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Biology 0610/32 May/June 2021: question paper and mark scheme

Cambridge IGCSE Biology (0610), Paper 3 Theory (Core), May/June 2021. Read both free below, or download them. Done the paper? Get it marked by AI against this mark scheme.

0610_s21_qp_320610_s21_ms_320610/32/M/J/21

Paper
Paper 3 Theory (Core)
Total marks
80
Time
1 hour 15 minutes
Questions
7
Code on the paper
0610/32/M/J/21
0610_s21_ms_32.pdf

0610/32 mark scheme, question by question

Each question as it's printed, and the mark scheme's points for it, as text. Diagrams, tables and graphs are in the PDFs above.

Question 111 marks

Question

Fig. 1.1 is a diagram of the human gas exchange system. A region B Fig. 1.1 (a) (i) Identify using a label line and a label on Fig. 1.1: • a lung • the diaphragm. [2] (ii) State the name of structure A in Fig. 1.1. …… [1] (iii) Oxygen molecules pass through structure A on their way to the red blood cells. State the names of three other structures in the gas exchange system that oxygen molecules must pass through on their way to the red blood cells. 1 …… 2 …… 3 …… [3] (iv) State the name of the process that moves oxygen into the red blood cells. …… [1] (b) Fig. 1.2 is a magnified image of the exchange surface shown in region B in Fig. 1.1. Fig. 1.2 (i) State the name of the main blood vessel that delivers blood to the lungs. …… [1] (ii) The gas exchange surface shown in Fig. 1.2 is permeable to make gas exchange efficient. List two other features of gas exchange surfaces. 1 …… 2 …… [2] (c) Oxygen concentration is higher in inspired air than in expired air. State one other way the composition of inspired air differs from the composition of expired air. …… [1] [Total: 11]

Mark scheme

1(a)(i) lung correctly identified with a label and a label line ; 2 diaphragm correctly identified with a label and a label line ; 1(a)(ii) trachea ; 1 1(a)(iii) any three from : 3 mouth / nose ; larynx ; bronchus / bronchi ; bronchioles ; alveoli ; capillary wall / AW ; plasma ; 1(a)(iv) diffusion ; 1 1(b)(i) pulmonary artery ; 1 1(b)(ii) any two from : 2 large surface area ; thin / one cell thick / AW ; good blood supply / many capillaries ; short diffusion, distance / pathway ; 1(c) lower carbon dioxide concentration / less water vapour ; 1

Question 213 marks

Question

(a) (i) List the chemical elements in a carbohydrate. …… [1] (ii) State the name of one chemical element that is found in a protein but is not found in a carbohydrate. …… [1] (b) Fig. 2.1 shows a variegated leaf which uses photosynthesis to make carbohydrates. A variegated leaf has green parts that contain chlorophyll and white parts that do not contain chlorophyll. green white Fig. 2.1 (i) State the word equation for photosynthesis. …… [2] (ii) The carbohydrate produced by photosynthesis can be stored as starch in the leaf. A plant with variegated leaves used up its store of starch because it was placed in the dark. Explain why the plant used up its store of starch when it was placed in the dark. …… [2] (iii) The plant with variegated leaves was then left in a warm, sunny place. After a few days, a leaf from this plant was removed and tested for starch. Predict the results of the starch test by placing ticks (3) in Table 2.1. Table 2.1 part of leaf starch present starch absent green white [1] (iv) State the name of the mineral ion that is needed to make chlorophyll. …… [1] (c) Starch is a large molecule. The boxes on the left show the names of some other large molecules. The boxes on the right show some sentence endings. Draw five lines to make five correct sentences. large molecule sentence endings Cellulose is made from amino acids. DNA is made from fatty acids and glycerol. Glycogen is made from glucose. Oil is the genetic material. Protein [5] [Total: 13]

Mark scheme

2(a)(i) carbon, hydrogen, oxygen ; 1 2(a)(ii) nitrogen ; 1 2(b)(i) carbon dioxide + water ; glucose + oxygen ; 2 2(b)(ii) any two from: 2 no photosynthesis in the dark / light required, for photosynthesis / to make glucose / AW ; starch converted to glucose / AW ; (starch / glucose,) used, for respiration OR as a source of energy / AW ; 2(b)(iii) 1 part of leaf starch present starch absent green white ; 2(b)(iv) magnesium ; 1 2(c) large molecule sentence endings 5 one mark for each correct line R each additional line Cellulose is made from amino acids. DNA is made from fatty acids and glycerol. Glycogen is made from glucose. Oil is the genetic material. Protein ;;;;;

Question 310 marks

Question

(a) Fig. 3.1 is a diagram showing stages during the development of a human embryo and fetus. Fig. 3.1 (i) Put a tick (3) in the box that describes a human embryo. a ball of cells a cell with energy stores and a jelly coating a cell with a flagellum is made of cells that have a cell wall [1] (ii) Table 3.1 shows some of the events (D to J) that occur between fertilisation and birth. The events are not in the correct order. Table 3.1 D a baby is born E complexity of the fetus increases more than size F a zygote is formed G embryo implants into the wall of the uterus H size of the fetus increases more than complexity J the zygote divides by mitosis to produce two cells Put the events into the correct sequence by ordering the letters. One has been done for you. J [3] (b) Complete the sentences using the words and phrases from the list. Each word or phrase may be used once, more than once or not at all. afterbirth amniotic sac amniotic fluid cervix oviduct penis umbilical cord uterus wall vagina Birth begins when the strong muscles of the …… start to contract. This causes the …… to dilate. The …… can break at this stage. The muscles start to push the baby out. The baby moves through the …… . The …… is tied and cut. Finally the …… is delivered. [6] [Total: 10]

Mark scheme

3(a)(i) tick in the box next to ‘a ball of cells’ ; 1 R additional ticks 3(a)(ii) 3 one mark for F at the start and D at the F J G E H D end one mark for G before E ;;; one mark for E before H 3(b) uterus wall ; 6 cervix ; amniotic sac ; vagina / cervix ; umbilical cord ; afterbirth ;

Question 410 marks

Question

(a) (i) Define the term genetic engineering. …… [2] (ii) State one example of genetic engineering. …… [1] (b) Fig. 4.1 is a diagram of a fruit fly with normal wings and a fruit fly with vestigial wings. normal wings vestigial wings Fig. 4.1 A gene determines whether fruit flies have normal wings or vestigial wings. There are two alleles for this gene: • A is dominant and represents the allele for normal wings • a is recessive and represents the allele for vestigial wings. (i) A homozygous dominant fruit fly was crossed with a heterozygous fruit fly. Complete the genetic diagram to predict the probability of the offspring having vestigial wings. parental phenotypes normal wings × normal wings parental genotypes …… × …… gametes …… , …… × …… , …… offspring genotypes …… …… …… …… offspring phenotypes …… …… …… …… probability of offspring having vestigial wings …… [5] (ii) State the genotype of a pure-breeding fruit fly that has normal wings. …… [1] (iii) The binomial name for a fruit fly is Drosophila melanogaster. State the genus of this fruit fly. …… [1] [Total: 10]

Mark scheme

4(a)(i) changing the genetic material of an organism ; 2 by, removing / changing / inserting, (individual) genes ; 4(a)(ii) any one from: 1 AW throughout (insertion of human genes) into bacteria, to produce human insulin ; (insertion of genes into crop) plants, to confer resistance to herbicides ; (insertion of genes into crop) plants, to confer resistance to insect pests ; (insertion of genes into crop) plants, to provide additional vitamins ; AVP ; e.g. named examples 4(b)(i) parental genotypes: AA and Aa ; 5 ecf for each subsequent row gametes: A A (×) A a ; offspring genotypes: AA, AA, Aa, Aa ; offspring phenotypes: all normal wings ; probability: zero ; 4(b)(ii) AA ; 1 A homozygous dominant 4(b)(iii) Drosophila ; 1

Question 515 marks

Question

(a) Fig. 5.1 shows a section through a human molar tooth. Fig. 5.1 (i) Use label lines and labels to identify these structures on Fig. 5.1: • cement • gum • nerves. [3] (ii) State the function of the canine teeth in humans. …… [1] (b) Sheep are herbivores. They do not have canine teeth, or teeth in the front upper jaw. The other types of teeth in sheep are similar to humans. Fig. 5.2 shows an x-ray of the teeth in the skull of a sheep. Q R S Fig. 5.2 The boxes on the left show a letter from Fig. 5.2. The boxes in the middle show the name of a type of tooth shown in Fig. 5.2. The boxes on the right show the function of each type of tooth. Draw one line to link each letter from Fig. 5.2 to its correct name. Draw one line to link each name to its correct function. Draw a total of six lines. letter name function from Fig. 5.2 Q incisor biting off pieces of food R molar grinding food S premolar [5] (c) State the type of digestion that breaks up large pieces of food. …… [1] (d) Fig. 5.3 is a diagram showing the stages of dental decay. A B C Fig. 5.3 (i) Describe the causes of dental decay. Use the letters in Fig. 5.3 in your answer. …… [4] (ii) Describe one way of preventing dental decay. …… [1] [Total: 15]

Mark scheme

5(a)(i) cement correctly identified with a label and a label line ; 3 gum correctly identified with a label and a label line ; nerves correctly identified with a label and a label line ; 5(a)(ii) piercing / tearing / gripping, (food) ; 1 5(b) letter name function 5 mark by column from first column: Fig 3 correct names = 2 marks 5.2 1 or 2 correct names = 1 mark last column: Q incisor 3 correct functions = 3 marks biting off pieces of 2 correct functions = 2 marks food 1 correct function = 1 mark R molar grinding food R each additional line S premolar ;;;;; 5(c) mechanical ; 1 A physical 5(d)(i) any four from: 4 (coating of) bacteria and food / plaque, on teeth ; bacteria respire (the sugars in food) ; (bacteria) produce acid ; (acid) dissolves, enamel / A / dentine / B ; idea of nerves / pulp cavity / C, exposed / reached / AW ; 5(d)(ii) any one from: 1 regular brushing (of teeth) / described ; ref. to less sugar in diet / AW ; regular use of toothpaste ; AVP ;

Question 611 marks

Question

(a) The activity of the heart can be monitored by measuring the pulse rate. Two students measured their pulse rates before, during and after exercise. The results are shown in Fig. 6.1. before during after exercise exercise exercise 180 Key: student A 160 student B 140 120 pulse rate 100 / per minute 80 60 40 20 0 0 5 10 15 20 25 30 35 40 45 50 time / minutes Fig. 6.1 (i) Describe the changes in the pulse rates shown in Fig. 6.1 for student A and student B. …… [4] (ii) Calculate the percentage change in the pulse rate between 0 and 15 minutes for student A. Give your answer to the nearest whole number. Space for working. …… % [3] (iii) State two other methods that can be used to monitor the activity of the heart. 1 …… 2 …… [2] (b) Exercise levels, environmental temperature and changes in water intake can affect the volume and concentration of urine produced. Complete the sentences by circling the correct words in bold. The first sentence has been done for you. More exercise causes the volume of urine to increase / decrease / stay the same and the concentration of urine to increase / decrease / stay the same. A greater intake of water causes the volume of urine to increase / decrease / stay the same and the concentration of urine to increase / decrease / stay the same. A higher environmental temperature causes the volume of urine to increase / decrease / stay the same and the concentration of urine to increase / decrease / stay the same. [2] [Total: 11]

Mark scheme

6(a)(i) 1 pulse rates for both students increase, during exercise 4 / at 10–15 minutes / for 5 minutes ; 2 pulse rate for both students plateau, during exercise / at 15–25 minutes / for 10 minutes / until 25 minutes ; 3 pulse rate for both students decreases, after exercise / at 25–40 minutes / for 15 minutes / until 40 minutes ; 4 both students, took the same amount of time to recover from exercise / get back to the same pulse rate as before exercise / AW ; 5 pulse rate for student B increases more than student A / AW ; 6 comparative data quote / manipulation, with units ; 6(a)(ii) 94(%) ;;; 3 MP1 correct readings from graph of 64 and 124 MP2 correct calculation, i.e. 93.75(%) ecf wrong graph readings. MP3 correct rounding to whole number ecf MP2 6(a)(iii) any two from: 2 ECG ; listening to the closing of the valves ; AVP ; 6(b) (second sentence) ‘increase’ circled and then ‘decrease’ circled ; 2 (third sentence) ‘decrease’ circled and then ‘increase’ circled ;

Question 710 marks

Question

Measles is an example of a transmissible disease that is caused by a virus. (a) Complete the definition of transmissible disease. A transmissible disease is a disease in which the …… can be passed from one …… to another. [2] (b) Fig. 7.1 is a pie chart showing the number of people infected with four different transmissible diseases in one country in 2018. 29 304 19 000 65 098 170 000 Key: cholera AIDS measles tuberculosis Fig. 7.1 (i) State the name of the disease with the smallest number of infections in Fig. 7.1. …… [1] (ii) Use the information in Fig. 7.1 to calculate the total number of people infected with these four diseases. …… people infected [1] (iii) State the type of organism that causes cholera. …… [1] (c) (i) The list shows some examples of ways that disease-causing organisms can be transmitted. air animals blood contaminated surfaces food Complete Table 7.1 to show which are examples of direct contact and which are examples of indirect contact. Each example can be used once, more than once or not at all. Table 7.1 direct contact indirect contact [2] (ii) Table 7.2 shows three ways the body can defend itself and some examples of the three methods. Place ticks (3) in the boxes to show the correct type of defence mechanism for each example. Table 7.2 example of defence mechanism cells chemical mechanical antibody production hairs in the nose mucus phagocytosis skin stomach acid [3] [Total: 10]

Mark scheme

7(a) pathogen ; 2 host ; 7(b)(i) AIDS ; 1 7(b)(ii) 283 402 (people infected) ; 1 7(b)(iii) bacteria ; 1 7(c)(i) 2 5 correct = 2 marks direct contact indirect contact 4 or 3 correct = 1 mark blood air 2 or 1 correct = 0 marks animal contaminated surfaces food ;; 7(c)(ii) 3 one mark for each correct column example of defence cells chemical mechanical mechanism antibody production hairs in the nose mucus phagocytosis skin stomach acid ;;;

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Where can I find the 0610/32 May/June 2021 mark scheme?

On this page, free: the mark scheme for IGCSE Biology 0610/32, May/June 2021 (0610_s21_ms_32), and the question paper (0610_s21_qp_32), to read or download, with each question's marking points written out underneath.

How many marks is 0610/32 out of?

Biology 0610/32 for May/June 2021 is out of 80 marks, with 1 hour 15 minutes to answer it, across 7 questions.

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Yes. Upload your answers to 0610/32/M/J/21 as a PDF or photos, and CIE Buddy marks every question against this paper's official mark scheme, using Cambridge's marking rules. You get your score, each lost mark explained on your own script, and the topics to revise. It's a guide, not an official Cambridge grade.