Question 119 marks
Question
Solid FB 1 is hydrated sodium carbonate, Na2CO3•xH2O. You will determine the value of x in a sample of FB 1. The experiment involves three steps: Step 1 React a known mass of sodium carbonate, FB 1, with an excess of acid. Step 2 Dilute the products of Step 1 to a known volume. Step 3 Carry out a titration to find out how much acid remained after the reaction in Step 1. You will use the results of these three steps to find x. FB 1 is hydrated sodium carbonate, Na2CO3•xH2O. FB 2 is 0.800 mol dm–3 hydrochloric acid, HCl. FB 4 is 0.100 mol dm–3 sodium hydroxide, NaOH. bromophenol blue indicator (a) Method Step 1 ● Label a burette FB 2 and fill this burette with FB 2. ● Run 50.00 cm3 of FB 2 into the 250 cm3 beaker. ● Weigh the container with FB 1. Record the mass. ● Slowly, and in small portions, add FB 1 to the acid. ● Stir the mixture until the fizzing has stopped. Leave the stirring rod in the beaker. ● Reweigh the container with any residue. Record the mass. ● Calculate and record the mass of FB 1 added to the acid. Step 2 ● Stir the mixture from Step 1 and ensure that all the solid has dissolved. Transfer this solution to the graduated flask. ● Rinse the beaker and stirring rod twice with distilled water, then add the washings into the graduated flask. ● Make the solution up to 250 cm3 with distilled water. Thoroughly mix the contents of the flask. This solution is FB 3. Step 3 ● Label the other burette FB 4. Fill this burette with FB 4. ● Pipette 25.0 cm3 of FB 3 into a conical flask. ● Add several drops of bromophenol blue indicator. ● Perform a rough titration and record your burette readings in the space below. The rough titre is …… cm3. ● Carry out as many titrations as you think are necessary to obtain consistent results. ● Make certain any recorded results show the precision of your practical work. ● Record, in a suitable form below, all of your burette readings and the volume of FB 4 added in each accurate titration. I II III IV V VI VII VIII [8] (b) From your accurate titration results, calculate a suitable mean value to use in your calculations. Show clearly how you obtained this value. 25.0 cm3 of FB 3 required …… cm3 of FB 4. [1] Calculations (c) (i) Give your answers to (c)(ii), (c)(iii), (c)(iv), and (c)(vi) to an appropriate number of significant figures. [1] (ii) Calculate the number of moles of hydrochloric acid in the FB 2 used in Step 1. moles of HCl in FB 2 used in Step 1 = …… mol [1] (iii) Use your answer to (b) to calculate the number of moles of sodium hydroxide, FB 4, required to react with 25.0 cm3 of FB 3 in Step 3. moles of NaOH required = …… mol Use this answer to deduce the number of moles of hydrochloric acid in 250 cm3 of FB 3. This is the number of moles remaining after the reaction in Step 1. moles of HCl in 250 cm3 of FB 3 = …… mol [1] (iv) Use your answers to (c)(ii) and (c)(iii) to calculate the number of moles of hydrochloric acid that reacted with sodium carbonate in FB 1. moles of HCl that reacted with FB 1 = …… mol [1] (v) Write an equation for the reaction of sodium carbonate with hydrochloric acid in Step 1. Include state symbols. . …… [1] (vi) Use the equation and your answer to (c)(iv) to determine the moles of sodium carbonate present in FB 1. moles of Na2CO3 = …… mol [1] (vii) Use your answer to (c)(vi) and your mass of FB 1 to calculate the formula mass of hydrated sodium carbonate. Hence find the value for x. (If you were unable to calculate the number of moles of Na2CO3 in (c)(vi) assume that it is 5.55 × 10–3 mol. This is not the correct value.) x = …… [2] (d) State the maximum error in a single balance reading. maximum error in a balance reading = …… g Calculate the maximum percentage error in the mass of FB 1 you used. Show your working. maximum percentage error = …… % [1] (e) A student decided to use a larger mass of FB 1 when carrying out the same method. What effect would this have on the titre volume in Step 3? Explain your answer. . …… . …… . …… [1] [Total: 19]
Mark scheme
1(a) I Unambiguous headings 1 2 balance readings and mass of FB 1 correctly calculated and correctly displayed units II The following data must be shown 1 • burette readings and titre for rough titration • 2 × 2 ‘box’ showing both accurate burette readings III Headings and units correct for accurate titration table and headings match readings. 1 • initial / start and (burette) reading / volume + unit • final / end and (burette) reading / volume + unit titre or volume / FB 4 and used / added + unit All accurate burette readings are recorded to the nearest 0.05 cm3 1 The final accurate titre recorded is within 0.10 cm3 of any other accurate titre. 1 1(a) VI, VII and VII: 3 Award V for a range of 15% of the supervisor value for Mr Award VI for a range of 10% of the supervisor value for Mr Award VII for a range of 5% of the supervisor value for Mr If the supervisor titre is ≤ 10.00 cm3 then halve tolerances (0.10, 0.15, 0.25). If supervisor titre & candidate titres ≤ 5.00 cm3 contact TL 1(b) Candidate must average two (or more) accurate titres with total spread of not more than 0.20 cm3. 1 Working must be shown or ticks must be put next to the two (or more) accurate readings selected. The mean should be correctly calculated to the nearest 0.01. 1(c)(i) All answers in (c)(iii), (c)(iv) and (c)(vi) given to 3 or 4 sf 1 1(c)(ii) Correctly calculates moles of HCl added: 1 0.800 × (50 / 1000) = 0.0400 1(c)(iii) Correctly calculates mol of NaOH used: 1 (b) × (0.1 / 1000) and moles of HCl remaining = moles of NaOH × 10 1(c)(iv) Correct expression 1 (d)(iv) = (c)(ii) – (c)(iii) 1(c)(v) Na2CO3(s) + 2HCl(aq) → 2NaCl(aq) + H2O(l) + CO2(g) 1 OR Na2CO3•xH2O(s) + 2HCl(aq) → 2NaCl(aq) + (x + 1)H2O(l) + CO2(g) 1(c)(vi) Correctly uses 1 (c)(iv) / 2 1(c)(vii) Correctly uses 1 Mr = m / n = mass of FB 1 from (a) / (c)(vi) Correct expression 1 x = (Mr – 106) / 18 and expressed to the nearest integer or to 2–4 sf 1(d) 0.05 or 0.1 if 1 dp balance used / 0.005 or 0.01 if 2 dp balance used / 0.0005 or 0.001 if 3 dp balance used 1 and Correct expression {(2 × error above) / mass from (a)} × 100 1(e) Titre would be smaller 1 and More acid has reacted in Step 1 / less acid remaining after reaction in Step 1