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Biology 0610/33 October/November 2021: question paper and mark scheme

Cambridge IGCSE Biology (0610), Paper 3 Theory (Core), October/November 2021. Read both free below, or download them. Done the paper? Get it marked by AI against this mark scheme.

0610_w21_qp_330610_w21_ms_330610/33/O/N/21

Paper
Paper 3 Theory (Core)
Total marks
80
Time
1 hour 15 minutes
Questions
9
Code on the paper
0610/33/O/N/21
0610_w21_ms_33.pdf

0610/33 mark scheme, question by question

Each question as it's printed, and the mark scheme's points for it, as text. Diagrams, tables and graphs are in the PDFs above.

Question 111 marks

Question

Respiration is a process that occurs in all living organisms. (a) (i) Complete the definition of aerobic respiration. The …… reactions in cells that use …… to break down …… molecules to release energy. [3] (ii) State two uses of the energy released by respiration in the human body. 1 …… 2 …… [2] (iii) Carbon dioxide is one chemical product of aerobic respiration. State the name of the other chemical product of aerobic respiration. …… [1] (b) A student investigated respiration at two different temperatures in germinating pea seeds. The apparatus is shown in Fig. 1.1. Soda lime is a chemical that absorbs carbon dioxide. oil drop germinating pea soda lime Fig. 1.1 The results of the investigation are shown in Table 1.1. Table 1.1 temperature / °C distance moved by the oil drop / cm 5 2.3 25 5.0 (i) Calculate the percentage increase in the distance the oil drop moved, when the temperature changed from 5 °C to 25 °C. Give your answer to one decimal place. Space for working. …… % [3] (ii) State two environmental conditions that the pea seeds shown in Fig. 1.1 would need for germination. 1 …… 2 …… [2] [Total: 11]

Mark scheme

1(a)(i) chemical ; 3 oxygen ; nutrient ; 1(a)(ii) any two from: 2 muscle contraction / protein synthesis / cell division / active transport / growth / passage of nerve impulses / maintenance of a constant body temperature / AVP ;; 1(a)(iii) water ; 1 1(b)(i) 117.4 (%) ;;; 3 MP1 5.0 – 2.3 = 2.7 (cm) MP2 correct calculation (2.7 ÷ 2.3) × 100 = 117.391… MP3 correct rounding to one decimal place ecf MP3 from wrong answer if working shown 1(b)(ii) any two from: 2 water ; suitable temperature ; oxygen ;

Question 28 marks

Question

Transmissible diseases are caused by pathogens. (a) Cholera is a transmissible disease that causes diarrhoea. State the type of organism that causes cholera. …… [1] (b) One method of controlling the spread of disease is to treat raw sewage to make it safe. (i) Describe how raw sewage is treated to make the water safe to drink and safe to release into the sea. …… [3] (ii) State one other method of controlling the spread of disease. …… [1] (c) The body has defences against diseases. (i) The body has barriers that prevent pathogens from entering the body. State the name of one mechanical barrier and one chemical barrier. mechanical …… chemical …… [2] (ii) State one product of white blood cells that defends the body from pathogens. …… [1] [Total: 8]

Mark scheme

2(a) bacterium / bacteria ; 1 2(b)(i) any three from: 3 screening / removal of large objects ; settlement ; (trickling) filters / reed bed ; aerobic respiration (by microorganisms) / activated sludge ; chlorination / UV treatment ; 2(b)(ii) any one from: 1 hygienic food preparation / described ; good personal hygiene / described ; hygienic waste disposal ; vaccination ; AVP ; 2(c)(i) mechanical: 2 skin / hairs in nose ; chemical: mucus / stomach acid / hydrochloric acid ; 2(c)(ii) antibodies ; 1

Question 310 marks

Question

(a) Fig. 3.1 shows a diagram of a cross‑section through a leaf. D F E Fig. 3.1 (i) State the name of the tissues labelled D and E. D …… E …… [2] (ii) State the name of the cell structure labelled F. …… [1] (b) Plant cells photosynthesise. State the word equation for photosynthesis. …… [2] (c) A student investigated the effect of light on the rate of photosynthesis. Fig. 3.2 shows the apparatus used. lamp gas bubble ruler to water measure the distance of the light source from the plant aquatic plant Fig. 3.2 A lamp was used as the only source of light. The lamp was placed 10 cm from the aquatic plant. The number of bubbles the aquatic plant produced in three minutes was counted and the rate of photosynthesis was calculated. This method was repeated at 10 cm intervals. The results are shown in Table 3.1. Table 3.1 distance of the lamp from number of bubbles rate of photosynthesis the aquatic plant / cm counted in three minutes / bubbles per minute 10 87 29 20 87 29 30 75 40 48 16 50 24 8 (i) Use the information in Table 3.1 to calculate the rate of photosynthesis when the lamp was 30 cm from the aquatic plant. …… bubbles per minute [1] (ii) State the two distances between which the rate of photosynthesis halved. …… cm and …… cm [1] (iii) State two distances which have the same rate of photosynthesis. …… cm and …… cm [1] (iv) Predict what would happen to the rate of photosynthesis if the lamp was switched off. Give a reason for your answer. prediction …… reason …… [2] [Total: 10]

Mark scheme

3(a)(i) D palisade (mesophyll) ; 2 E spongy (mesophyll) ; 3(a)(ii) chloroplast ; 1 3(b) carbon dioxide + water → ; glucose + oxygen ; 2 3(c)(i) 25 (bubbles per minute) ; 1 3(c)(ii) 40 (cm) and 50 (cm) ; 1 3(c)(iii) 10 (cm) and 20 (cm) ; 1 3(c)(iv) prediction 2 rate is zero / photosynthesis stops / no bubbles produced ; reason light is required for photosynthesis ;

Question 47 marks

Question

(a) Fig. 4.1 is a diagram of the female reproductive system. J K M L Fig. 4.1 Table 4.1 shows some of the names and functions of the structures labelled with letters J to M in Fig. 4.1. Complete Table 4.1. Table 4.1 letter in name of the structure function of the structure Fig. 4.1 J transfers egg cells to the uterus K production of eggs L cervix M uterus wall [4] (b) There are a range of birth control options available to humans. Table 4.2 shows some information about types of birth control. Complete Table 4.2. Table 4.2 type of birth control example of birth control barrier contraceptive implant natural [3] [Total: 7]

Mark scheme

4(a) oviduct ; 4 ovary ; closed in pregnancy / dilates to allow childbirth / enables passage of sperm for fertilisation / AVP ; contracts in labour / AVP ; 4(b) 3 type of birth control example of birth control barrier condom / femidom / diaphragm ; chemical ; contraceptive implant natural abstinence / monitoring temperature / AVP ;

Question 57 marks

Question

(a) A class of students measured their wrist circumference, as shown in Fig. 5.1. Wrist circumference is an example of a characteristic that shows continuous variation in humans. Fig. 5.1 Fig. 5.2 shows the results of the investigation. 8 7 6 5 number of 4 students 3 2 1 0 12.0 – 13.0 – 14.0 – 15.0 – 16.0 – 17.0 – 18.0 – 19.0 – 12.9 13.9 14.9 15.9 16.9 17.9 18.9 19.9 wrist circumference / cm Fig. 5.2 (i) Calculate the total number of students in this investigation. …… [1] (ii) State the most frequent wrist circumference range. …… [1] (iii) Explain how these data show that wrist circumference is an example of continuous variation. …… [1] (b) State one example of discontinuous variation. …… [1] (c) Variation can be caused by mutation. Complete the sentences about mutation. A mutation is a …… change. Mutation is the way new …… are formed which are versions of a gene. Mutation can be caused by …… radiation and some chemicals. [3] [Total: 7]

Mark scheme

5(a)(i) 24 ; 1 5(a)(ii) 15.0-15.9 ; 1 5(a)(iii) there is a range (of phenotypes between two extremes) 1 / no distinct categories / can be any value between the extremes ; 5(b) tongue rolling / AVP ; 1 5(c) genetic ; 3 alleles ; ionising ;

Question 610 marks

Question

Carbon is a part of many biological molecules. (a) Fig. 6.1 is a diagram of part of the carbon cycle. CO2 in the atmosphere combustion A B carbon feeding carbon compounds compounds in in C plants decomposition carbon carbon compounds compounds in D in decomposers Fig. 6.1 (i) State the name of the process labelled A. …… [1] (ii) State the name of the process labelled B. …… [1] (iii) State the name of C. …… [1] (iv) State the name of D. …… [1] (b) Describe the undesirable effects of deforestation. …… [3] (c) Methane is a gas that pollutes the atmosphere. (i) State one source of the methane that pollutes the atmosphere. …… [1] (ii) State the effects of an increased concentration of methane in the atmosphere. …… [2] [Total: 10]

Mark scheme

6(a)(i) photosynthesis ; 1 6(a)(ii) respiration ; 1 6(a)(iii) animals ; 1 6(a)(iv) fossil fuels ; 1 6(b) any three from: 3 1 increase in carbon dioxide (concentration) ; 2 habitat destruction ; 3 loss of soil / soil erosion ; 4 idea of disruption of, food chains / food webs ; 5 lack of biodiversity / extinction of species ; 6 flooding ; 7 AVP ; e.g. reduction in rainfall 6(c)(i) decay / paddy fields / cattle / AVP ; 1 6(c)(ii) any two from: 2 enhanced greenhouse effect ; climate change / global warming ; AVP ;

Question 79 marks

Question

(a) Fig. 7.1 is a diagram of an animal cell. P Q R Fig. 7.1 Complete Table 7.1 by stating the functions of the structures labelled in Fig. 7.1. Table 7.1 structure label function of the structure P Q R [3] (b) Cell structure can be specialised to perform a specific function. A range of animal cell types are shown in Fig. 7.2. The boxes on the left contain the names of four specialised cells. The boxes in the middle contain diagrams of different specialised cells. The boxes on the right contain descriptions of functions. Draw one line from each name of a specialised cell to the diagram of that cell. Draw one line from each diagram of a specialised cell to its function. Two lines have been drawn for you. Draw six more lines. specialised cell names specialised cell diagrams functions absorption of mineral ions ciliated cell conduction of impulses nerve cell movement of mucus in the trachea red blood cell sexual reproduction sperm cell transport of oxygen Fig. 7.2 [6] [Total: 9]

Mark scheme

7(a) P controls movement of substances into and out of a cell ; 3 Q site of, chemical / metabolic, reactions ; R controls cell activities ; 7(b) 6 one mark for each correct link R each additional line ;;;;;;

Question 813 marks

Question

(a) (i) State the type of pathogen that can be treated with antibiotics. …… [1] (ii) State the name of the pathogen that can lead to AIDS. …… [1] (b) Many pathogens have developed resistance to some antibiotics. A study took samples of pathogens and tested them for resistance to various types of antibiotics. Fig. 8.1 shows the percentage of pathogens sampled that were resistant to various antibiotics. The samples were taken between 2000 and 2013. Key: antibiotic A antibiotic B antibiotic C 30 20 percentage of pathogens sampled that show resistance 10 0 2000 2001 2002 2003 2004 2005 2006 2007 2008 2009 2010 2011 2012 2013 year Fig. 8.1 (i) State the meaning of antibiotic resistance. …… [1] (ii) Describe the pattern of resistance for the three antibiotics shown in Fig. 8.1. …… [3] (c) Some medicinal drugs, such as human insulin, can be made using biotechnology and genetic engineering. (i) State where insulin is produced in humans. …… [1] (ii) State the function of insulin in humans. …… [1] (d) (i) State why bacteria are useful in biotechnology. …… [2] (ii) Describe the role of yeast in biotechnology. …… [3] [Total: 13]

Mark scheme

8(a)(i) bacteria ; 1 8(a)(ii) HIV / human immunodeficiency virus ; 1 8(b)(i) idea of antibiotics having reduced effectiveness against some 1 bacterial infections / AW ; 8(b)(ii) any three from: 3 1 resistance to all three antibiotics is increasing (2000–2012) ; 2 resistance to antibiotic A and B starts at 0% in 2000 ; 3 resistance to antibiotic C decreases from 2012 (to 2013) ; 4 data quote with units ; 5&6 AVP ;; e.g. resistance to B and C are the same between 2009 and 2012 / resistance to A rises very steeply between 2000 and 2001 / from 2001 the percentage of pathogens resistant to A is always higher than B and C ora 8(c)(i) pancreas ; 1 8(c)(ii) reduces blood glucose (concentration / level) ; 1 8(d)(i) any two from: 2 rapid reproduction rate ; ability to produce complex molecules ; AVP ; e.g. ethical reasons / cheaper than animals 8(d)(ii) any three from: 3 anaerobic respiration / fermentation ; production of ethanol for biofuels ; production of carbon dioxide in bread-making ; AVP ; e.g. brewing

Question 95 marks

Question

(a) Define inheritance. …… [2] (b) Some of the characteristics of pea plants are controlled by genes. An example of a characteristic of pea seeds is shown in Fig. 9.1. The allele for a smooth seed coat is dominant and is represented by the letter R. The allele for a wrinkled seed coat is recessive and is represented by the letter r. wrinkled seed coat smooth seed coat Fig. 9.1 The boxes on the left contain descriptions of genotypes. The boxes on the right contain examples of the possible genotypes of the pea seeds shown in Fig. 9.1. Draw a line to link each description to the correct genotype. Draw two lines. description of a genotype genotype r heterozygous genotype rr homozygous recessive genotype Rr RR [2] (c) Complete the sentence. A gene is a length of DNA that codes for a …… . [1] [Total: 5]

Mark scheme

9(a) the transmission of genetic information ; 2 from generation to generation ; 9(b) (heterozygous) line drawn to Rr ; 2 (homozygous recessive) line drawn to rr ; 9(c) protein ; 1

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Where can I find the 0610/33 October/November 2021 mark scheme?

On this page, free: the mark scheme for IGCSE Biology 0610/33, October/November 2021 (0610_w21_ms_33), and the question paper (0610_w21_qp_33), to read or download, with each question's marking points written out underneath.

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Biology 0610/33 for October/November 2021 is out of 80 marks, with 1 hour 15 minutes to answer it, across 9 questions.

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Yes. Upload your answers to 0610/33/O/N/21 as a PDF or photos, and CIE Buddy marks every question against this paper's official mark scheme, using Cambridge's marking rules. You get your score, each lost mark explained on your own script, and the topics to revise. It's a guide, not an official Cambridge grade.