Question 114 marks
Question
Washing soda consists of hydrated sodium carbonate, Na2CO3•10H2O. When it is stored it loses some of its water of crystallisation to leave Na2CO3•xH2O. Since water has been lost x is no longer an integer. You will carry out a titration to determine the value of x. You will titrate a solution of the sodium carbonate with hydrochloric acid. The equation for the reaction is shown. Na2CO3•xH2O(aq) + 2HCl (aq) → 2NaCl (aq) + CO2(aq) + (x+1)H2O(l) FB 1 is an aqueous solution containing 11.30 g dm–3 of Na2CO3•xH2O. FB 2 is 0.100 mol dm–3 hydrochloric acid, HCl. bromophenol blue indicator (a) Method ● Fill the burette with FB 2. ● Pipette 25.0 cm3 of FB 1 into a conical flask. ● Add a few drops of bromophenol blue indicator. ● Carry out a rough titration and record your burette readings in the space below. The rough titre is …… cm3. ● Carry out as many accurate titrations as you think necessary to obtain consistent results. ● Make sure your recorded results show the precision of your practical work. ● Record in a suitable form, in the space below, all of your burette readings and the volume of FB 2 added in each accurate titration. I II III IV V VI VII [7] (b) From your accurate titration results, obtain a value for the volume of FB 2 to be used in your calculations. Show clearly how you obtained this value. 25.0 cm3 of FB 1 required …… cm3 of FB 2. [1] (c) Calculations (i) Give your answers to (c)(ii), (c)(iii) and (c)(iv) to an appropriate number of significant figures. [1] (ii) Calculate the number of moles of hydrochloric acid present in the volume of FB 2 you calculated in (b). moles of HCl = …… mol [1] (iii) Use the equation on page 2, and your answer to (c)(ii), to calculate the concentration, in mol dm–3, of Na2CO3•xH2O present in FB 1. concentration of Na2CO3•xH2O = …… mol dm–3 [1] (iv) Calculate the value of x in this sample of Na2CO3•xH2O. Show your working. x = …… [3] [Total: 14]
Mark scheme
1(a) I Initial and final burette readings and volume added recorded for rough titre and accurate titre details tabulated. 1 (minimum 2 × 2 boxes with relevant information). II Initial and final burette readings recorded and vol of 1 FB 2 added recorded for each accurate titration. Headings and units correct for accurate titrations. Headings: initial / final and (burette) reading / volume or reading / volume at start / finish Do not allow difference / change and volume / FB 2 added / used or titre and units (cm3) or / cm3 or in cm3 or cm3 by every entry Accept vol but not V III All accurate burette readings are recorded to the nearest 0.05 cm3. 1 Do not award this mark if: 50(.00) is used as an initial burette reading; More than one final burette reading is 50(.00) Any burette reading is > 50(.00) IV The final accurate titre recorded is within 0.1 cm3 of any other accurate titre. 1 Do not award the mark if any accurate burette readings (apart from 0) are given to zero dp. For assessment of accuracy (Q) marks, the Examiner should round any burette readings to the nearest 0.05 cm3. Check and correct subtractions. Then select the ‘best’ titres using the hierarchy: • two (or more) accurate identical titres (ignoring any that are labelled ‘rough’), then • two (or more) accurate titres within 0.05 cm3, then • two (or more) accurate titres within 0.10 cm3, etc. These best titres should be used to calculate the mean titre, expressed to nearest 0.01 cm3. Calculate the difference (δ) between the candidate’s titre and the supervisor’s titre. Award the accuracy (Q) marks as shown below. 1(a) V, VI and VII 3 Award V, VI and VII for δ ⩽ 0.20 cm3 Award V and VI for 0.20cm3 < δ ⩽ 0.30 cm3 Award V for 0.30 cm3 < δ ⩽ 0.50 cm3 1(b) Candidate must average two (or more) titres that are all within 0.20 cm3. 1 Working must be shown or ticks must be put next to the two (or more) accurate titres selected. 1(c)(i) Answers to (ii) and (iii) given to 3–4 sf. 1 1(c)(ii) 0.1× vol in (b) 1 Correctly calculates moles of HCl = 1000 1(c)(iii) Correctly uses (c)(ii) ÷ 2 1 and x 40 1(c)(iv) Correctly uses 3 11.30 M1: Mr = moles from (c)(iii) M2: xH2O = Mr hydrated −106 or Mr = 106 + 18x M3: xH2O to calculate x = M2 / 18 and answer shown to 2–4 sf ALLOW alternative methods (e.g. ratio of anhydrous : water)