Question 113 marks
Question
A redox reaction takes place between hydroxylamine, NH2OH, and the iron(III) ion, Fe3+, in acidic conditions. The iron(III) ion is reduced to an iron(II) ion, Fe2+. The reaction is slow at room temperature but is complete in a few minutes at 100 °C. The reaction is shown by one of the following equations. equation 1 NH2OH(aq) + Fe3+(aq) Fe2+(aq) + H+(aq) + ½N2(g) + H2O(l) equation 2 NH2OH(aq) + 2Fe3+(aq) 2Fe2+(aq) + ½N2O(g) + 2H+(aq) + ½H2O(l) equation 3 NH2OH(aq) + 3Fe3+(aq) 3Fe2+(aq) + NO(g) + 3H+(aq) You will carry out a titration to determine which of equations 1, 2 or 3 best represents the reaction. The iron(II) ions formed in the reaction with the hydroxylamine are oxidised by manganate(VII) ions. MnO4–(aq) + 5Fe2+(aq) + 8H+(aq) Mn2+(aq) + 5Fe3+(aq) + 4H2O(l) FA 1 is 0.0200 mol dm–3 potassium manganate(VII), KMnO4. FA 2 is a solution prepared by boiling a 1.00 dm3 aqueous mixture containing 3.30 g of hydroxylamine hydrochloride, NH2OH•HCl , excess iron(III) chloride, FeCl 3, and excess sulfuric acid. Any water lost by evaporation was replaced after cooling. FA 3 is dilute sulfuric acid. Assume that one mole of hydroxylamine hydrochloride gives one mole of hydroxylamine in solution. (a) Method • Fill the burette with FA 1. • Pipette 25.0 cm3 of FA 2 into a conical flask. • Use the 25 cm3 measuring cylinder to add 10 cm3 of FA 3 into the same conical flask. • Perform a rough titration and record your burette readings in the space below. The rough titre is …… cm3. • Carry out as many accurate titrations as you think necessary to obtain consistent results. • Make sure any recorded results show the precision of your practical work. • Record, in a suitable form, all your burette readings and the volume of FA 1 added in each accurate titration. Keep FA 3 for use in Question 2(a). Results I II III IV V VI VII [7] (b) From your accurate titration results, calculate a suitable mean value to use in your calculations. Show clearly how you obtain the mean value. 25.0 cm3 of FA 2 required …… cm3 of FA 1. [1] (c) Calculations (i) Calculate the amount, in mol, of potassium manganate(VII) present in the volume of FA 1 in (b). amount of KMnO4 = …… mol [1] (ii) Use your answer to (c)(i) to calculate the amount, in mol, of iron(II) ions in 25.0 cm3 of solution FA 2. amount of Fe2+ = …… mol [1] (iii) Calculate the amount, in mol, of hydroxylamine hydrochloride that has reacted in the FA 2 pipetted into the conical flask. Show your working. amount of NH2OH•HCl = …… mol [2] (iv) Use your answer to (c)(iii) to deduce which of the three suggested equations corresponds to your results. Show your working. The correct equation number is …… . [1] [Total: 13]
Mark scheme
1(a) I The following data must be shown 7 burette readings and titre for rough titration 2 × 2 “box” showing both accurate burette readings II Headings and units correct for accurate titration table and headings match readings initial / start and (burette) reading / volume + unit final / end and (burette) reading / volume + unit titre or volume / FA 1 AND used / added + unit Units: (cm3) or / cm3 or in cm3 in heading or cm3 by every entry III All accurate burette readings to 0.05 cm3 IV The final accurate titre recorded is within 0.10 cm3 of any other accurate titre Accuracy marks Round burette readings to the nearest 0.05 cm3. Check and correct titre subtractions where necessary. Examiner selects the best mean titre. Apply hierarchy: 2 identical, titres within 0.05 cm3, titres within 0.10 cm3 etc. Examiner subtracts (corrected) candidate’s titre from Supervisor’s titre, δ. Award accuracy marks as follows: V Award if δ ≤ 0.50 cm3 VI Award if δ ≤ 0.30 cm3 VII Award if δ ≤ 0.20 cm3 1(b) Correctly calculates mean accurate titre: 1 Candidate must take the average of two (or more) titres that are within a total spread of not more than 0.20 cm3. Working / explanation must be shown or ticks must be put next to the two (or more) accurate readings selected. The mean should be quoted to 2 decimal places (dp) and be rounded to nearest 0.01 cm3. 1(c)(i) Correctly calculates 1 amount of KMnO4 = 0.02 × (b) / 1000 mol AND answer given to 3–4 significant figures 1(c)(ii) Correctly calculates 1 amount of Fe2+ = 5 × (c)(i) mol AND answer given to 3–4 significant figures 1(c)(iii) Correctly calculates 2 M1 Mr(NH2OH•HCl) = 69.5 3.3 M2 amount of NH2OH•HCl = /69.5 × 25/1000 = 1.187 × 10−3 / 1.19 × 10−3 mol AND final answer given to 3 or more significant figures 1(c)(iv) Correctly uses 1 mole ratio n(Fe2+) : n(NH2OH•HCl) = (c)(ii) / (c)(iii) AND states equation number that fits their data