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Biology 0610/43 May/June 2022: question paper and mark scheme

Cambridge IGCSE Biology (0610), Paper 4 Theory (Extended), May/June 2022. Read both free below, or download them. Done the paper? Get it marked by AI against this mark scheme.

0610_s22_qp_430610_s22_ms_430610/43/M/J/22

Paper
Paper 4 Theory (Extended)
Total marks
80
Time
1 hour 15 minutes
Questions
6
Code on the paper
0610/43/M/J/22
0610_s22_ms_43.pdf

0610/43 mark scheme, question by question

Each question as it's printed, and the mark scheme's points for it, as text. Diagrams, tables and graphs are in the PDFs above.

Question 114 marks

Question

Penicillin is produced by biotechnology industries. (a) (i) State the name of the type of pathogen penicillin is used to treat. …… [1] (ii) State the name of the group of medicinal drugs that includes penicillin. …… [1] (b) Fig. 1.1 is a flow diagram of some of the steps in the production of penicillin. organism A in step 4 a test-tube X Y Z step 5 gas outflow pipe step 1 filter step 3 nutrient mixing tank step 8 step 6 sterilising tank penicillin step 2 step 7 fermenter not to scale Fig. 1.1 (i) Organism A belongs to the fungus kingdom. State two main features of fungal cells that are used to distinguish them from the cells of prokaryotes. 1 …… 2 …… [2] (ii) State the genus name of organism A in Fig. 1.1. …… [1] (iii) Penicillin is produced in the fermenter shown in Fig. 1.1. A variety of nutrients, X, Y and Z, are mixed together and added to the fermenter in step 1. List two nutrients that need to be added to a fermenter to produce penicillin. 1 …… 2 …… [2] (iv) Explain why the nutrients are sterilised (step 2) before they are added to the fermenter (step 3). …… [1] (v) Explain why the fermenter has a gas outflow pipe. …… [2] (vi) Using the information in Fig. 1.1, outline the events occurring from step 4 to step 8 during the production of penicillin. …… [4] [Total: 14]

Mark scheme

1(a)(i) bacteria ; 1 1(a)(ii) antibiotic ; 1 1(b)(i) any two from: 2 nucleus ; mitochondria ; (r)ER ; vacuole ; AVP ; e.g., hyphae / structure of cell wall 1(b)(ii) Penicillium ; 1 1(b)(iii) any two from: 2 glucose ; ammonia / amino acids ; (named mineral) salts / ions ;; water ; 1(b)(iv) stops the growth of microorganisms / AW ; 1 A prevent contamination 1(b)(v) any two from: 2 release of, waste gas / carbon dioxide ; (carbon dioxide / gas) is produced during fermentation / respiration ; to prevent fermenter exploding / to reduce pressure ; carbon dioxide is toxic (to fungus if it builds up) ; 1(b)(vi) any four from: 4 1 (step 4) is reproduction (of A before adding to fermenter) ; A idea of adapting to environment 2 (step 5) inoculation in a fermenter / AW ; 3 (step 6) exponential growth (of organism A in fermenter) ; 4 sampling to check when penicillin is ready ; 5 penicillin is, a byproduct of maximum growth / a toxin / fermentation ; 6 (step 7) cells / product / penicillin, are removed ; 7 (step 8) purification / filtering / described ; A drying / AW 8 idea of packaging of penicillin ; 9 AVP ; e.g., batch cultures (described) / limited resources / stationary phase triggers production of penicillin

Question 220 marks

Question

Red blood cells contain the protein haemoglobin. (a) (i) State the names of the four chemical elements that are found in all proteins. …… [2] (ii) State the role of haemoglobin. …… [1] (b) Fig. 2.1 shows a photomicrograph of some red blood cells from a person with sickle cell anaemia. Abnormal red blood cells occur because of a mutation in the gene for haemoglobin. abnormal red blood cell Fig. 2.1 Suggest how the shape of the abnormal red blood cell shown in Fig. 2.1 will affect blood flow. …… [2] (c) The allele for the normal form of haemoglobin is HbA. The allele for the abnormal form of haemoglobin is HbS. Draw a genetic diagram to determine the probability of two heterozygous parents having a child who does not have the HbS allele. parental phenotypes …… x …… parental genotypes …… x …… gametes , x , offspring genotypes …… probability of offspring not having the HbS allele …… [5] (d) Fig. 2.2 and Fig. 2.3 are maps showing some of the different regions in a country. Scientists studied the distribution of the HbS allele in the country. Fig. 2.2 shows the estimated frequency of the allele within the population. Fig. 2.3 shows the estimated number of babies born with sickle cell anaemia in each region. low estimated frequency A of the HbS allele C in the population B high Fig. 2.2 estimated number A low of babies born C medium with sickle cell anaemia high B Fig. 2.3 The scientists made a statement: ‘There is a relationship between the frequency of the HbS allele and the number of babies born with sickle cell anaemia in regions A, B and C.’ (i) Using the information in Fig. 2.2 and Fig. 2.3, discuss the evidence for and against this statement for regions A, B and C only. …… [5] (ii) Suggest how the scientists would identify the presence of the HbS allele in tissue samples. …… [1] (e) Mutations are always inherited in single-celled organisms that reproduce asexually but are not always inherited in organisms that reproduce sexually. Explain why. …… [4] [Total: 20]

Mark scheme

2(a)(i) carbon and oxygen and hydrogen ; 2 nitrogen ; 2(a)(ii) binds to / releases / transports / AW, oxygen ; 1 2(b) any two from: 2 (it is) sickle-shaped / not biconcave ; rigid / inflexible ; get stuck in / block, blood vessels / capillaries ; reference to (increased) clotting ; 2(c) parental phenotypes unaffected / sickle trait / (sickle) carrier / AW × 5 ecf for subsequent rows unaffected / sickle trait / (sickle) carrier ; parental genotypes HbA HbS × HbA HbS ; gametes HbA, HbS + HbA, HbS ; offspring genotypes HbAHbA HbAHbS (HbAHbS ) HbSHbS ; probability 0.25 / 25% / ¼ ; 2(d)(i) any five from: 5 1 A has, almost no / low(est), HbS (allele) frequency / AW, but medium births ; 2 B has high(est) births and high(est) HbS (allele) frequency / AW ; 3 C has low(est) number of births and low / medium HbS (allele) frequency / AW ; 4 B supports the statement / A does not support the statement / no link between births and allele frequency / AW ; 5 data is estimated not actual ; 6 maps have different level of detail ; 7 ref. to effect of population density ; 8 AVP ; 2(d)(ii) look at, DNA base sequence / amino acid sequence / AW ; 1 2(e) any four from: 4 mutations are found in the DNA ; asexual reproduction offspring are, genetically identical to / clones of, the parent / AW ; (so) any existing mutations (in parent DNA) will be inherited / AW ; sexual reproduction (usually) involves two parents ; mutation will only be in one of the parents ; mutation will only be in some of the gametes ; meiosis does not result in genetically identical cells ;

Question 312 marks

Question

Acid rain has destroyed many forests including the forest shown in Fig. 3.1. Fig. 3.1 (a) Describe how acid rain destroys forests. …… [3] (b) Explain the negative consequences to the environment of destroying forests. …… [4] (c) Acid rain can also damage aquatic organisms such as the amphibian shown in Fig. 3.2. Fig. 3.2 Suggest why amphibians are vulnerable to pollutants such as acid rain. …… [2] (d) Many countries have strict laws to prevent acid rain. Describe how countries have reduced acid rain. …… [3] [Total: 12]

Mark scheme

3(a) any three from: 3 lowers pH / acidifies soil ; (acidified soil) causes leaching ; burn / corrode / damage , leaves ; affects ability of roots to absorb mineral ions ; consequence of named mineral ion deficiency described ; AVP ; e.g., described root damage / reduced ability to take up water 3(b) any four from: 4 species become endangered / extinct ; because there is a loss of habitat ; knock on negative effect to, other organisms / food chains ; (increases) soil erosion / nutrient leaching ; causes flooding ; (increases) landslides ; idea of change in the pattern of rainfall ; less photosynthesis ; increase (atmospheric) carbon dioxide / less carbon dioxide removed ; 3(c) any two from: 2 adapted to a different pH ; moist / permeable, skin ; large surface to volume ratio ; may have gills which are, fragile / thin / AW ; lays (unshelled) eggs in water ; part of the life cycle / larval stages, only exist in water ; 3(d) any three from: 3 scrubbers / flue gas desulfurisation, in power stations / chimneys ; reduce use of coal-fired power stations ; use alternative / renewable, energy sources ; catalytic converters ; low sulfur fuel / AW ; recycling / reusing / reducing, plastic / less plastic waste burnt ; AVP ; e.g., electric cars / carpool / public transport

Question 412 marks

Question

(a) Fig. 4.1 is a diagram of the alimentary canal. 1 2 3 4 5 6 Fig. 4.1 Complete Table 4.1 by stating: • the names of the organs from Fig. 4.1 • the letters of all the processes shown in the key that occur in each organ. Key: A – absorption C – chemical digestion E – egestion I – ingestion M – mechanical digestion Table 4.1 number from letter or letters of all the name of the organ Fig. 4.1 processes that occur in the organ 1 2 3 4 5 6 [6] (b) Fig. 4.2 is a diagram of a villus. The arrow indicates the direction of blood flow. P Q R U S T not to scale Fig. 4.2 Describe the structure of a villus and its role in the alimentary canal. Use the letters in Fig. 4.2 to support your answer. …… [6] [Total: 12]

Mark scheme

4(a) 6 one mark for each correct row letter or letters of all the number from name of the organ processes that occur in the Fig. 4.1 organ 1 mouth I, C, M 2 stomach C, M (A) 3 duodenum A, C (M) 4 ileum A, C 5 colon A 6 anus E ;;;;;; 4(b) any six from: 6 1 P is a lacteal ; 2 (lacteals) absorb, fats / fatty acids / glycerol / (named) fat soluble vitamin ; 3 T / lymphatic vessel, returns lymph / fats, to blood / to circulatory system ; 4 Q / epithelial cell, has microvilli ; 5 (microvilli / villi) increase the surface area for absorption ; 6 Q is one cell thick for short diffusion distance / fast diffusion 7 Q is site of breakdown of maltose to glucose ; 8 glucose uptake by active transport ; 9 R / capillary, for absorption of, amino acids / glucose / salts / water / products of digestion / soluble nutrients ; 10 R has thin walls / R is one cell thick ; 11 blood flowing to maintain concentration gradient / AW ; 12 transports absorbed nutrients to, S / venule / vein ;

Question 512 marks

Question

Glasshouses are designed to maximise crop plant yield. (a) (i) Explain why carbon dioxide enrichment is used in many glasshouses to increase crop plant yield. …… [3] (ii) Suggest how the carbon dioxide concentration in a glasshouse can be enriched. …… [1] (iii) Outline how carbon dioxide in a glasshouse moves into leaves. …… [2] (b) Additional lighting is often installed in glasshouses in countries with temperate climates. Table 5.1 summarises some of the factors that are considered by plant growers when choosing the type of lamps to install in a glasshouse. Table 5.1 type of electrical energy used light intensity output notes lamp by the lamp / J per s / arbitrary units • releases lots of heat sodium 1041 1767 • best when used in addition to sunlight • releases very little heat LED 423 378 • can be used as an alternative to sunlight • releases some heat metal 651 817 • can be used as an halide alternative to sunlight • releases some heat fluorescent 394 374 • best when used in addition to sunlight (i) Calculate the percentage increase in the energy used by the metal halide lamp compared to the energy used by the fluorescent lamp. Give your answer to two significant figures. Space for working. …… % [2] (ii) State which type of lamp has the highest light intensity output per unit of electrical energy used. …… [1] (iii) Some types of lamp release a lot of heat. Explain the possible effects of excessive heat on the plants in a glasshouse. …… [3] [Total: 12]

Mark scheme

5(a)(i) carbon dioxide is needed for photosynthesis ; 3 (atmospheric) carbon dioxide concentration is a limiting factor / AW ; glucose is, a product of photosynthesis / needed for growth ; 5(a)(ii) (named fossil fuel) burners / carbon dioxide gas cylinders / AVP ; 1 5(a)(iii) diffusion / high concentration to low concentration ; 2 through stomata / ref. to guard cells ; 5(b)(i) 65(%) ;; 2 MP1 correct calculation e.g. (651 – 394) ÷ 394 = 65.228 to any number of significant figures MP2 correct rounding to two significant figures ecf MP2 from incorrect MP1 5(b)(ii) sodium ; 1 5(b)(iii) any three from: 3 enzymes are involved (in, photosynthesis / respiration) ; (too much heat) can, denature enzyme / change shape of active site ; correct ref. to, transpiration / described / water vapour loss ; (more likely to) wilt ; decrease in yield / death ; AVP ;

Question 610 marks

Question

(a) Fig. 6.1 shows a photograph of fruit attached to the branch of an orange tree, Citrus sinensis. Fig. 6.1 State one reason why orange trees are classified as dicotyledonous plants. …… [1] (b) Biotechnologists use enzymes to extract juice from fruit such as oranges. Define the term enzyme. …… [2] (c) Fig. 6.2 shows the results of leaving pieces of orange fruit in an enzyme solution for different lengths of time. 9 8 total volume 7 of juice extracted / cm3 6 5 4 0 20 40 60 80 100 time / minutes Fig. 6.2 (i) State the name of the enzyme used to extract juice from fruit. …… [1] (ii) Using the information in Fig. 6.2, state the optimum length of time for efficient extraction of juice from oranges. …… [1] (iii) State the name of the vitamin found in high concentrations in citrus fruit such as oranges. …… [1] (d) The genes in some plants have been changed to increase the concentration of vitamins that these plants produce. (i) State the name of the process of changing the genes of a plant. …… [1] (ii) Discuss the possible disadvantages of people changing the genes in a plant. …… [3] [Total: 10]

Mark scheme

6(a) any one from 1 two cotyledons ; (leaves have) branching / network / AW, veins ; broad leaves ; (multiples of) five petals ; petioles ; 6(b) (made of) protein / biological ; 2 catalyst / described ; 6(c)(i) pectinase ; 1 6(c)(ii) 45 minutes ; 1 6(c)(iii) (vitamin) C / ascorbic acid ; 1 6(d)(i) genetic, engineering / modification ; 1 6(d)(ii) any three from: 3 reduced natural biodiversity ; insect-resistant plants negatively affect pollinators ; cross-pollinate into wild populations ; (GM seeds are) expensive / AW ; seeds need to be bought each season ; ethical concerns of consumers ; AVP ;

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On this page, free: the mark scheme for IGCSE Biology 0610/43, May/June 2022 (0610_s22_ms_43), and the question paper (0610_s22_qp_43), to read or download, with each question's marking points written out underneath.

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Biology 0610/43 for May/June 2022 is out of 80 marks, with 1 hour 15 minutes to answer it, across 6 questions.

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