Question 115 marks
Question
In this experiment you will determine the relative formula mass, Mr , of a basic metal carbonate, MCO3•M(OH)2, by a titration method. FB 1 is the basic metal carbonate MCO3•M(OH)2. FB 2 is a solution containing hydrochloric acid, HCl , and MCl 2, prepared using FB 1 as follows. ● 22.50 g of FB 1, MCO3•M(OH)2, is weighed out. ● 100.0 cm3 of 5.00 mol dm–3 hydrochloric acid (a small excess) is added to FB 1. ● The mixture is left to allow FB 1 to react completely. MCO3•M(OH)2(s) + 4HCl (aq) 2MCl 2(aq) + CO2(g) + 3H2O(l) ● The resulting solution is made up to 1.00 dm3 with distilled water. ● This solution is FB 2. FB 3 is potassium hydroxide, KOH, of concentration 5.05 g dm–3. FB 4 is thymolphthalein indicator. (a) Method ● Fill the burette with FB 2. ● Pipette 25.0 cm3 of FB 3 into a conical flask. ● Add a few drops of FB 4 to the conical flask. ● Perform a rough titration and record your burette readings in the space below. The rough titre is …… cm3. ● Carry out as many accurate titrations as you think necessary to obtain consistent results. ● Make sure any recorded results show the precision of your practical work. ● Record, in a suitable form in the space below, all your burette readings and the volume of FB 2 added in each accurate titration. I II III IV V VI VII [7] (b) From your accurate titration results, calculate a suitable mean value to use in your calculations. Show clearly how you obtain the mean value. 25.0 cm3 of FB 3 required …… cm3 of FB 2. [1] (c) Calculations (i) Give your answers to (c)(ii), (c)(iii) and (c)(iv) to an appropriate number of significant figures. [1] (ii) Calculate the amount, in mol, of potassium hydroxide present in 25.0 cm3 of FB 3. amount of KOH = …… mol [1] (iii) Give the ionic equation for the reaction of hydrochloric acid with potassium hydroxide during the titration. Include state symbols. Hence calculate the concentration, in mol dm–3, of hydrochloric acid in FB 2. concentration of HCl = …… mol dm–3 [2] (iv) Use the information about FB 2 and your answer to (c)(iii) to calculate the relative formula mass, Mr , of MCO3•M(OH)2. Mr of MCO3•M(OH)2 = …… [2] (d) A student suggested that the procedure used in (a) would be more accurate if the mass of FB 1 used to prepare solution FB 2 is doubled. No other change to the procedure is made. Explain why the student is not correct. …… [1] [Total: 15]
Mark scheme
1(a) I The following data are recorded 7 two burette readings AND titre for the rough titration initial and final burette readings for two (or more) accurate titrations II Correct headings and units in the accurate titration table and titre values recorded for accurate titrations initial / start AND (burette) reading / volume final / end AND (burette) reading / volume titre OR volume / FB 2 AND used / added unit: / cm3 OR (cm3) OR in cm3 (for each heading) OR cm3 unit given for each volume recorded III All accurate burette readings are recorded to the nearest 0.05 cm3. IV The final accurate titre recorded is within 0.10 cm3 of any other accurate titre. Accuracy marks Round all burette readings to the nearest 0.05cm3 then check and correct titre subtractions, where necessary. Select the ‘best’ mean titre, using the following hierarchy: two (or more) accurate identical titres (ignoring any that are labelled “rough”), then two (or more) accurate titres within 0.05 cm3, then two (or more) accurate titres within 0.10 cm3, etc The ‘best’ titres should be used to calculate the mean titre, expressed to the nearest 0.01 cm3. Calculate the supervisor’s mean titre to 2 decimal places. Calculate the candidate’s mean titre to 2 decimal places. Calculate the difference δ between the candidate’s titre and the supervisor’s titre. V Award if δ ⩽ 0.50 cm3 VI Award if δ ⩽.0.30 cm3 VII Award if δ ⩽ 0.20 cm3 If Supervisor’s mean titre < 10.00 cm3 then halve the tolerances (0.25, 0.15, 0.10 cm3). If Supervisor’s mean titre < 5.00 cm3 then use the tolerances 0.15, 0.10, 0.05 cm3. 1(b) Correctly calculates the mean titre to 2 decimal places. 1 Candidate must take the average of two (or more) titres that are within a total spread of not more than 0.20 cm3. Working / explanation must be shown OR ticks must be put next to the two (or more) accurate readings selected. The mean should be quoted to 2 decimal places and be rounded to nearest 0.01 cm3. 1(c)(i) answers to (c)(ii), (c)(iii) and (c)(iv) are given to 3 or 4 significant figures 1 1(c)(ii) Correctly calculates 1 amount of KOH used = 5.05 / 56.1 × 25 / 1000 mol = 0.00225(0) (mol) OR 2.25(0) x 10−3 (mol) 1(c)(iii) M1 ionic equation: H+(aq) + OH-(aq) → H2O(l) 2 M2 correct use of (b) AND (c)(ii) [FB 2 / HCl ] = (c)(ii) × 1000 / (b) (mol dm−3) 1(c)(iv) Correct use of (c)(iii) 2 M1 mol of HCl reacting with FB 1 = 0.10 × 5.00 – (c)(iii) (mol HCl from M1) M2 amount of FB 1 used = /4 AND 22.5 Mr of FB 1 = / amount FB 1 used 1(d) the acid / HCl (added to FB 1) would no longer be in excess / HCl becomes the limiting reagent 1 OR no HCl would be left (to do the titration) / insufficient HCl to react with all the FB 1 / (metal) carbonate OR FB 1 / (metal) carbonate is now / will be in excess (so titration will not be possible)