reasons for the difference in the results for test-tubes A and B in Table 2.1. …… [6] (b) Complete Table 2.2 by writing in the names of the missing enzymes, substrates and products. Table 2.2 enzyme substrate product or products pepsin fatty acids and glycerol trypsin glucose [4] (c) State the name of the structures that increase the surface area for absorption in the small intestine. …… [1] [Total: 11]

Mark scheme

2(a) 1 Benedict’s solution in A, remains blue / no colour change / negative 6 result, as there is no, maltose / breakdown of starch ; 2 Benedict’s solution in B, turns red / changes colour / positive result, in the presence of maltose ; 3 amylase breaks down starch ; 4 into maltose ; 5 (maltose) is a small / soluble, molecule ; 6 maltose is able to pass through the dialysis tubing ; 7 by diffusion ; 8 from an area of high concentration to low concentration / down a concentration gradient ; 2(b) 4 amino one mark for each correct row pepsin protein acids / peptides fatty acid and lipase fats / oils / lipids glycerol amino trypsin protein acids / peptides maltase maltose glucose ;;;; 2(c) villi / microvilli ; 1

Question 318 marks

Question

(a) Fig. 3.1 shows part of a classification diagram for plants. (i) Complete Fig. 3.1. plants ferns …… monocotyledons …… Fig. 3.1 [2] (ii) Describe two identifying features of monocotyledons. 1 …… 2 …… [2] (b) Fig. 3.2 shows the life cycle of a fern. The life cycle of a fern has some similarities and some differences compared with the life cycles of other plants. The letters represent processes that occur during the life cycle. The haploid stages of the life cycle are represented by (n). The diploid stages of the life cycle are represented by (2n). A B spores (n) adult sporophyte adult gametophyte (n) (2n) C D C zygote gametes (n) (2n) not to scale Fig. 3.2 (i) The adult sporophyte has 1200 chromosomes in its body cells. State the number of chromosomes in the body cells of the gametophyte. …… [1] (ii) Identify and describe process A in Fig. 3.2. …… [3] (iii) State the name of process D in Fig. 3.2. …… [1] (c) Fig. 3.3 shows the parts of two flowers from two different plants of the same species. Fig. 3.3 (i) Describe what is meant by the term species. …… [2] (ii) Annotate Fig. 3.3 to show the mechanism of cross-pollination by: • labelling the structures involved • drawing an arrow to show the pathway of pollen. [3] (iii) Draw an X on Fig. 3.3 to show where fertilisation occurs. [1] (iv) Explain the disadvantages of cross-pollination compared with self-pollination. …… [3] [Total: 18]

Mark scheme

3(a)(i) flowering plants ; 2 I flowers dicotyledons ; A dicots 3(a)(ii) any two from: 2 one seed leaf / one cotyledon ; parallel veins ; adventitious / fibrous, roots ; flower parts in multiples of three ; vascular bundles throughout stem / AW ; narrow leaves ; 3(b)(i) 600 ; 1 3(b)(ii) meiosis ; 3 reduction division / chromosome number is halved / single set of chromosomes (produced) ; producing genetically different, cells / spores ; ref to spore dispersal (by wind) / described; 3(b)(iii) fertilisation ; 1 3(c)(i) (a group of) organisms that can reproduce ; 2 to produce fertile offspring ; 3(c)(ii) anther correctly labelled ; 3 stigma correctly labelled ; arrow drawn from anther to the stigma ; 3(c)(iii) X drawn in ovary ; 1 3(c)(iv) any three from: 3 1 reliant on (named) pollinators / wind ; 2 idea of wastage of pollen / less chance of pollination ; 3 idea of more energy required ; 4 need to produce, more pollen / flowers / nectar ; 5 needs more than one plant ; 6 risk of less, fertilisation / reproduction ; 7 AVP ;

Question 411 marks

Question

(a) Fig. 4.1 is a photograph of a tree that has been girdled. Girdling involves removing a complete circle of bark and phloem from around the tree. Fig. 4.1 (i) Explain why the area above the girdle in Fig. 4.1 will become swollen. Use the terms source and sink in your answer. …… [4] (ii) Explain why the leaves in girdled trees are still able to receive mineral ions from the roots. …… [2] (b) Explain why glucose made during photosynthesis is required for the absorption of mineral ions by the roots. …… [3] (c) State the balanced symbol equation for photosynthesis. …… [2] [Total: 11]

Mark scheme

4(a)(i) any four from: 4 1 ref to translocation ; 2 carbohydrates / glucose / sugars / amino acids, made in the leaves OR ref to photosynthesis in leaves ; 3 glucose / carbohydrates, converted to sucrose ; 4 leaves act as a source and roots act as a sink ; 5 phloem transports sucrose / amino acids ; 6 sucrose / (named) sugars, collect above the girdle ; 4(a)(ii) xylem is still intact / idea that xylem is further inside the trunk ; 2 mineral ions transported by xylem ; 4(b) any three from: 3 idea that glucose required, for (aerobic) respiration / to release energy / for ATP production ; ref. to active transport ; to transport mineral ions, from low to high concentration / against their concentration gradient ; 4(c) 6CO2 + 6H2O → C6H12O6 + 6O2 ;; 2

Question 512 marks

Question

The eye is a sense organ that is part of the nervous system. (a) Explain why the eye can be described as a sense organ. …… [2] (b) State the two parts of the central nervous system. 1 …… 2 …… [2] (c) Fig. 5.1 is a diagram of a section through the human eye. A H B C G D E F Fig. 5.1 (i) Draw an X on Fig. 5.1 to identify the blind spot. [1] (ii) Table 5.1 shows some of the parts labelled in Fig. 5.1, their names and their functions. Complete Table 5.1. Table 5.1 name of the part letter in Fig. 5.1 function H transmits impulses to the central nervous system cornea [3] (d) State the names of the two effectors that contract and relax during the pupil reflex. …… and …… [1] (e) Explain why a person is unable to focus on distant objects if the suspensory ligaments become permanently overstretched. …… [3] [Total: 12]

Mark scheme

5(a) contains (a group of) receptor cells ; 2 that, detect / respond, to, light / (specific) stimuli ; 5(b) brain ; 2 A in either order spinal cord ; 5(c)(i) blind spot labelled ; 1 5(c)(ii) 3 one mark for each correct row contains, receptor (cells) / rods and retina H cones transmits impulses to the central optic nerve G nervous system refracts light / allows light to enter the cornea D eye ;;; 5(d) circular muscle and radial muscle ; 1 A in either order 5(e) any three from: 3 ciliary muscles relax ; suspensory ligaments can no longer become taut ; lens, is not stretched / remains wide ; angle of refraction remains unchanged / AW ;

Question 614 marks

Question

Golden rice is a type of rice that has been genetically modified to contain a nutrient called beta-carotene. Fig. 6.1 shows the genetic modification process used to produce golden rice. bacterial cell plant DNA A B C rice plant cells infected with the genetically modified bacteria rice plants with the ability to produce beta-carotene are grown tissue culture not to scale Fig. 6.1 (a) Using the information in Fig. 6.1, complete the sentences to describe how rice is genetically modified to contain beta-carotene. The part labelled A in the bacterial cell is a …… . Part A is extracted and cut using a …… enzyme forming …… ends. The part labelled B is the …… that codes for the production of beta-carotene. The enzyme used to cut part A is also used to cut part B from the plant DNA. Part B is inserted into the part labelled A using the enzyme …… . This forms the part labelled C, which is called a …… . Part C is put into a bacterium. The bacterium is taken up by rice plant cells, giving them the ability to produce beta-carotene. Tissue culture is a form of …… reproduction that is used to produce many identical rice plants producing beta-carotene for commercial use. [7] (b) Apart from structural features, state two reasons why bacteria are useful for genetic modification. 1 …… 2 …… [2] (c) Discuss the disadvantages of genetically modifying rice plants to produce beta-carotene. …… [3] (d) Beta-carotene is required to produce vitamin A, which is essential for eye function. State the nutrient required to prevent: scurvy …… rickets. …… [2] [Total: 14]

Mark scheme

6(a) plasmid ; 7 restriction ; sticky ; gene ; (DNA) ligase ; recombinant (plasmid) ; asexual ; 6(b) any two from: 2 reproduce rapidly ; no ethical / welfare, issues ; ability to make complex molecules ; easy to maintain or store / don’t take up too much space ; idea that share a genetic code with other (named) organisms ; 6(c) any three from: 3 1 (additional) nutrient / energy, content may be (too) small ; 2 seeds may be expensive to purchase ; 3 farmers unable to save seeds ; 4 ref. to side effects / (unknown) health risks, to consumers ; 5 risk of cross-contamination with wild rice ; 6 reduction, in biodiversity / genetic diversity ; 7 consumers won’t buy GM products / ethical concerns ; 8 AVP ; 6(d) scurvy – vitamin C ; 2 rickets – vitamin D / calcium ;

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Where can I find the 0610/42 February/March 2023 mark scheme?

On this page, free: the mark scheme for IGCSE Biology 0610/42, February/March 2023 (0610_m23_ms_42), and the question paper (0610_m23_qp_42), to read or download, with each question's marking points written out underneath.

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Biology 0610/42 for February/March 2023 is out of 80 marks, with 1 hour 15 minutes to answer it, across 6 questions.

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Yes. Upload your answers to 0610/42/F/M/23 as a PDF or photos, and CIE Buddy marks every question against this paper's official mark scheme, using Cambridge's marking rules. You get your score, each lost mark explained on your own script, and the topics to revise. It's a guide, not an official Cambridge grade.