Question 119 marks
Question
In this experiment you will determine the value of x in the formula of hydrated sodium thiosulfate, Na2S2O3•xH2O, where x is an integer. You will first prepare a solution of the salt and then use this solution in a titration with aqueous iodine. The thiosulfate ions react with iodine as shown. 2S2O32–(aq) + I2(aq) → S4O62–(aq) + 2I–(aq) FA 1 is hydrated sodium thiosulfate, Na2S2O3•xH2O. FA 3 is 0.0500 mol dm–3 iodine, I2. starch indicator (a) Method Preparation of salt solution ● Weigh the container containing FA 1. ● Tip the contents of the container into the 250 cm3 beaker. ● Weigh the container with any residue. ● Record all your readings in the space below. ● Add approximately 200 cm3 of distilled water to the salt in the beaker and stir until the salt has dissolved. ● Pour the contents carefully into the 250 cm3 volumetric flask. ● Rinse the beaker with a little distilled water and add these washings to the flask. ● Fill the flask to the mark with distilled water and shake to ensure thorough mixing. ● Label this solution FA 2. Titration ● Fill a burette with FA 2. ● Pipette 25.0 cm3 of FA 3 into the conical flask. ● Add FA 2 from the burette until the solution in the flask turns yellow. ● Add 10 drops of starch indicator to the conical flask. The solution will turn blue-black. ● Continue to add more FA 2 from the burette until the blue-black colour just disappears. This is the end-point of the titration. ● Carry out a rough titration and record your burette readings in the space below. The rough titre is …… cm3. ● Carry out as many accurate titrations as you think necessary to obtain consistent results. ● Make sure your recorded results show the precision of your practical work. ● Record, in a suitable form in the space below, all of your burette readings and the volume of FA 2 added in each accurate titration. I II III IV V VI VII VIII [8] (b) From your accurate titration results, obtain a value for the volume of FA 2 to be used in your calculations. Show clearly how you obtained this value. 25.0 cm3 of FA 3 required …… cm3 of FA 2. [1] (c) Calculations (i) Give your answers to (c)(ii) and (c)(iii) to the appropriate number of significant figures. [1] (ii) Calculate the number of moles of iodine in 25.0 cm3 of FA 3. moles of I2 = …… mol [1] (iii) Calculate the number of moles of thiosulfate ions in the volume recorded in (b). moles of S2O32– = …… mol Hence calculate the number of moles of hydrated sodium thiosulfate in the mass weighed in (a). moles of Na2S2O3•xH2O = …… mol [1] (iv) Calculate the value for x in the formula of hydrated sodium thiosulfate, Na2S2O3•xH2O. Show your working. x = …… [3] (d) (i) State the maximum error in a single reading on the balance used in (a). maximum error = ± …… g Calculate the maximum percentage error in the mass of FA 1 used in (a). Show your working. maximum percentage error = ± …… % [1] (ii) Assume that the uncertainty in the mass of FA 1 is the only source of error in your experiment. Calculate the minimum value for the relative formula mass of FA 1. Show your working. minimum value for the relative formula mass of FA 1 = …… [1] (e) A student prepares FA 2 using anhydrous sodium thiosulfate salt and the same mass of salt that you used in (a). State how the student’s titre would compare with the average titre value you obtained in (b). Explain your answer. . …… . …… . …… . …… [1] (f) In many titrations it is usual to fill the burette with the solution of known concentration. Suggest why this was not done in (a). . …… . …… [1] [Total: 19]
Mark scheme
1(a) I Four (or more) experiments completed 1 AND Table on page 4 with correct headings showing • volume of FA 1 • volume of water • time • rate Allow vol. Ignore V or FA 1 alone. Ignore extra columns of data. Ignore data for this mark. II Correct units for all data (in heading or for each entry) 1 • volume: in cm3 or / cm3 or (cm3) or cm3 • time: / s or (s) or s by each time Allow in seconds • rate: / s–1 or (s–1) or s–1 Ignore factor of 1000 III All times recorded to nearest second (minimum of 3 times) 1 AND volumes of FA 1 and water recorded to the nearest 0.05 cm3 IV Three additional experiments with volume FA 1 not less than 6.00 cm3, not more than 20.00 cm3 and no volume 1 less than 2.00 cm3 close to another volume. Reject if further additional experiments carried out. Reject if all 3 additional experiments are between 20 and 10 cm3. V Volumes of water chosen so that FA1 + water = 20.00 cm3 for additional experiments carried out. 1 Reject if FA 1 = 0 Reject if no times recorded. 1(a) VI Correctly calculates rate for all experiments and answer shown to 2–4 sf. 1 Use of significant figures or decimal places does not have to be consistent. Allow for a minimum of 3 experiments attempted. Round times to the nearest second before awarding Q marks. 1 Convert times recorded as decimals to seconds, e.g.1.42 (1:42) = 102 s VII Award if all candidate’s times increase with decrease in volume of FA 1. Reject if fewer than 4 experiments carried out. time for FA 1 = 10 Calculate candidate’s ratio to 2 dp time FA 1 = 20 and record the value under the results table. VIII Award if ratio is between 3.20 and 4.80 1 IX Award if ratio is between 3.50 and 4.50 1 X Award if ratio is between 3.80 and 4.20 1 1(b) I Linear scales that cover more than half the space in both directions including (0,0) 1 AND axes correctly orientated and clearly labelled If scale is non-linear then II is not available. II Points plotted correctly. 1 Points must be within half a small square of the correct position. If the point should be on a line it must be on the line and if it should not be on the line it must not be so. ‘Blobs’ should be less than half a small square across and be correctly centred. Reject if the scale is non-linear. 1(b) III Line of best fit drawn which ignores anomalous results identified by the candidate. 1 The line may be a smooth curve or straight AND use a minimum of 3 points. Ignore points which are circled or labelled as anomalous. Reject if a point has been shown at the origin and the line of best fit does not pass within 5 small squares of (0,0). 1(c) Correct lines drawn within 1 small square 1 Allow if horizontal line drawn and some mark shown at 5. Rate must be read to within correct half a small square, compared with examiner-read value. 1 AND Correctly calculates 1000 / rate AND answer correct to 2–4 sf or a whole number of seconds (unless penalised in 1(a)VI). Reject if the portion of the scale used for the reading is non-linear. 1(d)(i) Correctly calculates 1 Expt 1: 20 cm3 in total volume 60 cm3 ⇒ 1.67 × 10‒2 mol dm‒3 Expt 2: 10 cm3 in total volume 60 cm3 ⇒ 0.83 × 10‒2 mol dm‒3 20 1.67 1 = so directly proportional 10 0.83 Allow directly proportional as total volume unchanged but volume of FA 1 / KI doubled / halved. If neither mark is awarded, then allow a total of one mark in (d)(i) for a correct calculation of moles of KI in Experiments 1 and 2 (1 × 10–3 and 5 × 10–4 mol respectively). 1(d)(ii) Graph: comment must refer to the shape of the line drawn. 1 Curve: as concentration / volume (of iodide ions) increases rate increases more / not directly proportional as line is a curve / not a straight line Straight line: rate is proportional to concentration (of iodide ions) / proportional as line has a positive gradient Reject directly proportional unless the straight line passes within 5 small squares of (0,0). OR Table: compares ratio of concentrations / volumes of FA 1 with ratio of rates Reason: (plotted points give) line of increasing gradient 1 (This mark is not available if a straight line was drawn.) OR t2 greater than 2t1 (or similar correct comparison) e.g. ‘not directly proportional as rate increases more than concentration / volume’ 1(e)(i) S2O32‒(aq) + 2H+(aq) → S(s) + SO2(aq / g) + H2O(l) 1 1(e)(ii) worse – less thio / FA 3 left in the reaction mixture to react with iodine formed / so time decreased for each run (owtte) 1 e.g. ‘some FA 2 reacts with FA 3 before starting the experiment.’ Allow: same – the concentration of thio / FA 3 is very small so slow reaction with Fe3+ / acid / FA 2 so negligible effect / similar decrease in concentration of thio / FA 3 for each run so effects cancel better – quicker to transfer all the other reactants into the 1st beaker / takes more time to pour from measuring cylinder 1(f)(i) Volumes of FA 1, FA 3 and FA 4 are unchanged. 1 FA 2 + water = 20 cm3 1 Reject if these volumes are unchanged from Experiment 2 values. 1(f)(ii) Correctly calculates 1 10 t = 178 × vol FA 2 Reject if volumes FA 2 + water ≠ 20 cm3 FA 5 is MnCl 2•4H2O(s); FA 6 is MnO2(s); FA 7 is KI(aq)