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Biology 0610/51 October/November 2019: question paper and mark scheme

Cambridge IGCSE Biology (0610), Paper 5 Practical Test, October/November 2019. Read both free below, or download them. Done the paper? Get it marked by AI against this mark scheme.

0610_w19_qp_510610_w19_ms_510610/51/O/N/19

Paper
Paper 5 Practical Test
Total marks
40
Time
1 hour 15 minutes
Questions
2
Code on the paper
0610/51/O/N/19
0610_w19_ms_51.pdf

0610/51 mark scheme, question by question

Each question as it's printed, and the mark scheme's points for it, as text. Diagrams, tables and graphs are in the PDFs above.

Question 127 marks

Question

The leaves of plants contain green chlorophyll and other coloured pigments that are used in photosynthesis to trap light. You are going to investigate the pigments present in a green leaf using chromatography. The process of chromatography separates the pigments. The more soluble the pigment the further it moves. In this experiment the pigments in green leaves dissolve in a solvent (S1). The solvent moves up the paper carrying the pigments different distances. You should use the safety equipment provided while you are carrying out the practical work. Step 1 Use a ruler to draw a pencil line across the strip of chromatography paper 3 cm from one end. Step 2 Place a leaf on top of the pencil line and transfer the pigment from the leaf onto the pencil line by rolling a metal disc over the leaf as shown in Fig. 1.1. You should see a faint green line on the chromatography paper. pencil line 3 cm chromatography paper metal disc rolling leaf on top of from one end over the leaf the pencil line Fig. 1.1 Step 3 Move the leaf so that a different part of the leaf is over the line you have just made and repeat rolling the metal disc across the leaf along the pencil line. Repeat this step until you have a dark green line. Step 4 Pour solvent S1 into a test-tube to a depth of 2 cm. Put the lid back on the solvent container to prevent evaporation. Step 5 Carefully lower the strip of chromatography paper into the test-tube with the green line at the bottom. Do not allow the green line to go below the level of solvent S1 as shown in Fig. 1.2. stopper top of the chromatography paper test-tube chromatography paper green line solvent S1 2 cm Fig. 1.2 Step 6 Fold the free end of the chromatography paper over the edge of the outside of the test- tube and place a stopper in the test-tube. Do not move the test-tube during steps 7 and 8. Step 7 Start the stop-clock and observe the movement of solvent S1 up the chromatography paper for one minute while it is inside the test-tube. Step 8 Wait for five more minutes and then observe the movement of the solvent again while it is inside the test-tube. If the solvent is near the top of the chromatography paper move on to step 9. If it is not near the top of the chromatography paper wait for another five minutes and then move on to step 9. Step 9 When the solvent is near the top of the chromatography paper (or you have waited for a total of 11 minutes) remove the stopper from the test-tube and lift out the strip of chromatography paper. Put the stopper back into the test-tube to prevent the solvent from evaporating. Step 10 Place the chromatography paper on a paper towel and use the pencil to draw a line across the paper to mark how far up the chromatography paper solvent S1 has reached. Leave the paper to dry for one minute. (a) (i) Use the adhesive tape to stick your completed chromatogram in the space in Fig. 1.3. Observe the different pigment colours visible on your chromatogram. Complete Fig. 1.3 by drawing the shape of each pigment colour visible in your chromatogram onto the diagram. Label all the visible pigment colours and the position reached by solvent S1. pencil line space to attach your completed chromatogram diagram of your chromatogram Fig. 1.3 [3] (ii) Suggest why it is important that the green line was kept above solvent S1. …… [1] (b) Some students used a different method to obtain the pigments from a leaf by cutting up the leaf and grinding it with ethanol. They filtered the mixture and obtained a chlorophyll extract which was then evaporated until only a small volume of extract remained. Ethanol is flammable. (i) State one safety precaution that the students would take when evaporating substances containing ethanol. …… [1] (ii) A chromatography paper was prepared in the same way as in step 1. A small drop of the concentrated chlorophyll extract was placed on the pencil line and allowed to dry. The chromatography paper was then placed in a test-tube containing a different solvent (S2) and left for 10 minutes. Fig. 1.4 shows the appearance of the chromatogram after it was removed from solvent S2 and allowed to dry. solvent line orange-yellow the maximum distance moved by solvent S2 yellow from the start line blue-green the maximum distance moved green by green pigment from the start line drop of chlorophyll extract on the start line Fig. 1.4 The different pigments can be compared by calculating their Rf value. the maximum distance moved by the pigment from the start line Rf value = the maximum distance moved by the solvent from the start line Fig. 1.4 shows where these distances were measured on the chromatogram for the green pigment. The students calculated some of the Rf values. The results are shown in Fig. 1.5. green 0.24 blue-green 0.40 yellow 0.45 Fig. 1.5 Calculate the Rf values for the orange-yellow pigment in Fig. 1.4. Give your answer to two decimal places. the maximum distance moved by the orange-yellow pigment from the start line …… mm the maximum distance moved by the solvent from the start line …… mm orange-yellow Rf value …… [3] (iii) Prepare a table and record the colours and Rf values of the four pigments. [3] (iv) Identify the pigment colour that is the least soluble and explain your choice. pigment colour …… explanation …… [2] (c) The method used to separate the leaf pigments in 1(b) is different from the method you used in 1(a). Describe two ways in which the method used in 1(b) is an improvement to the method you used in 1(a). 1 …… 2 …… [2] (d) Chloroplasts can contain starch. State the name of the substance that would be used to test for the presence of starch. …… [1] (e) Chloroplasts contain coloured pigments. Fig. 1.6 shows some of the cells from a leaf that contains chloroplasts. cell containing chloroplasts chloroplasts Fig. 1.6 Make a large drawing to show the three complete cells containing chloroplasts in Fig. 1.6. Label one chloroplast on your drawing. [5] (f) Some plants have leaves that are not green. For example the plant may have red, purple or yellow leaves. A student predicted that leaves of different colours would have different rates of photosynthesis. Plan an investigation to find out if the student’s prediction is correct. …… [6] [Total: 27]

Mark scheme

1(a)(i) pigments shown or drawn ; 3 pigments labelled ; solvent line labelled ; 1(a)(ii) idea of: so that the, green line / pigment / leaf extract, will not, wash off / 1 dissolve (into the solvent) ; 1(b)(i) not using a Bunsen / flames / AW ; 1 using water-bath / electric heater ; 1(b)(ii) distance of orange-yellow pigment 75 ± 1 (mm) 3 and distance of solvent front 80 ± 1 (mm) ; 0.94 ;; 1(b)(iii) table drawn with minimum of two columns and header line ; 3 appropriate column / row headings ; three correct Rf values for green, blue-green and yellow and four colours ; 1(b)(iv) green ; 2 moves the least (distance up the paper) / smallest Rf value ; 1(c) the extract is more concentrated / contains more chlorophyll or 2 chloroplasts / the spot is smaller / less spread out than a line ; idea that it is more pure e.g. there is no cell debris in the extract / extract was filtered so was purer ; the solvent / ethanol / S2 / method 1b, was better at separating the pigments than S1 / 1a / AW ; 1(d) iodine (solution) ; 1 1(e) 1 outline of cells as clear single lines ; 5 2 drawing occupies at least half the space available (wider than 65 mm) ; 3 detail 1: approx. correct shape and proportions of three cells (i.e. 2 cells on left approx. same total size as the large cell on right) and cells up to 10 mm apart ; 4 detail 2: 6 chloroplasts in smallest cell / 5 chloroplasts in medium cell / 9 chloroplasts in largest cell ; 5 one chloroplast labelled ; 1(f) 1 using at least 2 different colours of leaf ; 6 2 identifying the dependent variable ; e.g. oxygen / gas production / indicator colour change 3 measuring (dependent variable) after a set time ; 4 method of collecting gas in a set time ; e.g. use of a measuring cylinder / gas syringe / counting bubbles / how long it takes leaf discs to surface 5 method to control temperature ; 6, 7, 8 three from: ;;; • same surface area / size / age, of leaf / plant • same temperature • same light, intensity / amount • same carbon dioxide, concentration / amount • same volume / amount of water • same volume / concentration / amount, of indicator 9 2 or more repeats / three or more trials of each leaf colour ;

Question 213 marks

Question

(a) Fig. 2.1 is a diagram of a sample of red blood cells on part of a counting grid. The blood has been diluted 200 times so that the cells can be counted more easily. A light microscope is used to view the counting grid. TOP counting grid LEFT RIGHT BOTTOM magnification ×550 Fig. 2.1 (i) Scientists count the number of red blood cells to estimate the total number of red blood cells in the blood. Cells that are touching the top and left side of the grid are counted. Cells touching the bottom and right side of the grid are not counted. State how many red blood cells would not be counted in the sample in Fig. 2.1. …… [1] (ii) The actual size of the counting grid in Fig. 2.1 is 0.20 mm × 0.20 mm. The depth of the counting grid is 0.10 mm. Calculate the volume of the counting grid. …… mm3 [1] (iii) A different sample of blood was also diluted 200 times. The number of red blood cells inside the same size counting grid was 95. Calculate the number of red blood cells per mm3 of undiluted blood. Use the formula: red blood cells counted × dilution number of red blood cells per mm3 = volume of the counting grid Space for working. number of red blood cells per mm3 …… [1] (b) Table 2.1 describes the number of red blood cells and white blood cells in different blood samples. Table 2.1 condition number of red blood cells number of white blood cells healthy normal normal anaemia low normal leukaemia low high infection normal high Fig. 2.2 shows drawings of blood samples. healthy blood A B C D Key: red blood cells white blood cells Fig. 2.2 State the letters in Fig. 2.2 which could represent these conditions: infection …… anaemia …… . [2] (c) Anaemia can also be diagnosed by measuring the haemoglobin content of the blood. Samples of blood were collected from 1800 men and 2400 women. The haemoglobin content of their blood was measured and the percentage of people with anaemia was calculated. Table 2.2 shows the percentage of men and women in the sample who have anaemia. Table 2.2 percentage with anaemia age group men women 65–74 7.0 8.5 75–84 16.5 11.0 85–94 26.0 20.5 (i) Plot a histogram to show the percentage of men and women with anaemia in each age group. [5] (ii) Describe the trends shown by these data. …… [2] (iii) Suggest why the data was reported as percentages rather than the actual numbers of men and women with anaemia. …… [1] [Total: 13]

Mark scheme

2(a)(i) 3; 1 A 3–6 2(a)(ii) 0.004 (mm3) ; 1 A 4 × 10–3 or 4 µm3 2(a)(iii) 4 750 000 / 4.75 × 106 ; 1 ecf volume calculated in 2(a)(ii) 2(b) infection: D ; 2 anaemia: A ; 2(c)(i) axes labelled ; 5 suitable even scale and plots occupy at least half the grid in both directions ; all points plotted accurately ± half a small square ; bars drawn ; key ; 2(c)(ii) as age increases % with anaemia increases ; 2 women (%) higher than men up to 74 then men higher ; women show a slow increase (in %) then faster increase (from age 85) / increase for men is constant / AW ; 2(c)(iii) idea of: more women than men were sampled ; 1

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Where can I find the 0610/51 October/November 2019 mark scheme?

On this page, free: the mark scheme for IGCSE Biology 0610/51, October/November 2019 (0610_w19_ms_51), and the question paper (0610_w19_qp_51), to read or download, with each question's marking points written out underneath.

How many marks is 0610/51 out of?

Biology 0610/51 for October/November 2019 is out of 40 marks, with 1 hour 15 minutes to answer it, across 2 questions.

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