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Biology 0610/53 October/November 2023: question paper and mark scheme

Cambridge IGCSE Biology (0610), Paper 5 Practical Test, October/November 2023. Read both free below, or download them. Done the paper? Get it marked by AI against this mark scheme.

0610_w23_qp_530610_w23_ms_530610/53/O/N/23

Paper
Paper 5 Practical Test
Total marks
40
Time
1 hour 15 minutes
Questions
2
Code on the paper
0610/53/O/N/23
0610_w23_ms_53.pdf

0610/53 mark scheme, question by question

Each question as it's printed, and the mark scheme's points for it, as text. Diagrams, tables and graphs are in the PDFs above.

Question 123 marks

Question

Flour and yeast are used to make bread dough, as shown in Fig. 1.1. Respiration in yeast produces carbon dioxide gas bubbles that make the bread dough increase in volume. bread dough Fig. 1.1 You are going to use bread dough to investigate the effect of temperature on the rate of respiration in yeast. Read all the instructions but DO NOT DO THEM until you have drawn a table for your results in the space provided in 1(a)(i). You should use the safety equipment provided while you are doing the practical work. Step 1 Label three large test-tubes C, R and H and place them in the test-tube rack. Step 2 Use the measuring cylinder to add 20 cm3 of water from the beaker labelled W to each of the test-tubes labelled C, R and H. Step 3 Place test-tube C into the empty beaker labelled cold water-bath. Step 4 Leave test-tube R in the test-tube rack. Step 5 Place test-tube H into the empty beaker labelled hot water-bath. Step 6 Raise your hand when you are ready for hot water to be added to your hot water-bath and ice water to be added to your cold water-bath. Step 7 Start the stop-clock and leave the test-tubes for five minutes. Continue with steps 8, 9 and 10 during this time. Step 8 Label three cups C, R and H. Step 9 Use a ruler and a permanent marker pen to draw a line 2 cm from the base of all three cups, as shown in Fig. 1.2. 2 cm Fig. 1.2 Step 10 Add the flour and yeast mixture from beaker F up to the lines you have drawn on cups C, R and H. Step 11 Measure the temperature of the water in test-tubes C, R and H. Record these temperatures in your table in 1(a)(i). Step 12 Pour the contents of test-tube C into cup C. Use the glass rod to stir the mixture to form a dough. Step 13 Pour the contents of test-tube R into cup R. Use the glass rod to stir the mixture to form a dough. Step 14 Pour the contents of test-tube H into cup H. Use the glass rod to stir the mixture to form a dough. Step 15 Draw a new line on each cup to mark the position of the top of the dough. Step 16 Start the stop-clock and leave the dough for 20 minutes. Continue with the other questions while you are waiting. Step 17 After 20 minutes, draw a third line on each cup to mark the position of the top of the dough. Step 18 Measure the distance between the lines drawn in Step 15 and Step 17 and record your measurements in your table in 1(a)(i). (a) (i) Prepare a table and record your results. [5] (ii) State a conclusion for your results. …… [1] (iii) State the independent variable in the investigation. …… [1] (iv) Identify one possible source of error with the method used to measure the dependent variable. …… [1] (v) State a piece of laboratory equipment that could be used to improve the method in step 10. …… [1] (vi) Explain why test-tubes C and H were kept in the water-baths for five minutes. …… [1] (vii) This investigation was done by another student using three cups which had different diameters, as shown in Fig. 1.3. Fig. 1.3 Explain why using different-sized cups caused an error in the results. …… [1] (b) Yeast uses the reducing sugar glucose for respiration. This reaction produces carbon dioxide. (i) A sample of flour was tested for reducing sugars using the Benedict’s test. State the result of a positive test. …… [1] (ii) Identify a hazard when doing the Benedict’s test. …… [1] (iii) State the name of a reagent that can be used to test for carbon dioxide. …… [1] (iv) Salt (sodium chloride) is usually added to the flour and yeast mixture when making bread but it can reduce the rate of respiration in yeast. The effect of salt concentration on the volume of carbon dioxide gas produced by yeast is shown in Table 1.1. Table 1.1 volume of carbon dioxide gas produced salt concentration / g per dm3 / cm3 per minute 0 5.3 5 1.9 10 0.3 20 0.0 Calculate the percentage change in the volume of carbon dioxide gas produced from a salt concentration of 0 g per dm3 to 10 g per dm3. Give your answer to one decimal place. Space for working. …… % [3] (c) Humans can use the energy released during respiration to exercise. Plan an investigation to determine the effect of exercising at different intensities on breathing rate. …… [6] [Total: 23]

Mark scheme

1(a)(i) table drawn with minimum two columns and a header line ; 5 appropriate column headings with units ; e.g. temperature / °C and change in (dough) height / mm three temperatures recorded ; three heights recorded ; correct trend: e.g. H / highest temperature, has the greatest change in height ; 1(a)(ii) as temperature increases (the rate of) respiration increases / ora ; 1 1(a)(iii) temperature ; 1 1(a)(iv) dough was, rounded / not flat / not smooth / AW ; 1 1(a)(v) (electronic) balance / measuring cylinder / AVP ; 1 1(a)(vi) to equilibrate the water / so that the water is the same temperature 1 as the water-baths ; 1(a)(vii) any one from: 1 1 (initial height of dry ingredients is 1 cm so) the initial amount / mass / volume, of dough is different in each cup ; 2 proportion of water to flour and yeast differs between cups ; 3 there are two independent variables ; 4 idea that the same increase in dough volume (during the investigation) will result in a different increase in height in the (3) cups / AW ; 1(b)(i) (brick-)red / AVP ; 1 1(b)(ii) any one from: 1 heating (the reagent, risk described) ; Benedict’s reagent is, toxic / harmful / irritant / corrosive ; 1(b)(iii) limewater / AVP ; 1 1(b)(iv) (–)94.3(%) ;;; 3 MP1 selection of correct values from table i.e. 5.3 and 0.3 only MP2 correct calculation for percentage decrease (5.3–0.3) ÷ 5.3 *100 or 100–((0.3 / 5.3)×100) =-94.339622641509 MP3 correct rounding to one decimal place ecf from previous step 1(c) independent variable: 6 1 at least two different exercise intensities ; dependent variable: 2 breathing rate (immediately) after /during exercising ; detail of the method: 3 method of changing intensity of one type of exercise ; 4 measurement of initial / resting breathing rate ; 5 describing type of exercise / equipment used ; 6 & 7 from variables kept constant – max two from: ;; • same age participants • same sex participants • same fitness of participants • same duration of exercise / pace / speed of exercise • same person • same named environmental conditions e.g. temperature / humidity / gradient 8 two or more replicates / repeat investigation two or more times ; 9 safety precaution e.g. checking participants are healthy / checking for trip hazards / suitable footwear ;

Question 217 marks

Question

(a) Fig. 2.1 is a photomicrograph of two guard cells in the lower epidermis of a leaf. P Q guard cell epidermal cell magnification ×1650 Fig. 2.1 (i) Make a large drawing of the two guard cells and the two complete epidermal cells shown in Fig. 2.1. [4] (ii) Line PQ represents the length of the guard cells in Fig. 2.1. Measure the length of line PQ in Fig. 2.1. length of line PQ …… mm Calculate the actual length of the guard cells using the formula and your measurement. length of line PQ magnification = actual length of the guard cells Give your answer to two significant figures. Space for working. …… mm [3] (b) Transpiration is the loss of water vapour from the leaves of a plant. A student used a potometer to investigate the effect of wind speed on transpiration. Fig. 2.2 shows part of the apparatus used. The air bubble in the tubing will move towards the leafy shoot because water moves into the stem when water is lost from the leaves. fan leafy shoot petroleum jelly bung water ruler tubing air bubble Fig. 2.2 The student used this method: • Cut a leafy shoot from a plant. • Place the leafy shoot into the potometer. • Measure the distance the air bubble moves in five minutes at different wind speeds. • Maintain the temperature in the room at 25 °C and the relative humidity at 60%. • Repeat the investigation using five different leafy shoots. Each shoot must have same number of leaves. (i) State the dependent variable in the investigation. …… [1] (ii) State two factors that were kept constant in the investigation described in 2(b). 1 …… 2 …… [2] (iii) Suggest the purpose of the petroleum jelly shown in Fig. 2.2. …… [1] The results are shown in Table 2.1. Table 2.1 distance the air bubble wind speed / km per hour moved in five minutes / mm 0 4.5 10 13.0 20 23.0 30 26.5 50 15.5 (iv) Plot a line graph on the grid of the data in Table 2.1. [4] (v) Using your graph, estimate the distance the air bubble moved in five minutes when the wind speed was 15 km per hour. Show on your graph how you obtained your estimate. …… mm [2] [Total: 17]

Mark scheme

2(a)(i) outline us a single clear line with no shading ; 4 size of the guard cell width is at least 31 mm ; detail 1: at least four nuclei, 2 roughly circular (epidermal) and 2 longer than wide (guard cells) ; detail 2: only two epidermal cells touching each other and touching two guard cells ; 2(a)(ii) line PQ length: 31 ±1(mm) ; 3 MP1 correct measurement of line PQ 0 019 (mm) ;; MP2 correct calculation MP3 correct rounding of answer to two significant figures line PQ of 30 mm = 0.018 line PQ of 32 mm = 0.019 ecf from previous step 2(b)(i) distance (air bubble) moved in five minutes / in a set time ; 1 2(b)(ii) any two from: 2 temperature ; same potometer ; number of leaves ; humidity ; time (measured) ; 2(b)(iii) airtight seal / prevent water loss / AW; 1 2(b)(iv) 1 axes labelled with units to match table headers ; 4 wind speed km / hour and distance (the air bubble) moved in 5 minutes / mm 2 suitable scale and occupies at least half the grid in both directions ; 3 all five plots plotted accurately ± half a small square ; 4 suitable line drawn ; 2(b)(v) value from candidate’s graph (mm) ; 2 indications on graph as to where reading taken ;

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Where can I find the 0610/53 October/November 2023 mark scheme?

On this page, free: the mark scheme for IGCSE Biology 0610/53, October/November 2023 (0610_w23_ms_53), and the question paper (0610_w23_qp_53), to read or download, with each question's marking points written out underneath.

How many marks is 0610/53 out of?

Biology 0610/53 for October/November 2023 is out of 40 marks, with 1 hour 15 minutes to answer it, across 2 questions.

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