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Chemistry 0620/43 May/June 2019: question paper and mark scheme

Cambridge IGCSE Chemistry (0620), Paper 4 Theory (Extended), May/June 2019. Read both free below, or download them. Done the paper? Get it marked by AI against this mark scheme.

0620_s19_qp_430620_s19_ms_430620/43/M/J/19

Paper
Paper 4 Theory (Extended)
Total marks
80
Questions
6
Code on the paper
0620/43/M/J/19
0620_s19_ms_43.pdf

0620/43 mark scheme, question by question

Each question as it's printed, and the mark scheme's points for it, as text. Diagrams, tables and graphs are in the PDFs above.

Question 16 marks

Question

Atoms contain particles called electrons, neutrons and protons. (a) Complete the table. where the particle particle relative mass relative charge is found in an atom 1 orbiting the nucleus 1840 +1 in the nucleus [3] (b) How many electrons, neutrons and protons are there in the ion shown? 20Ca 44 2+ number of electrons . …… number of neutrons …… number of protons …… [3] [Total: 6] 24

Mark scheme

1(a) 3 particle where found in an atom relative mass relative charge electron orbiting nucleus 1/1840 –1 proton (in the) nucleus 1 +1 neutron in the nucleus 1 0 / nil 1(b) M1 electrons 18 3 M2 neutrons 24 M3 protons 20

Question 217 marks

Question

Magnesium exists as three isotopes, 12 Mg, 12 25 Mg and 12 26 Mg. (a) State, in terms of the total numbers of electrons, neutrons and protons, one difference and two similarities between these magnesium isotopes. difference . …… similarity 1 . …… similarity 2 . …… [3] (b) All isotopes of magnesium react with dilute hydrochloric acid to make hydrogen and a salt. (i) Why do all isotopes of magnesium react in the same way? . …… . …… . …… [2] (ii) Write a chemical equation for the reaction between magnesium and dilute hydrochloric acid. . …… [2] (iii) Describe a test for hydrogen. test . …… result . …… [2] (c) Magnesium is a metal. Describe the structure and bonding of metals. Include a labelled diagram in your answer. . …… . …… . …… . …… [3] (d) Magnesium reacts with oxygen to form the ionic compound magnesium oxide. (i) Complete the dot-and-cross diagrams to show the electronic structures of the ions in magnesium oxide. Show the charges on the ions. Mg O [3] (ii) Magnesium oxide melts at 2853 °C. Why does magnesium oxide have a high melting point? . …… . …… [1] (iii) Explain why molten magnesium oxide can conduct electricity. . …… . …… . …… [1] [Total: 17]

Mark scheme

2(a) difference: M1 (number of) neutrons 3 similarities: M2 (number of) protons M3 (number of) electrons 2(b)(i) M1 same number of electrons 2 M2 (same number of) electrons in outer shell 2(b)(ii) Mg + 2 HCl → MgCl2 + H2 2 M1 MgCl2 as product M2 fully correct equation 2(b)(iii) M1 Test: lighted / burning splint 2 M2 Result: (squeaky) pop 2(c) M1 (lattice of) positive ions / cations 3 M2 (delocalised / sea of) electrons M3 attraction / attract between positive and negative 2(d)(i) M1 magnesium ion 3 second shell shown containing 8 electrons shown as X M2 oxide ion second shell shown containing 8 electrons, two as X and six as z M3 charges: magnesium ion as 2+ and oxide as 2- 2(d)(ii) strong forces of attraction (between oppositely charged ions) 1 2(d)(iii) ions / Mg2+ and O2– / anions and cations can move (throughout the structure) 1

Question 317 marks

Question

(a) (i) Sodium is in Group I of the Periodic Table. Describe two physical properties of sodium which are different from the physical properties of transition elements such as copper. 1 . …… . …… 2 . …… . …… [2] (ii) Sodium reacts rapidly with water. Give one observation made when sodium is added to water. . …… [1] (b) Some car airbags contain sodium azide. When a car airbag is used the sodium azide, NaN3, decomposes. The products are nitrogen and sodium. The equation for the decomposition of sodium azide is shown. 2NaN3(s) 2Na(l) + 3N2(g) Calculate the mass, in g, of sodium azide needed to produce 144 dm3 of nitrogen using the following steps. ●● Calculate the number of moles in 144 dm3 of N2 measured at room temperature and pressure. moles of N2 = …… mol ●● Determine the number of moles of NaN3 needed to produce this number of moles of N2. moles of NaN3 = …… mol ●● Calculate the relative formula mass, Mr, of NaN3. Mr = …… ●● Calculate the mass of NaN3 needed to produce 144 dm3 of N2. …… g [4] (c) Some airbags contain silicon(IV) oxide. When the airbag is used sodium oxide is formed. Oxides can be classified as acidic, amphoteric, basic or neutral. Classify each of these oxides: sodium oxide …… silicon(IV) oxide. …… [2] (d) Lead(II) azide is insoluble in water. Solid lead(II) azide can be made in a precipitation reaction between aqueous lead(II) nitrate and aqueous sodium azide. Lead(II) azide has the formula Pb(N3)2. (i) Deduce the formula of the azide ion. . …… [1] (ii) Complete the chemical equation for the reaction between aqueous lead(II) nitrate and aqueous sodium azide to form solid lead(II) azide and aqueous sodium nitrate. Include state symbols. Pb(NO3)2(aq) + …… NaN3(aq) Pb(N3)2(……) + …… ……(……) [2] (iii) Describe how you could obtain a sample of lead(II) azide that is not contaminated with any soluble salts from the reaction mixture. . …… . …… . …… . …… [2] (e) An organic compound made from sodium azide has the composition by mass: 49.5% carbon, 7.2% hydrogen and 43.3% nitrogen. Calculate the empirical formula of the organic compound. [3] [Total: 17] Question 4 starts on the next page.

Mark scheme

3(a)(i) any two from: max 2 • low melting point or low boiling point • soft • low density 3(a)(ii) any one from: max 1 • fizz / bubbles • moves • floats • melts / forms a ball • gets smaller / disappears 3(b) mass sodium azide = 260 (g) 4 • Moles N2 = (144 / 24 =) 6 • Moles NaN3 = (6 × 2 / 3 =) 4 • Mr NaN3 = 65 • (4 × 65 = ) 260 3(c) M1 (sodium oxide) basic 2 M2 (silicon dioxide) acidic 3(d)(i) N3– 1 3(d)(ii) M1 state symbols on right correct (s) then (aq) 2 M2 (Pb(NO3)2 +) 2 (NaN3) → (Pb(N3)2 +) 2NaNO3 3(d)(iii) M1 filter 2 M2 wash with water 3(e) M1 49.5 / 12 7.2 / 1 43.3 / 14 3 OR 4.125 7.2 3.093 . M2 1.33 : 2.33 : 1 OR 4 : 7 : 3 M3 C4H7N3

Question 413 marks

Question

Solutions of ionic compounds can be broken down by electrolysis. (a) Concentrated aqueous copper(II) chloride was electrolysed using the apparatus shown. power supply – + cathode made anode made of platinum of platinum concentrated aqueous copper(II) chloride The ionic half-equations for the reactions at the electrodes are shown. negative electrode: Cu2+(aq) + 2e– Cu(s) positive electrode: 2Cl –(aq) Cl 2(g) + 2e– (i) Platinum is a solid which is a good conductor of electricity. State one other property of platinum which makes it suitable for use as electrodes. . …… . …… [1] (ii) State what would be seen at the positive electrode during this electrolysis. . …… . …… [1] (iii) State and explain what would happen to the mass of the negative electrode during this electrolysis. . …… . …… . …… [2] (iv) The concentrated aqueous copper(II) chloride electrolyte is green. Suggest what would happen to the colour of the electrolyte during this electrolysis. Explain your answer. . …… . …… . …… [2] (v) Identify the species that is oxidised during this electrolysis. Explain your answer. species that is oxidised . …… explanation …… . …… [2] (b) Metal objects can be electroplated with silver. (i) Describe how a metal spoon can be electroplated with silver. Include: ● what to use as the positive electrode and as the negative electrode ● what to use as the electrolyte ● an ionic half-equation to show the formation of silver. You may include a diagram in your answer. . …… . …… . …… ionic half-equation …… [4] (ii) Give one reason why metal spoons are electroplated with silver. . …… . …… [1] [Total: 13]

Mark scheme

4(a)(i) inert / unreactive / does not react with chlorine 1 4(a)(ii) bubbles / fizzing / effervescence 1 4(a)(iii) M1 increases 2 M2 (solid) copper deposited 4a(iv) M1 colour fades / becomes pale(r) / becomes colourless / becomes lighter 2 M2 copper (ions) removed (from solution) 4(a)(v) M1 species oxidised: chloride (ions) / Cl – 2 M2 explanation: loss of electrons / increase in oxidation state 4(b)(i) M1 spoon as cathode 4 M2 (pure)silver as anode M3 aqueous silver nitrate as electrolyte M4 Ag+ + e– → Ag 4(b)(ii) any one from: max 1 • Improves appearance • prevent / resist corrosion / oxidation • antibacterial

Question 515 marks

Question

Carboxylic acids react with alcohols to form esters. The reaction is reversible. The equation for the reaction between ethanoic acid and ethanol is shown. CH3COOH + CH3CH2OH CH3COOCH2CH3 + H2O (a) (i) What is the name of the ester formed in this reaction? . …… [1] (ii) Draw the structure of the ester formed. Show all of the atoms and all of the bonds. [1] (b) The reaction between ethanoic acid and ethanol is exothermic. Draw an energy level diagram for this reaction. On your diagram label: ●● the reactants and products ●● the energy change of the reaction, ∆H. energy progress of reaction [3] (c) Concentrated sulfuric acid is a catalyst for this reaction. What is meant by the term catalyst ? . …… . …… [2] (d) The rate of reaction can be increased by increasing the temperature. Explain why increasing the temperature increases the rate of reaction. . …… . …… . …… . …… . …… . …… [4] (e) The reaction between ethanoic acid and ethanol reaches equilibrium. (i) The reaction between ethanoic acid and ethanol is exothermic. State and explain the effect, if any, of increasing the temperature on the amount of ester at equilibrium. . …… . …… . …… [2] (ii) State and explain the effect, if any, of removing water from the mixture on the amount of ester at equilibrium. . …… . …… . …… [2] [Total: 15]

Mark scheme

5(a)(i) ethyl ethanoate 1 5(a)(ii) correct structure of ethyl ethanoate showing all bonds 1 5(b) M1 right hand energy level lower than left hand side energy level 3 M2 reactants and product positions identified M3 energy change shown as approximately vertical line indicating gap between reactants and products with arrow head pointing from reactant to products. Arrow needs to be labelled 5(c) M1 (a substance which) increases the rate of a reaction 2 M2 without being used up (at the end) OR unchanged (chemically) at the end OR without changing mass 5(d) M1 particles / molecules in explanation 4 M2 (particles) move faster / more energy M3 more collisions per second or greater collision rate M4 more of the (colliding) molecules / particles have sufficient energy (activation energy) to react / more of the collisions have sufficient energy (activation energy) to react 5(e)(i) M1 less ester 2 M2 equilibrium moves left and because forward reaction is exothermic 5(e)(ii) M1 more ester 2 M2 (equilibrium moves right) to replace water

Question 612 marks

Question

(a) Two hydrocarbons have the structures shown. hydrocarbon A hydrocarbon B H H H H H H H C H H C C H H C C C C C H C C H H H H H H H H (i) Why are these two compounds hydrocarbons? . …… . …… [2] (ii) Hydrocarbon B reacts in the same way as a typical alkane. Describe a chemical test to tell the difference between hydrocarbon A and hydrocarbon B. State the name of the reagent you would use and the result you would obtain with hydrocarbon A and hydrocarbon B. reagent …… result with hydrocarbon A . …… result with hydrocarbon B . …… [3] (b) Alkenes react with steam to form alcohols. Compound C is an alcohol. compound C H H H H H C C C C O H H H H H Draw the structure of the alkene which could be reacted with steam to make compound C. Show all of the atoms and all of the bonds. [1] (c) Alkenes can form polymers. (i) What type of polymerisation occurs when alkenes form polymers? . …… [1] (ii) Part of the structure of a polymer is shown. CH3 H CH3 H CH3 H C C C C C C H CH3 H CH3 H CH3 Draw the structure of the alkene from which this polymer can be made. Show all of the atoms and all of the bonds. [1] (iii) Polymers can undergo incomplete combustion to form carbon monoxide. Complete the chemical equation for the incomplete combustion of poly(ethene). The only carbon‑containing product is carbon monoxide. H H C C + ……O2 …… + 2n H2O H H n [2] (d) Part of the structure of a polyamide is shown. H H H C N C N C N O O O This polyamide is formed from identical monomers. Complete the diagram to show the structure of one monomer. Show all of the atoms and all of the bonds. [2] [Total: 12] The Periodic Table of Elements Group I II III IV V VI VII VIII 1 2 H He hydrogen helium Key 1 4 3 4 atomic number 5 6 7 8 9 10 Li Be atomic symbol B C N O F Ne lithium beryllium name boron carbon nitrogen oxygen fluorine neon 7 9 relative atomic mass 11 12 14 16 19 20 11 12 13 14 15 16 17 18 Na Mg Al Si P S Cl Ar sodium magnesium aluminium silicon phosphorus sulfur chlorine argon 23 24 27 28 31 32 35.5 40 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr potassium calcium scandium titanium vanadium chromium manganese iron cobalt nickel copper zinc gallium germanium arsenic selenium bromine krypton 39 40 45 48 51 52 55 56 59 59 64 65 70 73 75 79 80 84 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe rubidium strontium yttrium zirconium niobium molybdenum technetium ruthenium rhodium palladium silver cadmium indium tin antimony tellurium iodine xenon 16 85 88 89 91 93 96 – 101 103 106 108 112 115 119 122 128 127 131 55 56 57–71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 lanthanoids Cs Ba Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po At Rn caesium barium hafnium tantalum tungsten rhenium osmium iridium platinum gold mercury thallium lead bismuth polonium astatine radon 133 137 178 181 184 186 190 192 195 197 201 204 207 209 – – – 87 88 89–103 104 105 106 107 108 109 110 111 112 114 116 actinoids Fr Ra Rf Db Sg Bh Hs Mt Ds Rg Cn Fl Lv francium radium rutherfordium dubnium seaborgium bohrium hassium meitnerium darmstadtium roentgenium copernicium flerovium livermorium – – – – – – – – – – – – – 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 lanthanoids La Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu lanthanum cerium praseodymium neodymium promethium samarium europium gadolinium terbium dysprosium holmium erbium thulium ytterbium lutetium 139 140 141 144 – 150 152 157 159 163 165 167 169 173 175 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 actinoids Ac Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No Lr actinium thorium protactinium uranium neptunium plutonium americium curium berkelium californium einsteinium fermium mendelevium nobelium lawrencium – 232 231 238 – – – – – – – – – – – The volume of one mole of any gas is 24 dm3 at room temperature and pressure (r.t.p.).

Mark scheme

6(a)(i) M1 contain hydrogen and carbon 2 M2 only 6(a)(ii) M1 (Reagent): Bromine (water / solution) 3 M2 (Result with hydrocarbon A): becomes colourless / decolourised M3 (Result with hydrocarbon B): no change / stays orange 6(b) 1 6(c)(i) addition 1 6(c)(ii) 1 6(c)(iii) M1 CO on right 2 M2 2n O2 2n(CO) 6(d) 2 M1 –NH2 group drawn as displayed on one end M2 carboxylic acid group drawn as displayed on the other end

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Chemistry 0620/43 for May/June 2019 is out of 80 marks, across 6 questions.

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