Question 111 marks
Question
Students are told to plan and carry out an experiment to determine the enthalpy change, ΔH1, when one mole of anhydrous sodium thiosulfate, Na2S2O3, is hydrated. Na2S2O3(s) + 5H2O(l) Na2S2O3•5H2O(s) One student suggested adding five moles of water to one mole of anhydrous sodium thiosulfate and measuring the temperature change. Their teacher said that method would not work and suggested another method using Hess’s law. You will carry out the teacher’s method to determine the enthalpy change, ΔH2, when one mole of hydrated sodium thiosulfate, Na2S2O3•5H2O, is dissolved in water. Na2S2O3•5H2O(s) + water Na2S2O3(aq) You will do this by adding a known mass of hydrated sodium thiosulfate to a known volume of water and measuring the temperature change when the solid dissolves. (a) Explain why the student’s suggestion to add five moles of water to one mole of anhydrous sodium thiosulfate would not be a suitable method to determine ΔH1. …… [1] (b) Teacher’s method FB 1 is hydrated sodium thiosulfate, Na2S2O3•5H2O. ● Support the cup in the 250 cm3 beaker. ● Use the 25 cm3 measuring cylinder to transfer 25.0 cm3 of distilled water into the cup. ● Place the thermometer in the water and tilt the cup, if necessary, so that the bulb of the thermometer is fully covered. Record the temperature of the water in the space for results. ● Weigh the container with FB 1. Record the mass. ● Add all of the FB 1 to the water in the cup. ● Stir the mixture. Measure and record the minimum temperature reached. ● Reweigh the container and any residual FB 1. Record the mass. ● Calculate and record the mass of FB 1 added. ● Calculate and record the change in temperature. Results I II III IV [4] (c) Calculations (i) Calculate the energy change, in J, when FB 1 is added to water. energy change = …… J [1] (ii) Calculate the enthalpy change, ΔH2, in kJ mol–1, when one mole of hydrated sodium thiosulfate, FB 1, dissolves in water. ΔH2 = …… …… kJ mol–1 [2] sign value (iii) The enthalpy change, ΔH3, when one mole of anhydrous sodium thiosulfate is dissolved in water is –8.1 kJ mol–1. Na2S2O3(s) + water Na2S2O3(aq) ΔH3 = –8.1 kJ mol–1 Use your answer to (c)(ii) and the information given to construct a Hess’s cycle to calculate ΔH1 in kJ mol–1. Show clearly how you used the data. (If you were unable to calculate an answer in (c)(ii), assume a value of 31.6 kJ mol–1. Note this may not be the correct value and the sign has been omitted.) Na2S2O3(s) + 5H2O(l) Na2S2O3•5H2O(s) ΔH1 ΔH1 = …… …… kJ mol–1 [2] sign value (d) A sample of FB 1 was contaminated with anhydrous sodium thiosulfate. State what effect this would have on the temperature change in (b). Explain your answer. …… [1] [Total: 11]
Mark scheme
1(a) One of: 1 would not all form pentahydrate some would dissolve cannot (accurately) measure (change in) temperature of a solid. 1(b) I Unambiguous headings and units covering all entries 4 (mass of) container + solid / FB 1 (mass of) container (+ residue) initial thermometer reading / temperature (of water) final / lowest thermometer reading / temperature (of solution) (mass of) solid (used / added) / FB 1 change in temperature / ΔT Units: / g, (g), in g and / °C, (°C), in °C ll All balance readings consistent to either 2 or 3 dp AND thermometer readings to .0 °C or.5 °C AND written in their table AND all subtractions correct Accuracy marks ΔT / Calculate mass to 2 decimal places for candidate and for supervisor. lll Award if the candidate ratio is within 30% of the supervisor ratio lV Award if the candidate ratio is within 15% of the supervisor ratio 1(c)(i) Correctly calculates 1 energy change = 4.18 × temperature change × 25 (J) AND answer given to 2–4 significant figures (ignore sign) 1(c)(ii) M1 Correctly uses 2 candidate mass amount of thiosulfate = / 248.2 mol M2 Correct use of (c)(i) ΔH2 = + / (moles of thiosulfate × 1000) (kJ mol−1) AND answer given to 2–4 significant figures 1(c)(iii) M1 diagram with two downward arrows AND correct labels 2 Na2S2O3(s) + 5H2O(l) → Na2S2O3.5H2O(s) ΔH3 or –8.1 ΔH2 or (c)(ii) or (+)31.6 (Na2S2O3(aq)) M2 ΔH1 = –8.1 – (answer to 1(c)(ii)) (default answer = –39.7) 1(d) (temperature change is) less / decreased because reaction of anhydrous (sodium thiosulfate) is exothermic / causes a 1 temperature increase